If f(x) is a polynomial of degree five with leading coefficient-Turito

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Maths-

General

Easy

Question

If f(x) is a polynomial of degree five with leading coefficient one such that f(1)=1²,f(2)=2²,f(3)=3²,f(4)=4²,f(5)=5² then

f(6)= 156
$\lim_{x \to \infty} (\frac{f (x)}{x^{5}})$
f(0) $<$ 0
f(0) $>$ 0

The correct answer is: f(6)= 156

$f left parenthesis x right parenthesis minus x to the power of 2 end exponent equals left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis left parenthesis x minus 4 right parenthesis left parenthesis x minus 5$

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