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Question

If the solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator 1 over denominator x c o s invisible function application y plus s i n invisible function application 2 y end fraction text end text text is end text text end text x equals c o s i n invisible function application y minus k left parenthesis 1 plus s i n invisible function application y right parenthesis comma text  then  end text k equals

  1. 1    
  2. 2    
  3. 3    
  4. 4    

The correct answer is: 2

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A curve passes through the point open parentheses 1 comma fraction numerator pi over denominator 6 end fraction close parentheses Let the slope of the curve at each point (x, y) be fraction numerator y over denominator x end fraction plus s e c invisible function application open parentheses fraction numerator y over denominator x end fraction close parentheses comma x greater than 0 Then the equation of the curve is

A curve passes through the point open parentheses 1 comma fraction numerator pi over denominator 6 end fraction close parentheses Let the slope of the curve at each point (x, y) be fraction numerator y over denominator x end fraction plus s e c invisible function application open parentheses fraction numerator y over denominator x end fraction close parentheses comma x greater than 0 Then the equation of the curve is

maths-General
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The solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator x plus y over denominator x end fraction fraction numerator d y over denominator d x end fraction equals fraction numerator x plus y over denominator x end fraction

The solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator x plus y over denominator x end fraction fraction numerator d y over denominator d x end fraction equals fraction numerator x plus y over denominator x end fraction

maths-General
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maths-

Statement-I : Integral curves denoted by the first order linear differential equation fraction numerator d y over denominator d x end fraction minus fraction numerator 1 over denominator x end fraction y equals negative x blankare family of parabolas passing through the origin.
Statement-II : Every differential equation geometrically represents a family of curve having some common property.

Statement-I : Integral curves denoted by the first order linear differential equation fraction numerator d y over denominator d x end fraction minus fraction numerator 1 over denominator x end fraction y equals negative x blankare family of parabolas passing through the origin.
Statement-II : Every differential equation geometrically represents a family of curve having some common property.

maths-General
parallel
General
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A function f(x) satisfying stretchy integral subscript 0 end subscript superscript 1 end superscript   f left parenthesis t x right parenthesis d t equals n f left parenthesis x right parenthesis comma text end textwhere x>0 , is

A function f(x) satisfying stretchy integral subscript 0 end subscript superscript 1 end superscript   f left parenthesis t x right parenthesis d t equals n f left parenthesis x right parenthesis comma text end textwhere x>0 , is

maths-General
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text If  end text y equals fraction numerator x over denominator l n invisible function application vertical line c x vertical line end fraction (where c is an arbitrary constant) is the general solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator y over denominator x end fraction plus phi open parentheses fraction numerator x over denominator y end fraction close parentheses text end textthen the function text end text phi open parentheses fraction numerator x over denominator y end fraction close parentheses text  is : end text

text If  end text y equals fraction numerator x over denominator l n invisible function application vertical line c x vertical line end fraction (where c is an arbitrary constant) is the general solution of the differential equation fraction numerator d y over denominator d x end fraction equals fraction numerator y over denominator x end fraction plus phi open parentheses fraction numerator x over denominator y end fraction close parentheses text end textthen the function text end text phi open parentheses fraction numerator x over denominator y end fraction close parentheses text  is : end text

maths-General
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A function y = f (x) satisfies the condition f '(x) sin x + f (x) cos x = 1, f (x) being bounded when x rightwards arrow 0. If I equals stretchy integral subscript 0 end subscript superscript there exists 2 end superscript   f left parenthesis x right parenthesis d x text  then end text

A function y = f (x) satisfies the condition f '(x) sin x + f (x) cos x = 1, f (x) being bounded when x rightwards arrow 0. If I equals stretchy integral subscript 0 end subscript superscript there exists 2 end superscript   f left parenthesis x right parenthesis d x text  then end text

Maths-General
parallel
General
maths-

Statement-I : In throwing of two dice, let the events A, B and C be 'the first dice shows an even number', 'the second dice shows an odd numbers' and 'both the dice show an odd numbers or both the dice show an even number’ respectively. Then text end text P left parenthesis A right parenthesis equals P left parenthesis B right parenthesis equals P left parenthesis C right parenthesis equals fraction numerator 1 over denominator 2 end fraction text end textand P left parenthesis A intersection B right parenthesis equals P left parenthesis B intersection C right parenthesis equals P left parenthesis C intersection A right parenthesis equals fraction numerator 1 over denominator 4 end fraction Therefore A, B and C are mutually independent events
Statement-II : Three events A, B and C are mutually independent if and only if P(A Ç B) = P(A) . P(B), P(B Ç C) = P(B) . P(C), P left parenthesis C intersection A right parenthesis equals P left parenthesis C right parenthesis= P(C) . P(A) and P left parenthesis A intersection B intersection C right parenthesis= P(A) . P(B) . P(C)

