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Maths-

General

Easy

Question

Given O is center of smaller Circle, BD is common chord, ABC, EDO are straight lines. If AED =130°, then C O D =

80°
160°
100°
110°

The correct answer is: 100°

Related Questions to study

In the figure x y z=

In the figure x y z=

From the figure $left floor P B R equals$

From the figure $left floor P B R equals$

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if $stack ∣ O A B with _ below$ = 35° then $left floor E B C equals$

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if $stack ∣ O A B with _ below$ = 35° then $left floor E B C equals$

parallel

About 2 to 5% of gypsum $left parenthesis C a S O subscript 4.2 H subscript 2 O right parenthesis$ is added to Portland cement. It is just to

About 2 to 5% of gypsum $left parenthesis C a S O subscript 4.2 H subscript 2 O right parenthesis$ is added to Portland cement. It is just to

chemistry-General

If $sec to the power of 4 space theta plus sec squared space theta equals 10 plus tan to the power of 4 space theta plus tan squared space theta text then end text sin squared text end text theta$ =

If $sec to the power of 4 space theta plus sec squared space theta equals 10 plus tan to the power of 4 space theta plus tan squared space theta text then end text sin squared text end text theta$ =

Osmosis is the phenomenon expressed by :

Osmosis is the phenomenon expressed by :

parallel

If $4 n alpha equals pi comma$ then the numerical value of $tan space alpha tan space 2 alpha tan space 3 alpha horizontal ellipsis horizontal ellipsis tan space left parenthesis 2 n minus 1 right parenthesis alpha$ is equal to

4 n minus alpha equals pi rightwards double arrow alpha equals fraction numerator pi over denominator 4 n end fraction n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha A s comma space left parenthesis 2 n minus 1 right parenthesis alpha equals 2 n alpha minus alpha equals pi over 2 minus alpha tan left parenthesis 2 n minus 1 right parenthesis alpha equals tan open parentheses pi over 2 minus alpha close parentheses equals c o t space alpha tan left parenthesis 2 n minus 2 right parenthesis alpha equals tan open parentheses pi over 2 minus 2 alpha close parentheses equals c o t space 2 alpha S o comma space n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha equals tan alpha. tan 2 alpha. tan 3 alpha.... c o t space 3 alpha. c o t 2 alpha. c o t alpha equals left parenthesis tan alpha. c o t alpha right parenthesis left parenthesis tan 2 alpha. c o t alpha right parenthesis left parenthesis tan 3 alpha. c o t 3 alpha right parenthesis...... equals 1.1.1.... equals 1

If $4 n alpha equals pi comma$ then the numerical value of $tan space alpha tan space 2 alpha tan space 3 alpha horizontal ellipsis horizontal ellipsis tan space left parenthesis 2 n minus 1 right parenthesis alpha$ is equal to

4 n minus alpha equals pi rightwards double arrow alpha equals fraction numerator pi over denominator 4 n end fraction n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha A s comma space left parenthesis 2 n minus 1 right parenthesis alpha equals 2 n alpha minus alpha equals pi over 2 minus alpha tan left parenthesis 2 n minus 1 right parenthesis alpha equals tan open parentheses pi over 2 minus alpha close parentheses equals c o t space alpha tan left parenthesis 2 n minus 2 right parenthesis alpha equals tan open parentheses pi over 2 minus 2 alpha close parentheses equals c o t space 2 alpha S o comma space n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha equals tan alpha. tan 2 alpha. tan 3 alpha.... c o t space 3 alpha. c o t 2 alpha. c o t alpha equals left parenthesis tan alpha. c o t alpha right parenthesis left parenthesis tan 2 alpha. c o t alpha right parenthesis left parenthesis tan 3 alpha. c o t 3 alpha right parenthesis...... equals 1.1.1.... equals 1

$3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator space$ =

3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator A s comma space tan space 30 degree equals fraction numerator 1 over denominator square root of 3 end fraction rightwards double arrow tan 3 left parenthesis 10 degree right parenthesis equals fraction numerator 1 over denominator square root of 3 end fraction space rightwards double arrow fraction numerator left parenthesis 3 tan 10 degree minus tan cubed 10 degree right parenthesis over denominator left parenthesis 1 minus 3 tan squared 10 degree right parenthesis end fraction equals fraction numerator 1 over denominator square root of 3 end fraction S q u a r i n g space b o t h space s i d e s comma space w e space g e t colon rightwards double arrow left parenthesis 3 tan 10 degree minus tan cubed 10 degree right parenthesis squared over left parenthesis 1 minus 3 tan squared 10 degree right parenthesis squared equals 1 third rightwards double arrow fraction numerator 9 tan squared 10 degree minus 6 tan to the power of 4 10 degree plus tan to the power of 6 10 degree over denominator 1 minus 6 tan squared 10 degree plus 9 tan to the power of 4 10 degree end fraction equals 1 third rightwards double arrow 27 tan squared 10 degree minus 18 tan to the power of 4 10 degree plus 3 tan to the power of 6 10 degree equals 1 minus 6 tan squared 10 degree plus 9 tan to the power of 4 10 degree rightwards double arrow 3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator equals 1

