Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If f : R → R is continuous and differentiable function such that $not stretchy integral subscript negative 1 end subscript superscript x end superscript blank$ f(t) dt + f¢¢¢ (3) $not stretchy integral subscript x end subscript superscript 0 end superscript d t equals not stretchy integral subscript 1 end subscript superscript x end superscript blank$ t³
dt – f ¢ (1) $not stretchy integral subscript 0 end subscript superscript x end superscript blank$ t² dt + f ¢¢ (2) $not stretchy integral subscript x end subscript superscript 3 end superscript blank$ t. dt, then the value of f ¢ (4) is :

48 – 8 f ¢ (1) + f ¢¢ (2)
48 – 8 f ¢ (1) – f ¢¢ (2)
48 + 8 f ¢ (1) + f ¢¢ (2)
None of these.

The correct answer is: 48 – 8 f ¢ (1) – f ¢¢ (2)

Related Questions to study

Assertion : The refractive index of diamond is $square root of 6$ and that of liquid is $square root of 3$
If the light travels from diamond to the liquid, it will totally reflected when the angle of incidence is 30^o
Reason : $mu equals fraction numerator 1 over denominator sin invisible function application C end fraction$ where $mu$ is the refractive index of diamond with respect to liquid

Assertion : The refractive index of diamond is $square root of 6$ and that of liquid is $square root of 3$
If the light travels from diamond to the liquid, it will totally reflected when the angle of incidence is 30^o
Reason : $mu equals fraction numerator 1 over denominator sin invisible function application C end fraction$ where $mu$ is the refractive index of diamond with respect to liquid

physics-General

If f : [0, p] → R is continuous and $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) sin x dx = $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) cos x dx = 0, then the number of roots of f(x) in (0, p) is

If f : [0, p] → R is continuous and $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) sin x dx = $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) cos x dx = 0, then the number of roots of f(x) in (0, p) is

Assertion : Different colours travel with different speed in vacuum
Reason : Wavelength of light depends on refractive index of medium

Assertion : Different colours travel with different speed in vacuum
Reason : Wavelength of light depends on refractive index of medium

physics-General

parallel

The following substance can be used as a raw material for obtaining alcohol:

The following substance can be used as a raw material for obtaining alcohol:

chemistry-General

Etherates are

Etherates are complexes of ethers with Lewis acid

Etherates are

chemistry-General

Etherates are complexes of ethers with Lewis acid

$E t h y l space a l c o h o l space r e a c t s space w i t h space H C l space b u t space n o t space w i t h space H C N space b e c a u s e colon$

Weak base reacts with strong acid.

$E t h y l space a l c o h o l space r e a c t s space w i t h space H C l space b u t space n o t space w i t h space H C N space b e c a u s e colon$

chemistry-General

Weak base reacts with strong acid.

parallel

Lucas reagent produces cloudiness immediately with:

Reactivity order of towards Lucas reagent is, Tertiary>Secondary>Primary alcohol.

Lucas reagent produces cloudiness immediately with:

chemistry-General

Reactivity order of towards Lucas reagent is, Tertiary>Secondary>Primary alcohol.

The product is

The pinacol-pinacolone rearrangement involves dehydration of diols through the formation of carbocation intermediate which rearranges to more stable compound.

The product is

chemistry-General

The pinacol-pinacolone rearrangement involves dehydration of diols through the formation of carbocation intermediate which rearranges to more stable compound.

Alloys of which metal are light and strong and are used in the manufacture of aeroplane parts?

Alloys of which metal are light and strong and are used in the manufacture of aeroplane parts?

chemistry-General

parallel

The right order of the solubility of sulphates of alkaline earth metals in water is

The right order of the solubility of sulphates of alkaline earth metals in water is

chemistry-General

$A space g a s space r e a c t s space w i t h space C a O space a n d space n o t space w i t h space N a H C O subscript 3 space i s colon$

$A space g a s space r e a c t s space w i t h space C a O space a n d space n o t space w i t h space N a H C O subscript 3 space i s colon$

chemistry-General

If point O is the centre of a circle circumscribed about a triangle ABC. Then $Error converting from MathML to accessible text.$

If point O is the centre of a circle circumscribed about a triangle ABC. Then $Error converting from MathML to accessible text.$

parallel

Which pair of the following chlorides do not impart colour to the flame?

Which pair of the following chlorides do not impart colour to the flame?

chemistry-General

If for $A X equals B comma$ $B equals open square brackets table row cell 9 end cell row cell 52 end cell row cell 0 end cell end table close square brackets$ and $A to the power of negative 1 end exponent equals open square brackets table row 3 cell negative fraction numerator 1 over denominator 2 end fraction end cell cell negative fraction numerator 1 over denominator 2 end fraction end cell row cell negative 4 end cell cell rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow fraction numerator 3 over denominator 4 end fraction end cell cell fraction numerator 5 over denominator 4 end fraction end cell row 2 cell negative fraction numerator 1 over denominator 4 end fraction end cell cell negative fraction numerator 3 over denominator 4 end fraction end cell end table close square brackets$ ,then X is equal to

A X equals B rightwards double arrow A to the power of negative 1 end exponent. A X equals A to the power of negative 1 end exponent B rightwards double arrow X equals A to the power of negative 1 end exponent B equals open square brackets table row cell 1 end cell row cell 3 end cell row cell 5 end cell end table close square brackets

If for $A X equals B comma$ $B equals open square brackets table row cell 9 end cell row cell 52 end cell row cell 0 end cell end table close square brackets$ and $A to the power of negative 1 end exponent equals open square brackets table row 3 cell negative fraction numerator 1 over denominator 2 end fraction end cell cell negative fraction numerator 1 over denominator 2 end fraction end cell row cell negative 4 end cell cell rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow fraction numerator 3 over denominator 4 end fraction end cell cell fraction numerator 5 over denominator 4 end fraction end cell row 2 cell negative fraction numerator 1 over denominator 4 end fraction end cell cell negative fraction numerator 3 over denominator 4 end fraction end cell end table close square brackets$ ,then X is equal to

A X equals B rightwards double arrow A to the power of negative 1 end exponent. A X equals A to the power of negative 1 end exponent B rightwards double arrow X equals A to the power of negative 1 end exponent B equals open square brackets table row cell 1 end cell row cell 3 end cell row cell 5 end cell end table close square brackets

The metal ion, that plays an important role in muscle contraction, is

The metal ion, that plays an important role in muscle contraction, is

chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.