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Here are the graphs of x→ t of moving body. which of them is not suitable?

The correct answer is:

A cubic polynomial f(x) = ax³ + bx² + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

If a function has a tangent at a point $x = a$ , then, it means, it is the critical point of that function and the derivative of the function is zero at that point.
Perform the calculations carefully, to avoid silly mistakes.
One should know how to read a graph to solve such questions.

A cubic polynomial f(x) = ax³ + bx² + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

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Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b $sin invisible function application fraction numerator pi over denominator 2 end fraction x$ , 1 £ x £ 2 then which of the following is correct?

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The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval $open square brackets fraction numerator pi over denominator 6 end fraction comma fraction numerator 5 pi over denominator 6 end fraction close square brackets$ is -

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physics

The relation between time and displacement of a moving particle is given by $t equals 2 a x squared$ where $alpha$ is a constant. The shape of the graph is $x not stretchy rightwards arrow y$ is....

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If P (q) and Q $open parentheses fraction numerator pi over denominator 2 end fraction plus theta close parentheses$ are two points on the ellipse $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1$ , then locus of the mid – point of PQ is

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If CP and CD are semi – conjugate diameters of an ellipse $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1 comma$ then CP² + CD² =

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The normals to the curve x = a ( $theta$ + sin $theta$ ), y = a (1 – cos $theta$ ) at the points $theta$ = (2n + 1) $pi$ , n $element of$ I are all -

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General

Maths-

The normal to the curve x = 3 cos $theta$ – cos3 $theta$ , y = 3 sin $theta$ – sin3 $theta$ at the point $theta$ = $pi$ /4 passes through the point -

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Maths-

The normal of the curve given by the equation x = a (sin $theta$ + cos $theta$ ), y = a (sin $theta$ – cos $theta$ ) at the point Q is -

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General

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If the tangent at ‘t’ on the curve y = 8t3 –1, x = 4t2 + 3 meets the curve again at t¢ and is normal to the curve at that point, then value of t must be -

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The tangent at (t, t2 – t3) on the curve y = x2 – x3 meets the curve again at Q, then abscissa of Q must be -

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General

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If $fraction numerator x over denominator a end fraction plus fraction numerator y over denominator b end fraction$ = 1 is a tangent to the curve x = 4t,y = $fraction numerator 4 over denominator t end fraction$ , t $element of$ R then -

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The line $fraction numerator x over denominator a end fraction$ + $fraction numerator y over denominator b end fraction$ = 1 touches the curve y = be-x/a at the point :

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physics

An object moves in a straight line. It starts from the rest and its acceleration is . 2 ms².After reaching a certain point it comes back to the original point. In this movement its acceleration is -3 ms², till it comes to rest. The total time taken for the movement is 5 second. Calculate the maximum velocity.

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For the ellipse $fraction numerator x to the power of 2 end exponent over denominator 2 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 1 end fraction equals 1 comma$ the foci are

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Here are the graphs of x→ t of moving body. which of them is not suitable?

The correct answer is:

Related Questions to study

A cubic polynomial f(x) = ax3 + bx2 + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

A cubic polynomial f(x) = ax3 + bx2 + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b , 1 £ x £ 2 then which of the following is correct?

Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b , 1 £ x £ 2 then which of the following is correct?

The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval is -

The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval is -

The relation between time and displacement of a moving particle is given by where is a constant. The shape of the graph is is....

The relation between time and displacement of a moving particle is given by where is a constant. The shape of the graph is is....

If P (q) and Q are two points on the ellipse , then locus of the mid – point of PQ is

If P (q) and Q are two points on the ellipse , then locus of the mid – point of PQ is

If CP and CD are semi – conjugate diameters of an ellipse then CP2 + CD2 =

If CP and CD are semi – conjugate diameters of an ellipse then CP2 + CD2 =

The normals to the curve x = a ( + sin ), y = a (1 – cos ) at the points = (2n + 1) , n I are all -

The normals to the curve x = a ( + sin ), y = a (1 – cos ) at the points = (2n + 1) , n I are all -

The normal to the curve x = 3 cos – cos3, y = 3 sin – sin3 at the point = /4 passes through the point -

The normal to the curve x = 3 cos – cos3, y = 3 sin – sin3 at the point = /4 passes through the point -

