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Question

Let f : (0, ¥) → R and F(x) = not stretchy integral subscript 0 end subscript superscript x end superscript blankt f (t) dt. If F (x2) = x4 + x5, then not stretchy sum subscript r equals 1 end subscript superscript 12 end superscript blankf(r2), is equal to

  1. 216    
  2. 219    
  3. 221    
  4. 223    

The correct answer is: 219

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