Physics
General
Easy
Question
In a common emitter amplifier, using output resistance of 5000Ω and input resistance of 2000Ω, if the peak value of input signal voltage is 10mv and β=50 then what is the peak value of output voltage?


- 1.25 Volt
- 125 Volt
The correct answer is: 1.25 Volt
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If the tangent at the point
on the curve
meets the curve again at
The given curve is ay2 = x3
The point of tangency is (at2, at3)
Let the point that tangent intersects again be (as2, as3)
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Now, we will use two point form to solve the question.
If (x1, y1) and (x2, y2) be two points on the line then the slope is

For this question, it will be

We will solve it further and find the value.


(s - t) = 0
s = t
It means the same point of tangency. We want to find different point.
(2s + t) = 0
s =
So, the point will be

This is the required answer.
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Let the point that tangent intersects again be (as2, as3)
We can find the slope of tangent by differentiating the given curve w.r.t x
Now, we will use two point form to solve the question.
If (x1, y1) and (x2, y2) be two points on the line then the slope is
For this question, it will be
We will solve it further and find the value.
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s = t
It means the same point of tangency. We want to find different point.
(2s + t) = 0
s =
So, the point will be
This is the required answer.
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on the curve
meets the curve again at
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The given curve is ay2 = x3
The point of tangency is (at2, at3)
Let the point that tangent intersects again be (as2, as3)
We can find the slope of tangent by differentiating the given curve w.r.t x

Now, we will use two point form to solve the question.
If (x1, y1) and (x2, y2) be two points on the line then the slope is

For this question, it will be

We will solve it further and find the value.


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s = t
It means the same point of tangency. We want to find different point.
(2s + t) = 0
s =
So, the point will be

This is the required answer.
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Now, we will use two point form to solve the question.
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For this question, it will be
We will solve it further and find the value.
(s - t) = 0
s = t
It means the same point of tangency. We want to find different point.
(2s + t) = 0
s =
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This is the required answer.
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Slope1 × Slope2 = -1
We will substitute (3) in (1)
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Divide (5) by (6)
This is the required answer.
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We will take the derivative of equation (1) w.r.t x.
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This is this slope of first curve. We will call it slope1.
In the same way we will take the derivative of equation (2) w.r.t x
2Ax + 2By
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We will call it slope2.
The two curves are orthogonal. So, the product of their slope is -1.
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Divide (5) by (6)

This is the required answer.
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ax2 + by2 = 1 ...(1)
Ax2 + By2 = 1 ...(2)
We will take the derivative of equation (1) w.r.t x.
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This is this slope of first curve. We will call it slope1.
In the same way we will take the derivative of equation (2) w.r.t x
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