In /_\abc,a^(2)cot a+b^(2)cot b+c^(2)cot c= -Turito

General

Easy

Maths-

In $straight capital delta A B C comma a squared cot invisible function application A plus b squared cot invisible function application B plus C squared cot invisible function application C equals$

Maths-General

$4 Δ$
$3 Δ$
$Δ$
$2 Δ$

Answer:The correct answer is: $4 straight capital delta$

Book A Free Demo

Name

Mobile

+91

Grade

I agree to get WhatsApp notifications & Marketing updates

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

In $straight capital delta A B C comma a squared cot invisible function application A plus b squared cot invisible function application B plus C squared cot invisible function application C equals$

$4 Δ$
$3 Δ$
$Δ$
$2 Δ$

Answer:The correct answer is: $4 straight capital delta$

Book A Free Demo

Related Questions to study

$Lt subscript x not stretchy rightwards arrow 1 end subscript space left parenthesis 1 minus x right parenthesis tan space open parentheses pi x over 2 close parentheses equals$

$Lt subscript x not stretchy rightwards arrow 1 end subscript space left parenthesis 1 minus x right parenthesis tan space open parentheses pi x over 2 close parentheses equals$

In $straight capital delta A B C comma sum a cubed sin invisible function application left parenthesis B minus C right parenthesis equals$

In $straight capital delta A B C comma sum a cubed sin invisible function application left parenthesis B minus C right parenthesis equals$

$Lt subscript x not stretchy rightwards arrow a end subscript fraction numerator square root of a plus 2 x end root minus square root of 3 x end root over denominator square root of 3 a plus x end root minus 2 square root of x end fraction equals$

$Lt subscript x not stretchy rightwards arrow a end subscript fraction numerator square root of a plus 2 x end root minus square root of 3 x end root over denominator square root of 3 a plus x end root minus 2 square root of x end fraction equals$

In $straight triangle A B C comma cot invisible function application A over 2 plus cot invisible function application B over 2 plus cot invisible function application C over 2 equals$

In $straight triangle A B C comma cot invisible function application A over 2 plus cot invisible function application B over 2 plus cot invisible function application C over 2 equals$

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

$text In end text straight triangle A B C comma straight capital sigma fraction numerator a squared sin invisible function application left parenthesis B minus C right parenthesis over denominator sin invisible function application A end fraction equals$

$text In end text straight triangle A B C comma straight capital sigma fraction numerator a squared sin invisible function application left parenthesis B minus C right parenthesis over denominator sin invisible function application A end fraction equals$

$Lt subscript x not stretchy rightwards arrow 1 end subscript fraction numerator left parenthesis 2 x minus 3 right parenthesis left parenthesis square root of x minus 1 right parenthesis over denominator 2 x squared plus x minus 3 end fraction equals$

$Lt subscript x not stretchy rightwards arrow 1 end subscript fraction numerator left parenthesis 2 x minus 3 right parenthesis left parenthesis square root of x minus 1 right parenthesis over denominator 2 x squared plus x minus 3 end fraction equals$

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

$L t subscript x not stretchy rightwards arrow 2 end subscript open parentheses fraction numerator square root of 1 minus cos space left curly bracket 2 left parenthesis x minus 2 right parenthesis factorial end root over denominator x minus 2 end fraction close parentheses equals$

$L t subscript x not stretchy rightwards arrow 2 end subscript open parentheses fraction numerator square root of 1 minus cos space left curly bracket 2 left parenthesis x minus 2 right parenthesis factorial end root over denominator x minus 2 end fraction close parentheses equals$

$Lt subscript x not stretchy rightwards arrow straight infinity end subscript fraction numerator 11 x cubed minus 3 x plus 4 over denominator 13 x cubed minus 5 x squared minus 7 end fraction$

$Lt subscript x not stretchy rightwards arrow straight infinity end subscript fraction numerator 11 x cubed minus 3 x plus 4 over denominator 13 x cubed minus 5 x squared minus 7 end fraction$

In $straight capital delta A B C$ , cot $A plus cot invisible function application B plus cot invisible function application C equals$

In $straight capital delta A B C$ , cot $A plus cot invisible function application B plus cot invisible function application C equals$

$Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cube root of 1 plus x end root minus cube root of 1 minus x end root over denominator x end fraction equals$

$Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cube root of 1 plus x end root minus cube root of 1 minus x end root over denominator x end fraction equals$

Courses

Quick Links

Follow Us at

Support

Download App

Courses

Quick Links

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

In

Answer:The correct answer is:

Book A Free Demo

Related Questions to study

In

In

Let and be the distinct roots of then

Let and be the distinct roots of then

In

In

If then k=

If then k=

If then the values of a and b are

If then the values of a and b are

If

If

In , cot

In , cot

Courses

Quick Links

In $straight capital delta A B C comma a squared cot invisible function application A plus b squared cot invisible function application B plus C squared cot invisible function application C equals$

Answer:The correct answer is: $4 straight capital delta$

In $straight capital delta A B C comma sum a cubed sin invisible function application left parenthesis B minus C right parenthesis equals$

In $straight capital delta A B C comma sum a cubed sin invisible function application left parenthesis B minus C right parenthesis equals$

In $straight triangle A B C comma cot invisible function application A over 2 plus cot invisible function application B over 2 plus cot invisible function application C over 2 equals$

In $straight triangle A B C comma cot invisible function application A over 2 plus cot invisible function application B over 2 plus cot invisible function application C over 2 equals$

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

In $straight capital delta A B C$ , cot $A plus cot invisible function application B plus cot invisible function application C equals$

In $straight capital delta A B C$ , cot $A plus cot invisible function application B plus cot invisible function application C equals$