Maths-

General

Easy

Question

# Let be two sets. Then

- P=Q

Hint:

### In the two sets is derived from the given trigonometric equations in the respective sets. So, we will first simplify the equation then will get the relation between them.

## The correct answer is: P=Q

### Given two sets

### Related Questions to study

Maths-

### If then is

### If then is

Maths-General

physics-

### A long cylindrical tube carries a highly polished piston and has a side opening. A tuning fork of frequency n is sounded at the sound heard by the listener charges if the piston is moves in or out. At a particular position of the piston is moved through a distance of 9 cm, the intensity of sound becomes minimum, if the speed of sound is 360 m/s, the value of n is

When piston moves a distance, path difference change by 2 xs.

the path difference between maxima and consecutive minima=

∴

Or

λ=4x=4×9 cm=36cm=0.36m

the path difference between maxima and consecutive minima=

∴

Or

λ=4x=4×9 cm=36cm=0.36m

### A long cylindrical tube carries a highly polished piston and has a side opening. A tuning fork of frequency n is sounded at the sound heard by the listener charges if the piston is moves in or out. At a particular position of the piston is moved through a distance of 9 cm, the intensity of sound becomes minimum, if the speed of sound is 360 m/s, the value of n is

physics-General

When piston moves a distance, path difference change by 2 xs.

the path difference between maxima and consecutive minima=

∴

Or

λ=4x=4×9 cm=36cm=0.36m

the path difference between maxima and consecutive minima=

∴

Or

λ=4x=4×9 cm=36cm=0.36m

Maths-

The value of

The value of

Maths-General

Maths-

For any real , the maximum value of is

As cos is a decreasing function and sin is an increasing function so the function is maximum when =.

So, the maximum value of =

So, the maximum value of =

For any real , the maximum value of is

Maths-General

As cos is a decreasing function and sin is an increasing function so the function is maximum when =.

So, the maximum value of =

So, the maximum value of =

chemistry-

### Identify A and B

With H

_{2}/ pd / CaCO_{3}- is addition of ‘H’ know is oxidizing agent### Identify A and B

chemistry-General

With H

_{2}/ pd / CaCO_{3}- is addition of ‘H’ know is oxidizing agentMaths-

### If then sin (A-B) =

GIVEN-

$√2cosA=cosB+cos_{3}B..... equation 1$

$cosAcosB+cos_{3}√2)$

# √2 sin A = sin B - sin

∴ sin A = 1/√2 (sin B - sin

TO FIND-

Sin (A - B)

SOLUTION-

We know that-

Sin (A - B) = (Sin A * Cos B) - (Cos A * Sin B)

∴ Sin (A - B) = [1/√2 (sin B - sin

∴ Sin (A - B) = [1/√2 * (sin B Cos B - sin

∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

∴ Sin (A - B) = -1/√2 sin

∴ Sin (A - B) = -1/√2 sin B Cos B (sin

= -1/2√2 sin2B

Now squaring and adding equation 1 and 2 we get

$√2cosA=cosB+cos_{3}B..... equation 1$

$cosAcosB+cos_{3}√2)$

# √2 sin A = sin B - sin^{3} B..... equation 2

∴ sin A = 1/√2 (sin B - sin^{3}B) ........ (Dividing both sides by √2)TO FIND-

Sin (A - B)

SOLUTION-

We know that-

Sin (A - B) = (Sin A * Cos B) - (Cos A * Sin B)

∴ Sin (A - B) = [1/√2 (sin B - sin

^{3}B) * cos B] - [1/√2 (cos B + cos^{3}B) * sin B] ...... (From Equations i & ii)∴ Sin (A - B) = [1/√2 * (sin B Cos B - sin

^{3}B Cos B)] - [1/√2 * (sin B cos B + cos^{3}B * sin B)]∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

^{3}B Cos B - (1/√2 sin B cos B + 1/√2 cos^{3}B * sin B)∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

^{3}B Cos B - 1/√2 sin B cos B - 1/√2 cos^{3}B * sin B∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

^{3}B Cos B - 1/√2 sin B cos B - 1/√2 cos^{3}B * sin B∴ Sin (A - B) = -1/√2 sin

^{3}B Cos B - 1/√2 cos^{3}B * sin B∴ Sin (A - B) = -1/√2 sin B Cos B (sin

^{2}B +cos^{2}B)= -1/2√2 sin2B

Now squaring and adding equation 1 and 2 we get

### If then sin (A-B) =

Maths-General

GIVEN-

$√2cosA=cosB+cos_{3}B..... equation 1$

$cosAcosB+cos_{3}√2)$

# √2 sin A = sin B - sin

∴ sin A = 1/√2 (sin B - sin

TO FIND-

Sin (A - B)

SOLUTION-

We know that-

Sin (A - B) = (Sin A * Cos B) - (Cos A * Sin B)

∴ Sin (A - B) = [1/√2 (sin B - sin

∴ Sin (A - B) = [1/√2 * (sin B Cos B - sin

∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

∴ Sin (A - B) = -1/√2 sin

∴ Sin (A - B) = -1/√2 sin B Cos B (sin

= -1/2√2 sin2B

Now squaring and adding equation 1 and 2 we get

$√2cosA=cosB+cos_{3}B..... equation 1$

$cosAcosB+cos_{3}√2)$

# √2 sin A = sin B - sin^{3} B..... equation 2

∴ sin A = 1/√2 (sin B - sin^{3}B) ........ (Dividing both sides by √2)TO FIND-

Sin (A - B)

SOLUTION-

We know that-

Sin (A - B) = (Sin A * Cos B) - (Cos A * Sin B)

∴ Sin (A - B) = [1/√2 (sin B - sin

^{3}B) * cos B] - [1/√2 (cos B + cos^{3}B) * sin B] ...... (From Equations i & ii)∴ Sin (A - B) = [1/√2 * (sin B Cos B - sin

^{3}B Cos B)] - [1/√2 * (sin B cos B + cos^{3}B * sin B)]∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

^{3}B Cos B - (1/√2 sin B cos B + 1/√2 cos^{3}B * sin B)∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

^{3}B Cos B - 1/√2 sin B cos B - 1/√2 cos^{3}B * sin B∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin

^{3}B Cos B - 1/√2 sin B cos B - 1/√2 cos^{3}B * sin B∴ Sin (A - B) = -1/√2 sin

^{3}B Cos B - 1/√2 cos^{3}B * sin B∴ Sin (A - B) = -1/√2 sin B Cos B (sin

^{2}B +cos^{2}B)= -1/2√2 sin2B

Now squaring and adding equation 1 and 2 we get

chemistry-

### Observer the following reactions and predict the nature of A and B

Conceptual

### Observer the following reactions and predict the nature of A and B

chemistry-General

Conceptual

chemistry-

### on ozonolysis gives

### on ozonolysis gives

chemistry-General

chemistry-

### Which of the following reactions will yield 2, 2-dibromopropane?

### Which of the following reactions will yield 2, 2-dibromopropane?

chemistry-General

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### If then is equal to

### If then is equal to

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### If where being an acute angle then is equal to

### If where being an acute angle then is equal to

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maths-

### Let A,B,C be three angles such that and . Then, all possible values of P such that A,B,C are the angles of a triangle is

### Let A,B,C be three angles such that and . Then, all possible values of P such that A,B,C are the angles of a triangle is

maths-General

chemistry-

### is an example for

### is an example for

chemistry-General

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### If where then =

### If where then =

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chemistry-

### What is the hybridization state of benzyl carbonium ion

All carbons are sp

^{2}### What is the hybridization state of benzyl carbonium ion

chemistry-General

All carbons are sp

^{2}