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Maths-

General

Easy

Question

If $n element of N comma$ and theperiod of $fraction numerator c o s invisible function application n x over denominator s i n invisible function application open parentheses fraction numerator x over denominator n end fraction close parentheses end fraction$ is $4 pi$ , then $n equals$

4
3
2
1

The correct answer is: 2

$text L.C.M. of end text open parentheses fraction numerator 2 pi over denominator n end fraction comma 2 pi n close parentheses equals 4 pi$

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