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Easy

Question

# If A is symmetric matrix and B is a skew- symmetric matrix, then for n N, false statement is -

- A
^{n} is symmetric
- A
^{n} is symmetric only when n is even
- B
^{n} is skew symmetric when n is odd
- B
^{n} is symmetric when n is even

^{n}is symmetric^{n}is symmetric only when n is even^{n}is skew symmetric when n is odd^{n}is symmetric when n is even## The correct answer is: A^{n} is symmetric only when n is even

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