Maths-
General
Easy
Question
Let A =
be a matrix, then(determinant of A ) × (adjoint of inverse of A)is equal to-
- O3 × 3
- I3
The correct answer is: ![open square brackets table row cell negative 1 end cell 2 cell negative 3 end cell row cell negative 2 end cell 0 3 row 3 cell negative 3 end cell 1 end table close square brackets](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAGsAAABGCAYAAADLjWrkAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAo9ZE6ZAAAAs9JREFUeNrtnDFLA0EQhQ8RCSKCWFgKIiIWYisiYhNEgohgIRZiY20v/gexEETEwk4sLERsRCws7MRKbKzTWKSQIEKcJROMGoMmO3MzyXvwimwgmbvvbnbv7nFJUlaphqH0VJcH4NiHB1iABQEWYOnCGiFvk+8j/+4U+ZRcIL/x768a2Mmz5AvyK7lIfiLvkPs9wDombwj83w15hdzDn8fItzyWpq7JS+SuqrEJ8qWnNqjxf4PkB6NtrQBYP1U0CGqI/AhYXzXJrdCKBsjrPG/NA9anMuQ7XnhYuxuxqb0aLP3BacHqI5+Rswo7/j/bHepa5INoBmdWeT4IoIYNXzP1MLC2hjVKPiB3O7jILbYzrDB5n5A7HYAa50VG28I65zPLmsLF+jIfRB18R+OZvOYBltRzs0YXOtKa5gOpyA53NHLaq0EoxU4EWIAFARZgQYAFARZgQYAFARZgQYAFOYKlkevrJe8l5Qd7wfs8Jq1Y2UAzsDRyfVfkharPOR6TVqxsoOk2GDPXF54Z7dYY30nSC3oWWglWksTL9YUWm/2lRZ2msF2NZANNw4qZ63v51oYqCmN5xW1qJhtoFlbsXN97ne/elFZrzWYDxWA1m5+Lnet7V2i1f1Ez2UBzZ5ZUri//SxvMKLfBihrJBpqCJZnrC4uIuRrj2ZQWGLHPaFVY0rm+JT4QvusopaV7I9lAM7A0cn3XPLF3ckvc4otxacXKBpqBpZHrC5P7IbefcOtnv+qOiaRiZQPNXxRDgAVYEGBBgAVYEGBBgAVYEGBBgAVYkH9YGvk5y3VJvUtRBJZGfs5yXVLvUlRtgwWjrUWqLrewYufnPNTlDpZUfs5DXW5gSefnPNTl7sySys/V2vFa7/xr+Tkrdn7OQ12uV4MWXyosWZdbWLHzcx7qcgFLIz/noS4XsDTyc5brksxE4kauIwEWYEGABVg6kyMUabHyAQNPi+Yq0px/AAABi3RFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtZmVuY2VkIGNsb3NlPSJdIiBvcGVuPSJbIiBzZXBhcmF0b3JzPSJ8Ij48bXRhYmxlPjxtdHI+PG10ZD48bW8+LTwvbW8+PG1uPjE8L21uPjwvbXRkPjxtdGQ+PG1uPjI8L21uPjwvbXRkPjxtdGQ+PG1vPi08L21vPjxtbj4zPC9tbj48L210ZD48L210cj48bXRyPjxtdGQ+PG1vPi08L21vPjxtbj4yPC9tbj48L210ZD48bXRkPjxtbj4wPC9tbj48L210ZD48bXRkPjxtbj4zPC9tbj48L210ZD48L210cj48bXRyPjxtdGQ+PG1uPjM8L21uPjwvbXRkPjxtdGQ+PG1vPi08L21vPjxtbj4zPC9tbj48L210ZD48bXRkPjxtbj4xPC9tbj48L210ZD48L210cj48L210YWJsZT48L21mZW5jZWQ+PC9tYXRoPovbbeAAAAAASUVORK5CYII=)
|A| adj (A–1) = ?
A–1 adj (A–1) = |A–1| I3
A. A–1 adj (A–1) = |A–1| AI3
adj (A–1) = |A–1| A
|A| adj (A–1) = A
Here |A| = 13But |A| ≠ 0
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