The normal of the curve given by the equation x = a (sin + cos), y = a (sin – cos) at the point Q is -

The normal of the curve given by the equation x = a (sin + cos), y = a (sin – cos) at the point Q is -

If the tangent at ‘t’ on the curve y = 8t3 –1, x = 4t2 + 3 meets the curve again at t¢ and is normal to the curve at that point, then value of t must be -

If the tangent at ‘t’ on the curve y = 8t3 –1, x = 4t2 + 3 meets the curve again at t¢ and is normal to the curve at that point, then value of t must be -

The tangent at (t, t2 – t3) on the curve y = x2 – x3 meets the curve again at Q, then abscissa of Q must be -

The tangent at (t, t2 – t3) on the curve y = x2 – x3 meets the curve again at Q, then abscissa of Q must be -

If = 1 is a tangent to the curve x = 4t,y =, t R then -

If = 1 is a tangent to the curve x = 4t,y =, t R then -

The line + = 1 touches the curve y = be-x/a at the point :

The line + = 1 touches the curve y = be-x/a at the point :

For the ellipse the foci are

For the ellipse the foci are

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A cubic polynomial f(x) = ax³ + bx² + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

A cubic polynomial f(x) = ax³ + bx² + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b $sin invisible function application fraction numerator pi over denominator 2 end fraction x$ , 1 £ x £ 2 then which of the following is correct?

Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b $sin invisible function application fraction numerator pi over denominator 2 end fraction x$ , 1 £ x £ 2 then which of the following is correct?

The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval $open square brackets fraction numerator pi over denominator 6 end fraction comma fraction numerator 5 pi over denominator 6 end fraction close square brackets$ is -

The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval $open square brackets fraction numerator pi over denominator 6 end fraction comma fraction numerator 5 pi over denominator 6 end fraction close square brackets$ is -

The relation between time and displacement of a moving particle is given by $t equals 2 a x squared$ where $alpha$ is a constant. The shape of the graph is $x not stretchy rightwards arrow y$ is....

The relation between time and displacement of a moving particle is given by $t equals 2 a x squared$ where $alpha$ is a constant. The shape of the graph is $x not stretchy rightwards arrow y$ is....

The normals to the curve x = a ( $theta$ + sin $theta$ ), y = a (1 – cos $theta$ ) at the points $theta$ = (2n + 1) $pi$ , n $element of$ I are all -

The normals to the curve x = a ( $theta$ + sin $theta$ ), y = a (1 – cos $theta$ ) at the points $theta$ = (2n + 1) $pi$ , n $element of$ I are all -

The normal to the curve x = 3 cos $theta$ – cos3 $theta$ , y = 3 sin $theta$ – sin3 $theta$ at the point $theta$ = $pi$ /4 passes through the point -

The normal to the curve x = 3 cos $theta$ – cos3 $theta$ , y = 3 sin $theta$ – sin3 $theta$ at the point $theta$ = $pi$ /4 passes through the point -

The normal of the curve given by the equation x = a (sin $theta$ + cos $theta$ ), y = a (sin $theta$ – cos $theta$ ) at the point Q is -

The normal of the curve given by the equation x = a (sin $theta$ + cos $theta$ ), y = a (sin $theta$ – cos $theta$ ) at the point Q is -

If $fraction numerator x over denominator a end fraction plus fraction numerator y over denominator b end fraction$ = 1 is a tangent to the curve x = 4t,y = $fraction numerator 4 over denominator t end fraction$ , t $element of$ R then -

If $fraction numerator x over denominator a end fraction plus fraction numerator y over denominator b end fraction$ = 1 is a tangent to the curve x = 4t,y = $fraction numerator 4 over denominator t end fraction$ , t $element of$ R then -

The line $fraction numerator x over denominator a end fraction$ + $fraction numerator y over denominator b end fraction$ = 1 touches the curve y = be-x/a at the point :

The line $fraction numerator x over denominator a end fraction$ + $fraction numerator y over denominator b end fraction$ = 1 touches the curve y = be-x/a at the point :

For the ellipse $fraction numerator x to the power of 2 end exponent over denominator 2 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 1 end fraction equals 1 comma$ the foci are

For the ellipse $fraction numerator x to the power of 2 end exponent over denominator 2 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 1 end fraction equals 1 comma$ the foci are