$3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator space$ =

3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator A s comma space tan space 30 degree equals fraction numerator 1 over denominator square root of 3 end fraction rightwards double arrow tan 3 left parenthesis 10 degree right parenthesis equals fraction numerator 1 over denominator square root of 3 end fraction space rightwards double arrow fraction numerator left parenthesis 3 tan 10 degree minus tan cubed 10 degree right parenthesis over denominator left parenthesis 1 minus 3 tan squared 10 degree right parenthesis end fraction equals fraction numerator 1 over denominator square root of 3 end fraction S q u a r i n g space b o t h space s i d e s comma space w e space g e t colon rightwards double arrow left parenthesis 3 tan 10 degree minus tan cubed 10 degree right parenthesis squared over left parenthesis 1 minus 3 tan squared 10 degree right parenthesis squared equals 1 third rightwards double arrow fraction numerator 9 tan squared 10 degree minus 6 tan to the power of 4 10 degree plus tan to the power of 6 10 degree over denominator 1 minus 6 tan squared 10 degree plus 9 tan to the power of 4 10 degree end fraction equals 1 third rightwards double arrow 27 tan squared 10 degree minus 18 tan to the power of 4 10 degree plus 3 tan to the power of 6 10 degree equals 1 minus 6 tan squared 10 degree plus 9 tan to the power of 4 10 degree rightwards double arrow 3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator equals 1

$sin space 20 to the power of ring operator open parentheses 4 plus sec space 20 to the power of ring operator close parentheses$ =

space space space space space sin space 20 to the power of ring operator open parentheses 4 plus sec space 20 to the power of ring operator close parentheses equals 4 sin space 20 degree plus fraction numerator sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 4 sin 20 degree. cos 20 degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 left parenthesis 2 sin space 20 degree. cos space 20 degree right parenthesis plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 sin space 40 degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 sin space left parenthesis 60 minus 20 right parenthesis degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 open parentheses sin space 60 degree cos space 20 degree minus cos space 60 degree sin space 20 degree close parentheses plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 open parentheses begin display style fraction numerator square root of 3 over denominator 2 end fraction end style cos space 20 degree minus begin display style 1 half end style sin space 20 degree close parentheses plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator square root of 3 cos space 20 degree minus sin space 20 degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator square root of 3 cos space 20 degree over denominator cos space 20 degree end fraction equals square root of 3

$sin space 20 to the power of ring operator open parentheses 4 plus sec space 20 to the power of ring operator close parentheses$ =

space space space space space sin space 20 to the power of ring operator open parentheses 4 plus sec space 20 to the power of ring operator close parentheses equals 4 sin space 20 degree plus fraction numerator sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 4 sin 20 degree. cos 20 degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 left parenthesis 2 sin space 20 degree. cos space 20 degree right parenthesis plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 sin space 40 degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 sin space left parenthesis 60 minus 20 right parenthesis degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 open parentheses sin space 60 degree cos space 20 degree minus cos space 60 degree sin space 20 degree close parentheses plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator 2 open parentheses begin display style fraction numerator square root of 3 over denominator 2 end fraction end style cos space 20 degree minus begin display style 1 half end style sin space 20 degree close parentheses plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator square root of 3 cos space 20 degree minus sin space 20 degree plus sin space 20 degree over denominator cos space 20 degree end fraction equals fraction numerator square root of 3 cos space 20 degree over denominator cos space 20 degree end fraction equals square root of 3

parallel

In the figure $P Q greater than P R comma$ QS and RS are the bisectors of $stack ∣ Q with _ below$ and $stack R with _ below$ respectively then

angle

angle

PQR [angle opposite to the longer side of triangle is greater]
=1/2

angle

angle

angle

angle

SQR [as QR is the bisector of

angle

PQR and RS is the bisector of

angle

PRQ]
= SQ>SR [as side opposite to greater angle is greatest]
So, SQ>SR

In the figure $P Q greater than P R comma$ QS and RS are the bisectors of $stack ∣ Q with _ below$ and $stack R with _ below$ respectively then

angle

angle

PQR [angle opposite to the longer side of triangle is greater]
=1/2

angle

angle

angle

angle

SQR [as QR is the bisector of

angle

PQR and RS is the bisector of

angle

PRQ]
= SQ>SR [as side opposite to greater angle is greatest]
So, SQ>SR

If AB=AC and $A C D equals 115 to the power of ring operator end exponent$ then $stack B with _ below A C equals$

