Question

# If f(x) is a polynomial function satisfying the condition f(x). f(1/x) = f(x) + f(1/x) and f(2) = 9 then -

- 2 f(4) = 3f(6)
- 14 f(1) = f(3)
- 9 f(3) = f(5)
- f(10)= f(11)

Hint:

## The correct answer is: 14 f(1) = f(3)

### To choose the correct option from the given function.

The polynomial which satisfies $f(x)f(1/x)=f(x)+f(1/x)$ is ±

Given, $f(2)=9$

$±=9$

$n=3$

Hence the function is $f(x)=$

$f(3)=28,f(1)=2$

14 x f(1) = f(3)

14 x 2 = 28

28 = 28

Given, $f(2)=9$

Hence the function is $f(x)=$

Therefore, 14 f(1) = f(3)

### Related Questions to study

### Fill in the blank with the appropriate transition.

The movie managed to fetch decent collections ______ all the negative reviews it received.

### Fill in the blank with the appropriate transition.

The movie managed to fetch decent collections ______ all the negative reviews it received.

### If R be a relation '<' from A = {1, 2, 3, 4} to B = {1, 3, 5} i.e. (a, b) R iff a < b, then is

Values of are {(3, 3), (3, 5), (5, 3), (5, 5)}

### If R be a relation '<' from A = {1, 2, 3, 4} to B = {1, 3, 5} i.e. (a, b) R iff a < b, then is

Values of are {(3, 3), (3, 5), (5, 3), (5, 5)}

### Which one of the following relations on R is equivalence relation

### Which one of the following relations on R is equivalence relation

### Let R = {(x, y) : x, y A, x + y = 5} where A = {1, 2, 3, 4, 5} then

Hence, the given relation is not reflexive, symmetric and not transitive

### Let R = {(x, y) : x, y A, x + y = 5} where A = {1, 2, 3, 4, 5} then

Hence, the given relation is not reflexive, symmetric and not transitive

### Let be a relation defined by Then R is

Hence, the given relation is Reflexive, transitive but not symmetric.

### Let be a relation defined by Then R is

Hence, the given relation is Reflexive, transitive but not symmetric.

### The relation R defined in N as aRb b is divisible by a is

Hence, the given relations is reflexive but not symmetric.

### The relation R defined in N as aRb b is divisible by a is

Hence, the given relations is reflexive but not symmetric.