Maths-

#### satisfies the relation then value of A and B respectively are:

Maths-General

- –13, 12
- –13, 14
- –13, –12
- 12, –13

#### Answer:The correct answer is: –13, –12

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### Related Questions to study

physics-

#### According to Newton’s law of cooling, the rate of cooling is proportional to , where is the temperature differences between the body and the surroundings and is equal to

According to Newton’s law of cooling the rate of loss of heat of a body is directly proportional to the difference in temperature of the body,

(i)

Given, (ii)

Comparing Eqs. (i) and (ii), we get

=1

(i)

Given, (ii)

Comparing Eqs. (i) and (ii), we get

=1

#### According to Newton’s law of cooling, the rate of cooling is proportional to , where is the temperature differences between the body and the surroundings and is equal to

physics-General

According to Newton’s law of cooling the rate of loss of heat of a body is directly proportional to the difference in temperature of the body,

(i)

Given, (ii)

Comparing Eqs. (i) and (ii), we get

=1

(i)

Given, (ii)

Comparing Eqs. (i) and (ii), we get

=1

maths-

#### Statement-1- The number is not divisible by 11.Because

Statement-2- If p is a prime, the exponent of p in n! is + + +……Where [x] denotes the greatest integer x.

#### Statement-1- The number is not divisible by 11.Because

Statement-2- If p is a prime, the exponent of p in n! is + + +……Where [x] denotes the greatest integer x.

maths-General

maths-

#### Number of values of 'p' for which the equation possess more than two roots ,is:

For (p2– 3p+2)x2–(p2–5p+4)x+p–p2=0tobe anidentity

p2–3p+2 =0 p = 1, 2...(i)

p2 – 5p + 4 = 0 p = 1, 4...(ii)

p – p2 = 0 p = 0, 1...(iii)

For (i), (ii) & (iii) to hold simultaneously p = 1.

p2–3p+2 =0 p = 1, 2...(i)

p2 – 5p + 4 = 0 p = 1, 4...(ii)

p – p2 = 0 p = 0, 1...(iii)

For (i), (ii) & (iii) to hold simultaneously p = 1.

#### Number of values of 'p' for which the equation possess more than two roots ,is:

maths-General

For (p2– 3p+2)x2–(p2–5p+4)x+p–p2=0tobe anidentity

p2–3p+2 =0 p = 1, 2...(i)

p2 – 5p + 4 = 0 p = 1, 4...(ii)

p – p2 = 0 p = 0, 1...(iii)

For (i), (ii) & (iii) to hold simultaneously p = 1.

p2–3p+2 =0 p = 1, 2...(i)

p2 – 5p + 4 = 0 p = 1, 4...(ii)

p – p2 = 0 p = 0, 1...(iii)

For (i), (ii) & (iii) to hold simultaneously p = 1.

maths-

#### Let p, q{1,2,3,4}.Then number of equation of the form px^{2}+qx+1=0,having real roots ,is

q2–4p0

q=2 p=1

q=3 p=1,2

q=4 p=1,2,3,4

Hence 7 values of (p, q)7equationsarepossible.

q=2 p=1

q=3 p=1,2

q=4 p=1,2,3,4

Hence 7 values of (p, q)7equationsarepossible.

#### Let p, q{1,2,3,4}.Then number of equation of the form px^{2}+qx+1=0,having real roots ,is

maths-General

q2–4p0

q=2 p=1

q=3 p=1,2

q=4 p=1,2,3,4

Hence 7 values of (p, q)7equationsarepossible.

q=2 p=1

q=3 p=1,2

q=4 p=1,2,3,4

Hence 7 values of (p, q)7equationsarepossible.

maths-

The differential equation of all circles which pass through the origin and whose centres lie on y-axis is

The differential equation of all circles which pass through the origin and whose centres lie on y-axis is

maths-General

physics-

#### A simple magnifying lens is used in such a way that an image is formed at 25 *cm* away from the eye. In order to have 10 *times* magnification, the focal length of the lens should be

or

#### A simple magnifying lens is used in such a way that an image is formed at 25 *cm* away from the eye. In order to have 10 *times* magnification, the focal length of the lens should be

physics-General

or

maths-

#### If then the solution of the equation is :

#### If then the solution of the equation is :

maths-General

physics-

#### Radius of a conductor increases uniformly from left end to right end as shown in fig Material of the conductor is isotropic and its curved surface is thermally insulated from surrounding. Its ends are maintained at temperatures and : If, in steady state, heat flow rate is equal to , then which of the following graphs is correct