If AB=AC and $A C D equals 115 to the power of ring operator end exponent$ then $stack B with _ below A C equals$

In the figure $A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent$ then ACD=

In the figure $A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent$ then ACD=

parallel

$open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses$ =

space space space open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses equals sin to the power of 8 open parentheses 90 minus 15 close parentheses degree minus cos to the power of 8 left parenthesis 90 minus 15 right parenthesis degree equals cos to the power of 8 15 degree minus sin to the power of 8 15 degree equals open parentheses cos to the power of 4 15 degree plus sin to the power of 4 15 degree close parentheses open parentheses cos to the power of 4 15 degree minus sin to the power of 4 15 degree close parentheses equals open parentheses open parentheses cos squared 15 degree plus sin squared 15 degree close parentheses squared minus 2 sin squared 15 degree. cos squared space 15 degree close parentheses open parentheses cos squared 15 degree plus sin squared 15 degree close parentheses open parentheses cos squared 15 degree minus sin squared 15 degree close parentheses equals open parentheses 1 minus open parentheses 2 sin space 15 degree. cos 15 degree close parentheses squared over 2 close parentheses 1 cross times cos open parentheses 2 cross times 15 close parentheses degree equals open parentheses 1 minus fraction numerator s i n squared 30 degree over denominator 2 end fraction close parentheses cos space 30 degree equals open parentheses 1 minus 1 over 8 close parentheses fraction numerator square root of 3 over denominator 2 end fraction equals 7 over 8. fraction numerator square root of 3 over denominator 2 end fraction equals fraction numerator 7 square root of 3 over denominator 16 end fraction

$open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses$ =

space space space open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses equals sin to the power of 8 open parentheses 90 minus 15 close parentheses degree minus cos to the power of 8 left parenthesis 90 minus 15 right parenthesis degree equals cos to the power of 8 15 degree minus sin to the power of 8 15 degree equals open parentheses cos to the power of 4 15 degree plus sin to the power of 4 15 degree close parentheses open parentheses cos to the power of 4 15 degree minus sin to the power of 4 15 degree close parentheses equals open parentheses open parentheses cos squared 15 degree plus sin squared 15 degree close parentheses squared minus 2 sin squared 15 degree. cos squared space 15 degree close parentheses open parentheses cos squared 15 degree plus sin squared 15 degree close parentheses open parentheses cos squared 15 degree minus sin squared 15 degree close parentheses equals open parentheses 1 minus open parentheses 2 sin space 15 degree. cos 15 degree close parentheses squared over 2 close parentheses 1 cross times cos open parentheses 2 cross times 15 close parentheses degree equals open parentheses 1 minus fraction numerator s i n squared 30 degree over denominator 2 end fraction close parentheses cos space 30 degree equals open parentheses 1 minus 1 over 8 close parentheses fraction numerator square root of 3 over denominator 2 end fraction equals 7 over 8. fraction numerator square root of 3 over denominator 2 end fraction equals fraction numerator 7 square root of 3 over denominator 16 end fraction

If $tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction$ and $tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root$ then $alpha plus beta$ =

tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma space tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction space a n d space tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root space space space space tan space left parenthesis alpha plus beta right parenthesis equals fraction numerator tan space alpha plus tan space beta over denominator 1 minus tan space alpha. tan space beta end fraction equals fraction numerator fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction plus fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction over denominator 1 minus fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction. fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction end fraction equals fraction numerator square root of x squared plus x plus 1 end root plus x square root of x squared plus x plus 1 end root over denominator square root of x left parenthesis x squared plus x plus 1 right parenthesis minus square root of x end fraction equals fraction numerator open parentheses x plus 1 close parentheses square root of x squared plus x plus 1 end root over denominator square root of x open parentheses x squared plus x plus 1 minus 1 close parentheses end fraction equals fraction numerator left parenthesis x plus 1 right parenthesis square root of x squared plus x plus 1 end root over denominator x square root of x open parentheses x plus 1 close parentheses end fraction equals fraction numerator square root of x squared plus x plus 1 end root over denominator square root of x cubed end root end fraction equals square root of fraction numerator x squared plus x plus 1 over denominator x cubed end fraction end root equals square root of 1 over x plus 1 over x squared plus 1 over x cubed end root equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root equals tan space gamma A s comma space tan space left parenthesis alpha plus beta right parenthesis equals tan space gamma rightwards double arrow alpha plus beta equals gamma

