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Question

A function f(x) satisfying stretchy integral subscript 0 end subscript superscript 1 end superscript   f left parenthesis t x right parenthesis d t equals n f left parenthesis x right parenthesis comma text end textwhere x>0 , is

  1. f left parenthesis x right parenthesis equals c times x to the power of fraction numerator 1 minus n over denominator n end fraction end exponent    
  2. f left parenthesis x right parenthesis equals c times x to the power of fraction numerator n over denominator u minus 1 end fraction end exponent    
  3. f left parenthesis x right parenthesis equals c times x to the power of fraction numerator 1 over denominator n end fraction end exponent    
  4. f left parenthesis x right parenthesis equals c times x to the power of left parenthesis 1 minus n right parenthesis end exponent    

The correct answer is: f left parenthesis x right parenthesis equals c times x to the power of fraction numerator 1 minus n over denominator n end fraction end exponent

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text If  end text y equals fraction numerator x over denominator l n invisible function application vertical line c x vertical line end fraction (where c is an arbitrary constant) is the general solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator y over denominator x end fraction plus phi open parentheses fraction numerator x over denominator y end fraction close parentheses text end textthen the function text end text phi open parentheses fraction numerator x over denominator y end fraction close parentheses text  is : end text

text If  end text y equals fraction numerator x over denominator l n invisible function application vertical line c x vertical line end fraction (where c is an arbitrary constant) is the general solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator y over denominator x end fraction plus phi open parentheses fraction numerator x over denominator y end fraction close parentheses text end textthen the function text end text phi open parentheses fraction numerator x over denominator y end fraction close parentheses text  is : end text

maths-General
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A function y = f (x) satisfies the condition f '(x) sin x + f (x) cos x = 1, f (x) being bounded when x rightwards arrow 0. If I equals stretchy integral subscript 0 end subscript superscript there exists 2 end superscript   f left parenthesis x right parenthesis d x text  then end text

A function y = f (x) satisfies the condition f '(x) sin x + f (x) cos x = 1, f (x) being bounded when x rightwards arrow 0. If I equals stretchy integral subscript 0 end subscript superscript there exists 2 end superscript   f left parenthesis x right parenthesis d x text  then end text

Maths-General
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maths-

Statement-I : In throwing of two dice, let the events A, B and C be 'the first dice shows an even number', 'the second dice shows an odd numbers' and 'both the dice show an odd numbers or both the dice show an even number’ respectively. Then text end text P left parenthesis A right parenthesis equals P left parenthesis B right parenthesis equals P left parenthesis C right parenthesis equals fraction numerator 1 over denominator 2 end fraction text end textand P left parenthesis A intersection B right parenthesis equals P left parenthesis B intersection C right parenthesis equals P left parenthesis C intersection A right parenthesis equals fraction numerator 1 over denominator 4 end fraction Therefore A, B and C are mutually independent events
Statement-II : Three events A, B and C are mutually independent if and only if P(A Ç B) = P(A) . P(B), P(B Ç C) = P(B) . P(C), P left parenthesis C intersection A right parenthesis equals P left parenthesis C right parenthesis= P(C) . P(A) and P left parenthesis A intersection B intersection C right parenthesis= P(A) . P(B) . P(C)

Statement-I : In throwing of two dice, let the events A, B and C be 'the first dice shows an even number', 'the second dice shows an odd numbers' and 'both the dice show an odd numbers or both the dice show an even number’ respectively. Then text end text P left parenthesis A right parenthesis equals P left parenthesis B right parenthesis equals P left parenthesis C right parenthesis equals fraction numerator 1 over denominator 2 end fraction text end textand P left parenthesis A intersection B right parenthesis equals P left parenthesis B intersection C right parenthesis equals P left parenthesis C intersection A right parenthesis equals fraction numerator 1 over denominator 4 end fraction Therefore A, B and C are mutually independent events
Statement-II : Three events A, B and C are mutually independent if and only if P(A Ç B) = P(A) . P(B), P(B Ç C) = P(B) . P(C), P left parenthesis C intersection A right parenthesis equals P left parenthesis C right parenthesis= P(C) . P(A) and P left parenthesis A intersection B intersection C right parenthesis= P(A) . P(B) . P(C)

maths-General
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General
maths-

The probability that 4th power of a positive integer ends in the digit 6 is:

The probability that 4th power of a positive integer ends in the digit 6 is:

maths-General
General
maths-

Let A, B, C be pairwise independent events with P(C)> 0 and P left parenthesis A intersection B intersection C right parenthesis equals 0. Then P open parentheses A to the power of c end exponent intersection B to the power of c end exponent C close parentheses text  is equal to: end text

Let A, B, C be pairwise independent events with P(C)> 0 and P left parenthesis A intersection B intersection C right parenthesis equals 0. Then P open parentheses A to the power of c end exponent intersection B to the power of c end exponent C close parentheses text  is equal to: end text

maths-General
General
maths-

Let A and B be two events such that P left parenthesis stack A union B with bar on top right parenthesis equals fraction numerator 1 over denominator 6 end fraction comma P left parenthesis A intersection B right parenthesis equals fraction numerator 1 over denominator 4 end fraction and P left parenthesis stack A with bar on top right parenthesis equals fraction numerator 1 over denominator 4 end fraction comma text  where  end text stack A with bar on top stands for complement of event A. Then events A and B are-

