Maths-
General
Easy
Question
The eccentricity of the hyperbola with asymptotes 3x + 4y = 2 and 4x – 3y = 2 is
- 3
- 2
- 4
Hint:
The eccentricity of a hyperbola is always greater than 1. i.e. e > 1. The eccentricity of a hyperbola can be taken as the ratio of the distance of the point on the hyperbole, from the focus, and its distance from the directrix.
Eccentricity = Distance from Focus/Distance from Directrix
The correct answer is: 

We have been given two asymptotes i.e. 3x + 4y = 2 and 4x – 3y = 2
First find out their slopes

From above we can see that m1 and m2 are negative inverse of each other that means both are perpendicular to each other.
It is a rectangular hyperbola and it has fixed eccentricity.
Thus eccentricity = 
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