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Maths-

General

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Question

If $open square brackets table row alpha beta row gamma cell negative alpha end cell end table close square brackets$ is square root of I₂, then $alpha comma beta$ and $gamma$ will satisfy the relation-

1 + $α^{2}$ + $β γ$ = 0
1 – $α^{2}$ + $β γ$ = 0
1 + $α^{2}$ – $β γ$ = 0
$α^{2}$ + $β γ$ = 1

The correct answer is: $alpha squared$ + $beta gamma$ = 1

$open square brackets table row alpha beta row gamma cell negative alpha end cell end table close square brackets to the power of 2 end exponent$ = $open square brackets table row 1 0 row 0 1 end table close square brackets$ $not stretchy rightwards double arrow open square brackets table attributes columnalign center center columnspacing 1em end attributes row alpha beta row gamma cell negative alpha end cell end table close square brackets open square brackets table row alpha beta row gamma cell negative alpha end cell end table close square brackets$ = $open square brackets table row 1 0 row 0 1 end table close square brackets$
$not stretchy rightwards double arrow open square brackets table row cell alpha squared plus beta gamma end cell 0 row 0 cell alpha squared plus beta gamma end cell end table close square brackets$ = $open square brackets table row 1 0 row 0 1 end table close square brackets$ $rightwards double arrow$ $alpha squared plus beta gamma$ = 1

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