Question
The number of numbers can be formed by taking any 2 digits from digits 6,7,8,9 and 3 digits from 1, 2, 3, 4, 5 is -
- 5C3 × 4C2 × 3! × 2!
- 5P3 × 4P2 × 5!
- 5C3 × 4C2 × 5!
- 5C3 × 4C2 ×
Hint:
No repetition is allowed.
Number of ways of taking any 2 digits from digits 6,7,8,9 = 
similarly find out the rest.
The correct answer is: 5C3 × 4C2 × 5!
We have to form a 5digit number by taking any 2 digits from digits 6,7,8,9 and 3 digits from 1, 2, 3, 4, 5
Number of ways of taking any 2 digits from digits 6,7,8,9 =
Number of ways of taking any 3 digits from 1, 2, 3, 4, 5 = 
Number of ways of forming a 5 digit number = 5!
Thus, the number of numbers can be formed by taking any 2 digits from digits 6,7,8,9 and 3 digits from 1, 2, 3, 4, 5 is - 
5! .
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has outer radius 
and inner radius 
. The work required to take a unit mass from point 
on its axis to infinity is
and 
respectively are tied to the ends of a massless string, which passes over a light and frictionless pulley. The masses are initially at rest and the released. Then acceleration of the centre of mass of the system is
to 
terms, 
, then 
in 
is
