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The possible values of theta element of left parenthesis 0 comma pi right parenthesis such thatsin invisible function application theta plus sin invisible function application 4 theta plus sin invisible function application 7 theta equals 0  are :

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  1. pi over 4 comma fraction numerator 5 pi over denominator 2 end fraction comma pi over 2 comma fraction numerator 2 pi over denominator 3 end fraction comma fraction numerator 3 pi over denominator 4 end fraction comma fraction numerator 8 pi over denominator 9 end fraction
  2. fraction numerator 2 pi over denominator 9 end fraction comma pi over 4 comma pi over 2 comma fraction numerator 2 pi over denominator 3 end fraction comma fraction numerator 3 pi over denominator 4 end fraction comma fraction numerator 35 pi over denominator 6 end fraction
  3. fraction numerator 2 pi over denominator 9 end fraction comma pi over 4 comma fraction numerator 4 pi over denominator 9 end fraction comma pi over 2 comma fraction numerator 3 pi over denominator 4 end fraction comma fraction numerator 8 pi over denominator 9 end fraction
  4. fraction numerator 2 pi over denominator 9 end fraction comma pi over 4 comma pi over 2 comma fraction numerator 2 pi over denominator 3 end fraction comma fraction numerator 3 pi over denominator 4 end fraction comma fraction numerator 8 pi over denominator 9 end fraction

    Answer:The correct answer is: fraction numerator 2 pi over denominator 9 end fraction comma pi over 4 comma fraction numerator 4 pi over denominator 9 end fraction comma pi over 2 comma fraction numerator 3 pi over denominator 4 end fraction comma fraction numerator 8 pi over denominator 9 end fraction

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    The number of values of x in the interval [0, 3straight pi] satisfying the equation ,2 sin squared invisible function application x plus 5 sin invisible function application x minus 3 equals 0 is



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    maths-General


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    The number of solutions of the equation cos squared invisible function application open parentheses x plus pi over 6 close parentheses plus cos squared invisible function application x minus 2 cos invisible function application open parentheses x plus pi over 6 close parentheses cos invisible function application open parentheses pi over 6 close parentheses equals sin squared invisible function application pi over 6 in the interval left parenthesis negative pi divided by 2 comma pi divided by 2 right parenthesis is


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    maths-

    If 0 less or equal than x less than 2 pi, then the number of real values of x, which satisfy the equationcos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x plus cos invisible function application 4 x equals 0 is :

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    The number of solutions of tan x + sec x = 2 cos x in [0, 2straight pi], is

    The number of solutions of tan x + sec x = 2 cos x in [0, 2straight pi], is

    maths-General
    General
    maths-

    The number of distinct real roots of open vertical bar table attributes columnalign center center center columnspacing 1em end attributes row cell sin invisible function application x end cell cell cos invisible function application x end cell cell cos invisible function application x end cell row cell cos invisible function application x end cell cell sin invisible function application x end cell cell cos invisible function application x end cell row cell cos invisible function application x end cell cell cos invisible function application x end cell cell sin invisible function application x end cell end table close vertical bar equals 0 in the interval negative pi over 4 less or equal than x less or equal than pi over 4 is


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    maths-

    Over left square bracket negative pi comma pi right square bracket the solution of 2 sin squared invisible function application open parentheses x plus pi over 4 close parentheses plus square root of 3 cos invisible function application 2 x greater or equal than 0 is



    Over left square bracket negative pi comma pi right square bracket the solution of 2 sin squared invisible function application open parentheses x plus pi over 4 close parentheses plus square root of 3 cos invisible function application 2 x greater or equal than 0 is

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    maths-

    The number of integral values of k for which the equation 7 cos invisible function application x plus 5 sin invisible function application x equals 2 k plus 1 has a solution is

    The number of integral values of k for which the equation 7 cos invisible function application x plus 5 sin invisible function application x equals 2 k plus 1 has a solution is

    maths-General
    General
    maths-

    Solution to inequality cos 2x + 5 cos x + 3 ≥ 0 over left square bracket negative pi comma pi right square bracket is

    Solution to inequality cos 2x + 5 cos x + 3 ≥ 0 over left square bracket negative pi comma pi right square bracket is

    maths-General
    General
    maths-

    cos invisible function application left parenthesis alpha minus beta right parenthesis equals 1 text  and  end text cos invisible function application left parenthesis alpha plus beta right parenthesis equals 1 over c where alpha comma beta element of left square bracket negative pi comma pi right square bracket Pairs alpha comma beta which satisfy both the equations is/are


    cos invisible function application left parenthesis alpha minus beta right parenthesis equals 1 text  and  end text cos invisible function application left parenthesis alpha plus beta right parenthesis equals 1 over c where alpha comma beta element of left square bracket negative pi comma pi right square bracket Pairs alpha comma beta which satisfy both the equations is/are

