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Question

Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Equation of the plane containing the triangle ABC is

  1. x+y+3=0
  2. x-z-3=0
  3. x-z+3=0
  4. x-y+3=0

The correct answer is: x-z+3=0

Related Questions to study

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Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Projection of AB on BC is

Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Projection of AB on BC is

maths-General
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Let A(2,3,5), B(-1,3,2),  are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following The value of  is equal to

Let A(2,3,5), B(-1,3,2),  are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following The value of  is equal to

maths-General
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Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The image of plane P1 in the plane mirror P2 is

 Therefore, the equation becomes 7x-y+2z=9.

Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The image of plane P1 in the plane mirror P2 is

Maths-General

 Therefore, the equation becomes 7x-y+2z=9.

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Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The equation of the bisector of angle of the planes P1 and P2 which not containing origin is

P subscript 1 colon 2 x minus y plus z equals 2 + P subscript 2 colon x plus 2 y minus z equals 3
-> 3x +y = 5.

Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The equation of the bisector of angle of the planes P1 and P2 which not containing origin is

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P subscript 1 colon 2 x minus y plus z equals 2 + P subscript 2 colon x plus 2 y minus z equals 3
-> 3x +y = 5.

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Let f left parenthesis x right parenthesis equals sin invisible function application x integral subscript 1 superscript x   cos invisible function application t d t plus 2 integral subscript 0 superscript x   t d t plus cos squared invisible function application x minus x squared then area bounded by x. f(x), and x=0, x=5 with x axis, is (in sq units)

Let f left parenthesis x right parenthesis equals sin invisible function application x integral subscript 1 superscript x   cos invisible function application t d t plus 2 integral subscript 0 superscript x   t d t plus cos squared invisible function application x minus x squared then area bounded by x. f(x), and x=0, x=5 with x axis, is (in sq units)

maths-General
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(6,6) is a point on the circle x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 12 equals 0 by translation of origin to a certain point the translated equation is x to the power of 2 end exponent plus y to the power of 2 end exponent equals 25 the new co-ordinates of (6,6) are

(6,6) is a point on the circle x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 12 equals 0 by translation of origin to a certain point the translated equation is x to the power of 2 end exponent plus y to the power of 2 end exponent equals 25 the new co-ordinates of (6,6) are

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The locus of points from which lengths of tangents to the two circles x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x plus 3 equals 0 comma x squared plus y squared minus 6 x plus 5 equals 0 are in the ratio 2 : 3 is a circle with centre

The locus of points from which lengths of tangents to the two circles x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x plus 3 equals 0 comma x squared plus y squared minus 6 x plus 5 equals 0 are in the ratio 2 : 3 is a circle with centre

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A gas is found to have a density of 1.80 g L to the power of negative 1 end exponent at 760 mm pressure and 27ºC. The gas will be

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If X is the total number of collisions which a gas molecule registers with others per unit time under particular conditions, then the collision frequency of the gas containing N molecules per unit volume is

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At 100ºC and 1 atm, if the density of liquid water is 1.0 g cm-3  and that of water vapour is 0.0006  g cm-3, then the volume occupied by water molecules in 1 litre of steam at that temperature is

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chemistry-General
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Assertion : The equivalent resistance between the points X and Y in the figure, is 10 capital omega

Reason : According to wheat stone bridge points A and C have the same potential

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Reason : According to wheat stone bridge points A and C have the same potential

physics-General
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In the circuit shown in fig., the potential difference between the points C and D is balanced against 40 cm length of potentiometer wire of total length 100 cm. In order to balance the potential difference between the points D and E. The jockey be pressed on potentiometer wire at a distance of

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Three bulbs with their power and working voltage are connected as shown in the circuit diagram to a 12 V battery. The total power consumed by the bulbs is (ignore the internal resistance of the battery shown)

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In the following circuit, 5 capital omega resistor develops 45 J/s due to current flowing through it. The power developed across 12W resistor is

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Find out the value of current through 2 capital omega resistance for the given circuit

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