Maths-

General

Easy

Question

# Given the size of red blood cells as 0.000007 m and plant cell of size 0.00001275 m. Calculate the ratio between them

Hint:

### 1. In Mathematics, lets say, "a" represents a number and "n" is the number of times that number is to be multiplied with itself, in order to get a desired result. Then, such result can be written as an, where a is called the base and n is its power/ exponent.

an = a × a × ... × a n times.

2. Ratio between 2 items = 1st item / 2nd item

## The correct answer is: The ratio between red blood cells and plant cells is 28: 51.

### Step-by-step solution:-

Ratio between red blood cells and plant cell = size of each red blood cell / size of each plant cell

Ratio between red blood cells and plant cell = 0.000007 / 0.00001275

Ratio between red blood cells and plant cell = 28/51

Final Answer:-

∴ The ratio between red blood cells and plant cells is 28: 51.

### Related Questions to study

Maths-

### Evaluate 1 / (216)^{−2/3} + 1 / (256)^{−3/4} + 1 / (32)^{−1/5}

### Evaluate 1 / (216)^{−2/3} + 1 / (256)^{−3/4} + 1 / (32)^{−1/5}

Maths-General

Maths-

### If x^{2}=16 and y^{2}=4, find the greatest possible value of (x-y)^{2}

### If x^{2}=16 and y^{2}=4, find the greatest possible value of (x-y)^{2}

Maths-General

Maths-

### Find the area of a verandah 2.25 m wide constructed outside a room 5.5 m long and 4 m wide.

### Find the area of a verandah 2.25 m wide constructed outside a room 5.5 m long and 4 m wide.

Maths-General

Maths-

### = x-4 . Find the value of ( x-4 ) ^{3}

### = x-4 . Find the value of ( x-4 ) ^{3}

Maths-General

Maths-

### The length and breadth of a rectangular hall in a model are 0.4 m and 30 cm respectively. What is the distance between the opposite corners of the wall in the model?

### The length and breadth of a rectangular hall in a model are 0.4 m and 30 cm respectively. What is the distance between the opposite corners of the wall in the model?

Maths-General

Maths-

### The perimeter of a rectangle is 26 cm. The length and the breadth of the rectangle are integers. Find the number of possible pairs of length and breadth. Also find the maximum possible area of the rectangle.

### The perimeter of a rectangle is 26 cm. The length and the breadth of the rectangle are integers. Find the number of possible pairs of length and breadth. Also find the maximum possible area of the rectangle.

Maths-General

Maths-

### Find the value of ( 8^{-25} - 8^{-26} )

### Find the value of ( 8^{-25} - 8^{-26} )

Maths-General

Maths-

### Given 8712 = 2^{x} × 3^{y} × 11^{z} .Find the numerical values of x,y and z. Also find the value of 3^{x} × 2^{y} × 7^{-z} ?

### Given 8712 = 2^{x} × 3^{y} × 11^{z} .Find the numerical values of x,y and z. Also find the value of 3^{x} × 2^{y} × 7^{-z} ?

Maths-General

Maths-

### The perimeter of a rectangle is 26 cm. The length and the breadth of the rectangle are integers. Find the number of possible pairs of length and breadth. Also find the maximum possible area of the rectangle.

Maths-General

Maths-

### Evaluate as a fraction (64 / 27)^{2/3} − (1/9)^{−2} + 9^{0}

### Evaluate as a fraction (64 / 27)^{2/3} − (1/9)^{−2} + 9^{0}

Maths-General

Maths-

### Simplify:

4^{1/3} (2^{1/3} × 3^{1/2}) ÷ 9^{1/4}

### Simplify:

4^{1/3} (2^{1/3} × 3^{1/2}) ÷ 9^{1/4}

Maths-General

Maths-

### Simplify:

(64 / 125)^{−2/3} ÷ (625 / 256)^{1/4} × (−6)^{0}

### Simplify:

(64 / 125)^{−2/3} ÷ (625 / 256)^{1/4} × (−6)^{0}

Maths-General

Maths-

### Solve for x-

(3/5)^{(x+1)/3} = 625 / 81

### Solve for x-

(3/5)^{(x+1)/3} = 625 / 81

Maths-General

Maths-

### Solve for x-

(3/7)^{(1−2x)/2} = 12 19/27

### Solve for x-

(3/7)^{(1−2x)/2} = 12 19/27

Maths-General

Maths-

### The floor of a study room is in the shape of a rectangle, it is 12 ft long and 10 ft wide. How many tiles with 2 ft × 2 ft are required to cover the floor of the room?

### The floor of a study room is in the shape of a rectangle, it is 12 ft long and 10 ft wide. How many tiles with 2 ft × 2 ft are required to cover the floor of the room?

Maths-General