If $tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction$ and $tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root$ then $alpha plus beta$ =

tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma space tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction space a n d space tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root space space space space tan space left parenthesis alpha plus beta right parenthesis equals fraction numerator tan space alpha plus tan space beta over denominator 1 minus tan space alpha. tan space beta end fraction equals fraction numerator fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction plus fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction over denominator 1 minus fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction. fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction end fraction equals fraction numerator square root of x squared plus x plus 1 end root plus x square root of x squared plus x plus 1 end root over denominator square root of x left parenthesis x squared plus x plus 1 right parenthesis minus square root of x end fraction equals fraction numerator open parentheses x plus 1 close parentheses square root of x squared plus x plus 1 end root over denominator square root of x open parentheses x squared plus x plus 1 minus 1 close parentheses end fraction equals fraction numerator left parenthesis x plus 1 right parenthesis square root of x squared plus x plus 1 end root over denominator x square root of x open parentheses x plus 1 close parentheses end fraction equals fraction numerator square root of x squared plus x plus 1 end root over denominator square root of x cubed end root end fraction equals square root of fraction numerator x squared plus x plus 1 over denominator x cubed end fraction end root equals square root of 1 over x plus 1 over x squared plus 1 over x cubed end root equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root equals tan space gamma A s comma space tan space left parenthesis alpha plus beta right parenthesis equals tan space gamma rightwards double arrow alpha plus beta equals gamma

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi sin space theta right parenthesis comma 0 less than theta less than fraction numerator 3 pi over denominator 4 end fraction$ then $sin space open parentheses theta plus pi over 4 close parentheses equals$

space space space space tan left parenthesis pi space cos space ϑ right parenthesis equals c o t space left parenthesis pi space sin space ϑ right parenthesis rightwards double arrow tan left parenthesis pi space cos space ϑ right parenthesis equals tan space open parentheses pi over 2 minus pi space sin space ϑ close parentheses rightwards double arrow pi space cos space ϑ equals pi over 2 minus pi space sin space ϑ rightwards double arrow cos space ϑ equals 1 half minus sin space ϑ rightwards double arrow cos space ϑ plus sin space ϑ equals 1 half M u l t i p l y i n g space b o t h space t h e space s i d e s space w i t h space fraction numerator 1 over denominator square root of 2 end fraction comma space w e space g e t colon rightwards double arrow fraction numerator 1 over denominator square root of 2 end fraction cos space ϑ plus fraction numerator 1 over denominator square root of 2 end fraction sin space ϑ equals fraction numerator 1 over denominator 2 square root of 2 end fraction rightwards double arrow sin space pi over 4 cos space ϑ plus cos space pi over 4 sin space ϑ equals fraction numerator 1 over denominator 2 square root of 2 end fraction rightwards double arrow sin open parentheses ϑ plus pi over 4 close parentheses equals fraction numerator 1 over denominator 2 square root of 2 end fraction

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi sin space theta right parenthesis comma 0 less than theta less than fraction numerator 3 pi over denominator 4 end fraction$ then $sin space open parentheses theta plus pi over 4 close parentheses equals$

space space space space tan left parenthesis pi space cos space ϑ right parenthesis equals c o t space left parenthesis pi space sin space ϑ right parenthesis rightwards double arrow tan left parenthesis pi space cos space ϑ right parenthesis equals tan space open parentheses pi over 2 minus pi space sin space ϑ close parentheses rightwards double arrow pi space cos space ϑ equals pi over 2 minus pi space sin space ϑ rightwards double arrow cos space ϑ equals 1 half minus sin space ϑ rightwards double arrow cos space ϑ plus sin space ϑ equals 1 half M u l t i p l y i n g space b o t h space t h e space s i d e s space w i t h space fraction numerator 1 over denominator square root of 2 end fraction comma space w e space g e t colon rightwards double arrow fraction numerator 1 over denominator square root of 2 end fraction cos space ϑ plus fraction numerator 1 over denominator square root of 2 end fraction sin space ϑ equals fraction numerator 1 over denominator 2 square root of 2 end fraction rightwards double arrow sin space pi over 4 cos space ϑ plus cos space pi over 4 sin space ϑ equals fraction numerator 1 over denominator 2 square root of 2 end fraction rightwards double arrow sin open parentheses ϑ plus pi over 4 close parentheses equals fraction numerator 1 over denominator 2 square root of 2 end fraction

parallel

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