Let p={theta:sin theta-cos theta=sqrt2cos theta} and q={theta-Turito

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Let $P equals left curly bracket theta colon sin space theta minus cos space theta equals square root of 2 cos space theta right curly bracket text and end text Q equals left curly bracket theta colon sin space theta plus cos space theta equals square root of 2 sin space theta right curly bracket$ be two sets. Then

$P \subset Q and P \neq \emptyset$
$Q \subset\subset P$
$P \subset Q$
P=Q

Hint:

In the two sets $theta$ is derived from the given trigonometric equations in the respective sets. So, we will first simplify the equation then will get the relation between them.

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Question

Let be two sets. Then

P=Q

Hint:

Answer

The correct answer is: P=Q

Solution

Given two sets

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