Question
A function whose graph is symmetrical about the origin is given by -
Hint:
The correct answer is: ![f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis plus f left parenthesis y right parenthesis](data:image/png;base64,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)
To find the function from the given options whose graph is symmetrical about the origin.
f(x+y)=f(x)+f(y)
f(x) is of the form f(x)=λx where λ is a constant which represents a straight line passing through the origin, having a slope λ.
Hence, the function f(x+y)=f(x)+f(y) is symmetric about the origin.
Related Questions to study
The minimum value of
is
The minimum value of
is
is -
Hence, the given function is many one and onto.
is -
Hence, the given function is many one and onto.
If f(x) is a polynomial function satisfying the condition f(x). f(1/x) = f(x) + f(1/x) and f(2) = 9 then -
If f(x) is a polynomial function satisfying the condition f(x). f(1/x) = f(x) + f(1/x) and f(2) = 9 then -
Fill in the blank with the appropriate transition.
The movie managed to fetch decent collections ______ all the negative reviews it received.
Fill in the blank with the appropriate transition.
The movie managed to fetch decent collections ______ all the negative reviews it received.
If R be a relation '<' from A = {1, 2, 3, 4} to B = {1, 3, 5} i.e. (a, b)
R iff a < b, then
is ![text-end text](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAA0AAAAHCAYAAADTcMcaAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAGKUc3qwAAABJJREFUeNpjYECA/0TgUUAxAAAFGAj4Gd15qgAAAE90RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bXRleHQ+LTwvbXRleHQ+PC9tYXRoPs3uNooAAAAASUVORK5CYII=)
Values of are {(3, 3), (3, 5), (5, 3), (5, 5)}
If R be a relation '<' from A = {1, 2, 3, 4} to B = {1, 3, 5} i.e. (a, b)
R iff a < b, then
is ![text-end text](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAA0AAAAHCAYAAADTcMcaAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAGKUc3qwAAABJJREFUeNpjYECA/0TgUUAxAAAFGAj4Gd15qgAAAE90RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bXRleHQ+LTwvbXRleHQ+PC9tYXRoPs3uNooAAAAASUVORK5CYII=)
Values of are {(3, 3), (3, 5), (5, 3), (5, 5)}
Which one of the following relations on R is equivalence relation
Which one of the following relations on R is equivalence relation
Let R = {(x, y) : x, y
A, x + y = 5} where A = {1, 2, 3, 4, 5} then
Hence, the given relation is not reflexive, symmetric and not transitive
Let R = {(x, y) : x, y
A, x + y = 5} where A = {1, 2, 3, 4, 5} then
Hence, the given relation is not reflexive, symmetric and not transitive
Let
be a relation defined by
Then R is
Hence, the given relation is Reflexive, transitive but not symmetric.
Let
be a relation defined by
Then R is
Hence, the given relation is Reflexive, transitive but not symmetric.
The relation R defined in N as aRb
b is divisible by a is
Hence, the given relations is reflexive but not symmetric.
The relation R defined in N as aRb
b is divisible by a is
Hence, the given relations is reflexive but not symmetric.