Lt_(x rarr(pi)/(2))([1-tan (x)/(2)][1-sin x])/([1+tan (x)/(2)][-Turito

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Question

$Lt subscript x not stretchy rightwards arrow pi over 2 end subscript space fraction numerator open square brackets 1 minus tan space x over 2 close square brackets left square bracket 1 minus sin space x right square bracket over denominator open square brackets 1 plus tan space x over 2 close square brackets left square bracket pi minus 2 x right square bracket cubed end fraction equals$

$\frac{1}{8}$
0
$\frac{1}{32}$
$\infty$

Hint:

In this question firstly we will solve the trigonometric equation and after eliminating the tan part. Then we will use the L'hospital theorem twice and later evaluate and put the value.

The correct answer is: $1 over 32$

$space space space space Lt subscript x not stretchy rightwards arrow pi over 2 end subscript space fraction numerator open square brackets 1 minus tan space x over 2 close square brackets left square bracket 1 minus sin space x right square bracket over denominator open square brackets 1 plus tan space x over 2 close square brackets left square bracket pi minus 2 x right square bracket cubed end fraction equals Lt subscript x not stretchy rightwards arrow pi over 2 end subscript space fraction numerator open square brackets tan begin display style straight pi over 4 end style minus tan space x over 2 close square brackets over denominator open square brackets tan space begin display style straight pi over 4 end style plus tan space x over 2 close square brackets end fraction. fraction numerator left square bracket 1 minus sin space x right square bracket over denominator left square bracket pi minus 2 x right square bracket cubed end fraction equals Lt subscript x not stretchy rightwards arrow pi over 2 end subscript space tan space open parentheses straight pi over 4 minus x over 2 close parentheses. fraction numerator left square bracket 1 minus sin space x right square bracket over denominator left square bracket pi minus 2 x right square bracket cubed end fraction equals Lt subscript x not stretchy rightwards arrow pi over 2 end subscript space fraction numerator tan space open parentheses begin display style fraction numerator straight pi minus 2 straight x over denominator 4 end fraction end style close parentheses over denominator open parentheses begin display style fraction numerator straight pi minus 2 straight x over denominator 4 end fraction end style close parentheses end fraction. fraction numerator left square bracket 1 minus sin space x right square bracket over denominator 4 left square bracket pi minus 2 x right square bracket squared end fraction equals 1 fourth space Lt subscript x not stretchy rightwards arrow pi over 2 end subscript fraction numerator left square bracket 1 minus sin space x right square bracket over denominator left square bracket pi minus 2 x right square bracket squared end fraction U sin g space L apostrophe H o s p i t a l space t h e o r e m comma space equals 1 fourth space Lt subscript x not stretchy rightwards arrow pi over 2 end subscript fraction numerator negative cos space x over denominator 2 left parenthesis straight pi minus 2 straight x right parenthesis. left parenthesis negative 2 right parenthesis end fraction equals 1 over 16 space Lt subscript x not stretchy rightwards arrow pi over 2 end subscript fraction numerator cos space x over denominator left parenthesis straight pi minus 2 straight x right parenthesis end fraction equals 1 over 16 Lt subscript x not stretchy rightwards arrow pi over 2 end subscript fraction numerator cos space x over denominator straight pi minus 2 straight x end fraction equals 1 over 16 Lt subscript x not stretchy rightwards arrow pi over 2 end subscript fraction numerator cos space x over denominator straight pi minus 2 straight x end fraction U sin g space L apostrophe H o s p i t a l space t h e o r e m comma space equals 1 over 16 Lt subscript x not stretchy rightwards arrow pi over 2 end subscript fraction numerator negative sin space x over denominator negative 2 end fraction equals 1 over 32 Lt subscript x not stretchy rightwards arrow pi over 2 end subscript space sin space x equals 1 over 32 cross times sin space straight pi over 2 equals 1 over 32 space cross times 1 equals 1 over 32.$

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$\frac{1}{8}$
0
$\frac{1}{32}$
$\infty$

The correct answer is: $1 over 32$

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In $straight capital delta A B C$ , cot $A plus cot invisible function application B plus cot invisible function application C equals$

In $straight capital delta A B C$ , cot $A plus cot invisible function application B plus cot invisible function application C equals$

In $straight triangle A B C comma$ cot $A plus cot invisible function application B plus cot invisible function application C equals$

In $straight triangle A B C comma$ cot $A plus cot invisible function application B plus cot invisible function application C equals$

A ray of light strikes a plane mirror at an angle of incidence 45⁰ as shown in the figure After reflection, the ray passes through a prism of refractive index 1.50, whose apex angle is 4⁰ The angle through which the mirror should be rotated if the total deviation of the ray is to be 90⁰ is

A ray of light strikes a plane mirror at an angle of incidence 45⁰ as shown in the figure After reflection, the ray passes through a prism of refractive index 1.50, whose apex angle is 4⁰ The angle through which the mirror should be rotated if the total deviation of the ray is to be 90⁰ is