Lt_(x rarr1)(1-x)tan(pi(x)/(2))= -Turito

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$Lt subscript x not stretchy rightwards arrow 1 end subscript space left parenthesis 1 minus x right parenthesis tan space open parentheses pi x over 2 close parentheses equals$

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$\frac{3}{π}$
$\frac{1}{π}$
$\frac{2}{π}$
$\frac{4}{π}$

Answer:The correct answer is: $2 over pi$

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$Lt subscript x not stretchy rightwards arrow 1 end subscript space left parenthesis 1 minus x right parenthesis tan space open parentheses pi x over 2 close parentheses equals$

$\frac{3}{π}$
$\frac{1}{π}$
$\frac{2}{π}$
$\frac{4}{π}$

Answer:The correct answer is: $2 over pi$

Book A Free Demo

Related Questions to study

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If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

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In

In

In

In

Let and be the distinct roots of then

Let and be the distinct roots of then

If then k=

If then k=

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Answer:The correct answer is: $2 over pi$

In $straight capital delta A B C comma a squared cot invisible function application A plus b squared cot invisible function application B plus C squared cot invisible function application C equals$

In $straight capital delta A B C comma a squared cot invisible function application A plus b squared cot invisible function application B plus C squared cot invisible function application C equals$

In $straight capital delta A B C comma sum a cubed sin invisible function application left parenthesis B minus C right parenthesis equals$

In $straight capital delta A B C comma sum a cubed sin invisible function application left parenthesis B minus C right parenthesis equals$

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

In $straight triangle A B C comma cot invisible function application A over 2 plus cot invisible function application B over 2 plus cot invisible function application C over 2 equals$

In $straight triangle A B C comma cot invisible function application A over 2 plus cot invisible function application B over 2 plus cot invisible function application C over 2 equals$

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are