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Question

The equation of the tangent to the parabola y = (x – 3)2 parallel to the chord joining the points (3, 0) and (4, 1) is -

  1. 2x – 2y + 6 = 0    
  2. 2y – 2x + 6 = 0    
  3. 4y – 4x + 13 = 0    
  4. 4x + 4y = 13    

The correct answer is: 4y – 4x + 13 = 0


    y' = 2(x –1) = 1 gives the point open parentheses fraction numerator 7 over denominator 2 end fraction comma fraction numerator 1 over denominator 4 end fraction close parenthesesand the required tangent is y –fraction numerator 1 over denominator 4 end fraction = 1. open parentheses x – fraction numerator 7 over denominator 2 end fraction close parentheses or 4y – 4x + 13 = 0.

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