Question

# If x & y are real numbers and then ' y ' cannot take the value(s) :

- -1
- 0
- 1
- 2

## The correct answer is: -1

### For that find y and where its value lies.

Complete step by step solution:

Here, we have to find the ‘y’ cannot take which value.

Firstly, x and y are real numbers,

= x

so,

y = x^{2}

x^{2} never be negative for any real value,

then we can say that y is always non-negative.

y ≥ 0,

from options, -1 is negative, then y cannot take this value.

Therefore, the correct answer is -1.

Here we have, x and y are real number and = x, we have to find that what ‘y’ cannot take the value. For that find y and where its value lies.

In this question, we have to which value y cannot give. Here ‘y’ is always non-negative, so it never given the negative value.

### Related Questions to study

Statement 1:In the process of drying dishes with a towel, the wetting agent is the dish and the drying agent is the towel

Statement 2:The wetting agent gets wet during the process

Statement 1:In the process of drying dishes with a towel, the wetting agent is the dish and the drying agent is the towel

Statement 2:The wetting agent gets wet during the process

Which of the following are correct ?

In this question, we have to find which option is correct. Check every option which one is satisfy. Use the properties of the logarithmic which going to help to get the answer.

Which of the following are correct ?

In this question, we have to find which option is correct. Check every option which one is satisfy. Use the properties of the logarithmic which going to help to get the answer.

### Statement 1:The reaction between and occurs in an acidic medium

Statement 2: is reduced to in acidic medium

### Statement 1:The reaction between and occurs in an acidic medium

Statement 2: is reduced to in acidic medium

Number of cyphers after decimal before a significant figure comes in is

In this question, we have to find the number of cyphers. We need to remember that the cypher number can be found from the logarithmic calculation but to find the actual value or to visualize it we need to remove the logarithm. Here, log_{10}5 = 0.6990 and log_{10}3 = 0.4770.

Number of cyphers after decimal before a significant figure comes in is

In this question, we have to find the number of cyphers. We need to remember that the cypher number can be found from the logarithmic calculation but to find the actual value or to visualize it we need to remove the logarithm. Here, log_{10}5 = 0.6990 and log_{10}3 = 0.4770.

The value of p for which both the roots of the quadratic equation, are less than 2 lies in :

In this question, we have to find where the p lies. Here, we use discriminant, which is . if D > 0 and D = 0 then real solution but if D < 0 then imaginary solution. Here we also us Factorization of quadratic equations.

The value of p for which both the roots of the quadratic equation, are less than 2 lies in :

In this question, we have to find where the p lies. Here, we use discriminant, which is . if D > 0 and D = 0 then real solution but if D < 0 then imaginary solution. Here we also us Factorization of quadratic equations.

### If where determine b –

Just like we can change the base b for the exponential function, we can also change the base b for the logarithmic function. The logarithm with base b is defined so that

### If where determine b –

Just like we can change the base b for the exponential function, we can also change the base b for the logarithmic function. The logarithm with base b is defined so that

### Statement 1:The two Fe atoms in have different oxidation numbers

Statement 2: ions decolourise solution

### Statement 1:The two Fe atoms in have different oxidation numbers

Statement 2: ions decolourise solution

### , where and is

In this question, we have to find the . Here Solve first B. In B, rationalize it means multiply it denominator by sign change in both numerator and denominator

### , where and is

In this question, we have to find the . Here Solve first B. In B, rationalize it means multiply it denominator by sign change in both numerator and denominator

Statement 1:The equivalence point refers the condition where equivalents of one species react with same number of equivalent of other species.

Statement 2:The end point of titration is exactly equal to equivalence point

Statement 1:The equivalence point refers the condition where equivalents of one species react with same number of equivalent of other species.

Statement 2:The end point of titration is exactly equal to equivalence point

If and are the roots of the equation then the value of equals

If and are the roots of the equation then the value of equals

Statement 1:Iodimetric titration are redox titrations.

Statement 2:The iodine solution acts as an oxidant to reduce the reductant

Statement 1:Iodimetric titration are redox titrations.

Statement 2:The iodine solution acts as an oxidant to reduce the reductant

Statement 1:Diisopropyl ketone on reaction with isopropyl magnesium bromide followed by hydrolysis gives alcohol

Statement 2:Grignard reagent acts as a reducing agent

Statement 1:Diisopropyl ketone on reaction with isopropyl magnesium bromide followed by hydrolysis gives alcohol

Statement 2:Grignard reagent acts as a reducing agent

The first noble gas compound obtained was:

The first noble gas compound obtained was:

Given that and then value of equals –

These four basic properties all follow directly from the fact that logs are exponents.

log_{b}(*xy*) = log_{b}*x* + log_{b}*y*.

log_{b}(*x/y*) = log_{b}*x* - log_{b}*y*.

log_{b}(*x ^{n}*) =

*n*log

_{b}

*x*.

log

_{b}

*x*= log

_{a}

*x*/ log

_{a}

*b*.

Given that and then value of equals –

These four basic properties all follow directly from the fact that logs are exponents.

log_{b}(*xy*) = log_{b}*x* + log_{b}*y*.

log_{b}(*x/y*) = log_{b}*x* - log_{b}*y*.

log_{b}(*x ^{n}*) =

*n*log

_{b}

*x*.

log

_{b}

*x*= log

_{a}

*x*/ log

_{a}

*b*.

Statement 1:Change in colour of acidic solution of potassium dichromate by breath is used to test drunk drivers.

Statement 2:Change in colour is due to the complexation of alcohol with potassium dichromate.

Statement 1:Change in colour of acidic solution of potassium dichromate by breath is used to test drunk drivers.

Statement 2:Change in colour is due to the complexation of alcohol with potassium dichromate.