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# The equation of the tangent to the parabola y = (x – 3)^{2} parallel to the chord joining the points (3, 0) and (4, 1) is -

- 2x – 2y + 6 = 0
- 2y – 2x + 6 = 0
- 4y – 4x + 13 = 0
- 4x + 4y = 13

## The correct answer is: 4y – 4x + 13 = 0

### y' = 2(x –1) = 1 gives the point and the required tangent is y – = 1. or 4y – 4x + 13 = 0.

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