Maths-
General
Easy

Question

Let a, b and c be real numbers, c≠0, Show that each of the following statements is true :
1. If a>b and c<0 , then ca< cb
2. If a>b and c<0 , then .a over c less than b over c

hintHint:

Linear inequalities are expressions where any two values are compared by the inequality symbols<,>,≤&≥ .
We are asked to prove the given statements.

The correct answer is: a/c<b/c


    Step 1 of 2:
    Given that, a<b and c<0.
    Multiply c with the inequality, so we get:
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell a greater than b end cell row cell a c less than b c end cell end table
    Here, the direction of symbol changes because we multiplied the inequality by a negative number.
    Step 2 of 2:
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell a greater than b end cell row cell a over c less than b over c end cell end table
    Similar to the previous step, here we divide the inequality by a negative number and hence the direction of the symbol changes.

    Whenever we multiply or divide an inequality by a negative number, the direction of the inequality symbol changes.

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