Let A and B be two events such that P left parenthesis stack A union B with bar on top right parenthesis equals fraction numerator 1 over denominator 6 end fraction comma P left parenthesis A intersection B right parenthesis equals fraction numerator 1 over denominator 4 end fraction and P left parenthesis stack A with bar on top right parenthesis equals fraction numerator 1 over denominator 4 end fraction comma text  where  end text stack A with bar on top stands for complement of event A. Then events A and B are-

maths-General
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General
maths-

A random variable X has the probability distribution :

For the events E = {X is a prime number} and F = {X < 4}, the probability P left parenthesis E union F right parenthesis is-

A random variable X has the probability distribution :

For the events E = {X is a prime number} and F = {X < 4}, the probability P left parenthesis E union F right parenthesis is-

maths-General
General
maths-

A fair coin is tossed 3 times. Consider the events A : first toss is head ; B : second toss is head C : exactly two consecutive heads or exactly two consecutive tails
Statement - I A,B,C are independent events.
Statement - II A,B,C are pairwise independent.

A fair coin is tossed 3 times. Consider the events A : first toss is head ; B : second toss is head C : exactly two consecutive heads or exactly two consecutive tails
Statement - I A,B,C are independent events.
Statement - II A,B,C are pairwise independent.

maths-General
General
maths-

An experiment resulting in sample space as S = {a, b, c, d, e, f} text  with  end text P left parenthesis A right parenthesis equals fraction numerator 1 over denominator 16 end fraction comma P left parenthesis B right parenthesis equals fraction numerator 1 over denominator 16 end fraction comma P left parenthesis C right parenthesis equals fraction numerator 2 over denominator 16 end fraction comma P left parenthesis D right parenthesis equals fraction numerator 3 over denominator 16 end fraction comma P left parenthesis e right parenthesis equals fraction numerator 4 over denominator 16 end fraction text  and  end text P left parenthesis f right parenthesis equals fraction numerator 5 over denominator 16 end fraction text  . end text Let three events A, B and C are defined as A = {a, c, e,}, B = {c, d, e, f} and C = {b, c, f}. text  If  end text P left parenthesis A divided by B right parenthesis equals p subscript 1 end subscript comma P left parenthesis B divided by C right parenthesis equals p subscript 2 end subscript comma P open parentheses C divided by A to the power of c end exponent close parentheses equals p subscript 3 end subscript text  and  end text P open parentheses A to the power of c end exponent divided by C close parentheses equals p subscript 4 end subscript then the correct order sequance is

An experiment resulting in sample space as S = {a, b, c, d, e, f} text  with  end text P left parenthesis A right parenthesis equals fraction numerator 1 over denominator 16 end fraction comma P left parenthesis B right parenthesis equals fraction numerator 1 over denominator 16 end fraction comma P left parenthesis C right parenthesis equals fraction numerator 2 over denominator 16 end fraction comma P left parenthesis D right parenthesis equals fraction numerator 3 over denominator 16 end fraction comma P left parenthesis e right parenthesis equals fraction numerator 4 over denominator 16 end fraction text  and  end text P left parenthesis f right parenthesis equals fraction numerator 5 over denominator 16 end fraction text  . end text Let three events A, B and C are defined as A = {a, c, e,}, B = {c, d, e, f} and C = {b, c, f}. text  If  end text P left parenthesis A divided by B right parenthesis equals p subscript 1 end subscript comma P left parenthesis B divided by C right parenthesis equals p subscript 2 end subscript comma P open parentheses C divided by A to the power of c end exponent close parentheses equals p subscript 3 end subscript text  and  end text P open parentheses A to the power of c end exponent divided by C close parentheses equals p subscript 4 end subscript then the correct order sequance is

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An ellipse is drawn with major and minor axes of lengths 10 and 8 respectively. Using one focus as centre, a circle is drawn that is tangent to the ellipse, with no part of the circle being outside the ellipse. The radius of the circle is

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From a point P, perpendicular tangents PQ and PR are drawn to ellipse x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 4 Locus of circumcentre of triangle PQR is

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maths-General
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The least integral value that contained is the range of the function f defined by f left parenthesis x right parenthesis equals fraction numerator x to the power of 2 end exponent plus 1 over denominator log invisible function application open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction is ___

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Let f left parenthesis x right parenthesis equals L t stretchy sum from n rightwards arrow infinity to n minus 1 of   fraction numerator x over denominator left parenthesis r x plus 1 right parenthesis left curly bracket left parenthesis r plus 1 right parenthesis x plus 1 right curly bracket end fraction comma then

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If m is the slope of tangent to the curve e to the power of y end exponent equals 1 plus x to the power of 2 end exponent then

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maths-General
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If stack l i m with x rightwards arrow 0 below   1 plus x to the power of 2 end exponent plus fraction numerator f open parentheses x close parentheses over denominator x end fraction is equal to e7, then stack l i m with x greater-than or slanted equal to 0 below   fraction numerator f open parentheses x close parentheses over denominator x to the power of 3 end exponent end fraction equals horizontal ellipsis horizontal ellipsis

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maths-General
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