Since the curved surface of the conductor is thermally insulated, therefore, in steady state, the rate of flow of heat at every section will be the same. Hence the curve between and will be straight line parallel to -axis

#### Radius of a conductor increases uniformly from left end to right end as shown in fig Material of the conductor is isotropic and its curved surface is thermally insulated from surrounding. Its ends are maintained at temperatures and : If, in steady state, heat flow rate is equal to , then which of the following graphs is correct

physics-General

Since the curved surface of the conductor is thermally insulated, therefore, in steady state, the rate of flow of heat at every section will be the same. Hence the curve between and will be straight line parallel to -axis

physics-

#### Water and turpentine oil (specific heat less than that of water) are both heated to same temperature. Equal amounts of these placed in identical calorimeters are then left in air

As we know, Rate of cooling

It is clear that, at a particular time after start cooling, temperature of oil will be less than that of water

So graph represents the cooling curve of oil and represents the cooling curve of water

It is clear that, at a particular time after start cooling, temperature of oil will be less than that of water

So graph represents the cooling curve of oil and represents the cooling curve of water

#### Water and turpentine oil (specific heat less than that of water) are both heated to same temperature. Equal amounts of these placed in identical calorimeters are then left in air

physics-General

As we know, Rate of cooling

It is clear that, at a particular time after start cooling, temperature of oil will be less than that of water

So graph represents the cooling curve of oil and represents the cooling curve of water

It is clear that, at a particular time after start cooling, temperature of oil will be less than that of water

So graph represents the cooling curve of oil and represents the cooling curve of water

physics-

#### Variation of radiant energy emitted by sun, filament of tungsten lamp and welding are as a function of its wavelength is shown in figure. Which of the following option is the correct match?

From the graph

Temperature of sun will be maximum

#### Variation of radiant energy emitted by sun, filament of tungsten lamp and welding are as a function of its wavelength is shown in figure. Which of the following option is the correct match?

physics-General

From the graph

Temperature of sun will be maximum

maths-

#### The degree of the differential equation satisfying is

#### The degree of the differential equation satisfying is

maths-General

physics-

#### Maximum kinetic energy (E_{k} ) of a photoelectron varies with the frequency ( v ) of the incident radiation as

#### Maximum kinetic energy (E_{k} ) of a photoelectron varies with the frequency ( v ) of the incident radiation as

physics-General

maths-

#### If f(x) is a differentiable function satisfying f(x+ y)= f(x)f(y) x, y R and f'(0)=2 then f(x)=

#### If f(x) is a differentiable function satisfying f(x+ y)= f(x)f(y) x, y R and f'(0)=2 then f(x)=

maths-General

maths-

#### If f(x) = ax^{2}+ bx + c such that f(p) + f(q) = 0 where a0 ; p , qR then number of real roots of equation f(x) = 0in interval [p, q] is

f(p)=–f(q) eitherf(p)f(q)<0 or f(p) =0=f(q)

exactlyonerootin(p,q) orrootsarepandq

exactlyonerootin(p,q) orrootsarepandq

#### If f(x) = ax^{2}+ bx + c such that f(p) + f(q) = 0 where a0 ; p , qR then number of real roots of equation f(x) = 0in interval [p, q] is

maths-General

f(p)=–f(q) eitherf(p)f(q)<0 or f(p) =0=f(q)

exactlyonerootin(p,q) orrootsarepandq

exactlyonerootin(p,q) orrootsarepandq

maths-

#### If f(x) is a polynomial of degree five with leading coefficient one such that f(1)=1^{2},f(2)=2^{2},f(3)=3^{2},f(4)=4^{2},f(5)=5^{2} then

#### If f(x) is a polynomial of degree five with leading coefficient one such that f(1)=1^{2},f(2)=2^{2},f(3)=3^{2},f(4)=4^{2},f(5)=5^{2} then

maths-General