Statement-I : In throwing of two dice, let the events A, B and C be 'the first dice shows an even number', 'the second dice shows an odd numbers' and 'both the dice show an odd numbers or both the dice show an even number’ respectively. Then text end text P left parenthesis A right parenthesis equals P left parenthesis B right parenthesis equals P left parenthesis C right parenthesis equals fraction numerator 1 over denominator 2 end fraction text end textand P left parenthesis A intersection B right parenthesis equals P left parenthesis B intersection C right parenthesis equals P left parenthesis C intersection A right parenthesis equals fraction numerator 1 over denominator 4 end fraction Therefore A, B and C are mutually independent events
Statement-II : Three events A, B and C are mutually independent if and only if P(A Ç B) = P(A) . P(B), P(B Ç C) = P(B) . P(C), P left parenthesis C intersection A right parenthesis equals P left parenthesis C right parenthesis= P(C) . P(A) and P left parenthesis A intersection B intersection C right parenthesis= P(A) . P(B) . P(C)

maths-General
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The probability that 4th power of a positive integer ends in the digit 6 is:

The probability that 4th power of a positive integer ends in the digit 6 is:

maths-General
General
maths-

Let A, B, C be pairwise independent events with P(C)> 0 and P left parenthesis A intersection B intersection C right parenthesis equals 0. Then P open parentheses A to the power of c end exponent intersection B to the power of c end exponent C close parentheses text  is equal to: end text

Let A, B, C be pairwise independent events with P(C)> 0 and P left parenthesis A intersection B intersection C right parenthesis equals 0. Then P open parentheses A to the power of c end exponent intersection B to the power of c end exponent C close parentheses text  is equal to: end text

maths-General
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maths-

Let A and B be two events such that P left parenthesis stack A union B with bar on top right parenthesis equals fraction numerator 1 over denominator 6 end fraction comma P left parenthesis A intersection B right parenthesis equals fraction numerator 1 over denominator 4 end fraction and P left parenthesis stack A with bar on top right parenthesis equals fraction numerator 1 over denominator 4 end fraction comma text  where  end text stack A with bar on top stands for complement of event A. Then events A and B are-

Let A and B be two events such that P left parenthesis stack A union B with bar on top right parenthesis equals fraction numerator 1 over denominator 6 end fraction comma P left parenthesis A intersection B right parenthesis equals fraction numerator 1 over denominator 4 end fraction and P left parenthesis stack A with bar on top right parenthesis equals fraction numerator 1 over denominator 4 end fraction comma text  where  end text stack A with bar on top stands for complement of event A. Then events A and B are-

maths-General
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A random variable X has the probability distribution :

For the events E = {X is a prime number} and F = {X < 4}, the probability P left parenthesis E union F right parenthesis is-

A random variable X has the probability distribution :

For the events E = {X is a prime number} and F = {X < 4}, the probability P left parenthesis E union F right parenthesis is-

maths-General
General
maths-

A fair coin is tossed 3 times. Consider the events A : first toss is head ; B : second toss is head C : exactly two consecutive heads or exactly two consecutive tails
Statement - I A,B,C are independent events.
Statement - II A,B,C are pairwise independent.

A fair coin is tossed 3 times. Consider the events A : first toss is head ; B : second toss is head C : exactly two consecutive heads or exactly two consecutive tails
Statement - I A,B,C are independent events.
Statement - II A,B,C are pairwise independent.

maths-General
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maths-

An experiment resulting in sample space as S = {a, b, c, d, e, f} text  with  end text P left parenthesis A right parenthesis equals fraction numerator 1 over denominator 16 end fraction comma P left parenthesis B right parenthesis equals fraction numerator 1 over denominator 16 end fraction comma P left parenthesis C right parenthesis equals fraction numerator 2 over denominator 16 end fraction comma P left parenthesis D right parenthesis equals fraction numerator 3 over denominator 16 end fraction comma P left parenthesis e right parenthesis equals fraction numerator 4 over denominator 16 end fraction text  and  end text P left parenthesis f right parenthesis equals fraction numerator 5 over denominator 16 end fraction text  . end text Let three events A, B and C are defined as A = {a, c, e,}, B = {c, d, e, f} and C = {b, c, f}. text  If  end text P left parenthesis A divided by B right parenthesis equals p subscript 1 end subscript comma P left parenthesis B divided by C right parenthesis equals p subscript 2 end subscript comma P open parentheses C divided by A to the power of c end exponent close parentheses equals p subscript 3 end subscript text  and  end text P open parentheses A to the power of c end exponent divided by C close parentheses equals p subscript 4 end subscript then the correct order sequance is

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maths-General
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An ellipse is drawn with major and minor axes of lengths 10 and 8 respectively. Using one focus as centre, a circle is drawn that is tangent to the ellipse, with no part of the circle being outside the ellipse. The radius of the circle is

An ellipse is drawn with major and minor axes of lengths 10 and 8 respectively. Using one focus as centre, a circle is drawn that is tangent to the ellipse, with no part of the circle being outside the ellipse. The radius of the circle is

maths-General
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From a point P, perpendicular tangents PQ and PR are drawn to ellipse x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 4 Locus of circumcentre of triangle PQR is

From a point P, perpendicular tangents PQ and PR are drawn to ellipse x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 4 Locus of circumcentre of triangle PQR is

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