Maths-
General
Easy

Question

Eleven animals of a circus have to be placed in eleven cages, one in each cage. If four of the cages are too small for six of the animals, the number of ways of caging the animals is-

  1. 7P6. 5!    
  2. 6P4. 7!    
  3. 11C4. 7!    
  4. None of these    

Hint:

From the statement we can conclude that :There are 6 large animals and 5 small animals  also there are 7 large cages and 4 small cages. Arrange the animals accordingly.

The correct answer is: 7P6. 5!


    We have been given that eleven animals of a circus have to be placed in eleven cages, one in each cage. If four of the cages are too small for six of the animals

    From the above statement we can conclude that :There are 6 large animals and 5 small animals  also there are 7 large cages and 4 small cages.


    6 large animals can be caged in 7 large cages in P presuperscript 7 subscript 6 space end subscript equals space 7 factorial thin space ways.

    5 small animals can be caged in remaining 5 cages (4 small + 1 large) in 5! ways.

    Thus, the number of ways of caging the animals is = P presuperscript 7 subscript 6 space cross times space 5 factorial

     

     

     

     

     

     

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