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    General
    physics-

    A string of length L is fixed at one end and carries a mass M at the other end. The string makes 2 divided by pi revolutions per s e c o n d around the vertical axis through the fixed end as shown in figure, then tension in the string is

    T sin invisible function application theta equals M omega to the power of 2 end exponent R(i)
    T sin invisible function application theta equals M omega to the power of 2 end exponent L sin invisible function application theta(ii)
    From (i) and (ii)
    T equals M omega to the power of 2 end exponent L
    equals M blank 4 pi to the power of 2 end exponent n to the power of 2 end exponent L
    equals M blank 4 pi to the power of 2 end exponent open parentheses fraction numerator 2 over denominator pi end fraction close parentheses to the power of 2 end exponent L equals 16 blank M L

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    physics-General
    T sin invisible function application theta equals M omega to the power of 2 end exponent R(i)
    T sin invisible function application theta equals M omega to the power of 2 end exponent L sin invisible function application theta(ii)
    From (i) and (ii)
    T equals M omega to the power of 2 end exponent L
    equals M blank 4 pi to the power of 2 end exponent n to the power of 2 end exponent L
    equals M blank 4 pi to the power of 2 end exponent open parentheses fraction numerator 2 over denominator pi end fraction close parentheses to the power of 2 end exponent L equals 16 blank M L
    General
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    Let f left parenthesis x right parenthesis equals fraction numerator c o s e c to the power of 4 end exponent invisible function application x minus 2 c o s e c to the power of 2 end exponent invisible function application x plus 1 over denominator c o s e c invisible function application x left parenthesis c o s e c invisible function application x minus s i n invisible function application x right parenthesis plus fraction numerator s i n invisible function application x minus c o s invisible function application x over denominator sin invisible function application x end fraction plus c o t invisible function application x end fraction The sum of all the solutions of f (x) = 0 in [0, 100p] is

    table row cell table row blank cell f left parenthesis x right parenthesis equals fraction numerator open parentheses c o s e c to the power of 2 end exponent invisible function application x minus 1 close parentheses to the power of 2 end exponent over denominator open parentheses c o s e c to the power of 2 end exponent invisible function application x minus 1 close parentheses plus 1 minus c o t invisible function application x plus c o t invisible function application x end fraction end cell row blank cell text  defined for  end text R minus n pi comma n element of I end cell row blank cell f left parenthesis x right parenthesis equals fraction numerator left parenthesis c o t invisible function application x right parenthesis to the power of 4 end exponent over denominator 1 plus c o t to the power of 2 end exponent invisible function application x end fraction end cell row blank cell f left parenthesis x right parenthesis equals 0 rightwards double arrow c o t invisible function application x equals 0 rightwards double arrow x equals left parenthesis 2 n minus 1 right parenthesis fraction numerator pi over denominator 2 end fraction end cell row blank cell therefore x equals fraction numerator pi over denominator 2 end fraction comma fraction numerator 3 pi over denominator 2 end fraction comma fraction numerator 5 pi over denominator 2 end fraction comma horizontal ellipsis horizontal ellipsis comma fraction numerator 199 pi over denominator 2 end fraction end cell row blank cell s u m equals fraction numerator pi over denominator 2 end fraction left square bracket 1 plus 3 plus 5 plus horizontal ellipsis horizontal ellipsis plus 199 right square bracket end cell end table end cell row cell text end text text ( end text text 100 end text text end text text s end text text o end text text l end text text u end text text t end text text i end text text o end text text n end text text s end text text ) end text text end text end cell row cell equals fraction numerator pi over denominator 2 end fraction times fraction numerator 100 over denominator 2 end fraction times 200 equals 5000 pi end cell end table

    Let f left parenthesis x right parenthesis equals fraction numerator c o s e c to the power of 4 end exponent invisible function application x minus 2 c o s e c to the power of 2 end exponent invisible function application x plus 1 over denominator c o s e c invisible function application x left parenthesis c o s e c invisible function application x minus s i n invisible function application x right parenthesis plus fraction numerator s i n invisible function application x minus c o s invisible function application x over denominator sin invisible function application x end fraction plus c o t invisible function application x end fraction The sum of all the solutions of f (x) = 0 in [0, 100p] is

    maths-General
    table row cell table row blank cell f left parenthesis x right parenthesis equals fraction numerator open parentheses c o s e c to the power of 2 end exponent invisible function application x minus 1 close parentheses to the power of 2 end exponent over denominator open parentheses c o s e c to the power of 2 end exponent invisible function application x minus 1 close parentheses plus 1 minus c o t invisible function application x plus c o t invisible function application x end fraction end cell row blank cell text  defined for  end text R minus n pi comma n element of I end cell row blank cell f left parenthesis x right parenthesis equals fraction numerator left parenthesis c o t invisible function application x right parenthesis to the power of 4 end exponent over denominator 1 plus c o t to the power of 2 end exponent invisible function application x end fraction end cell row blank cell f left parenthesis x right parenthesis equals 0 rightwards double arrow c o t invisible function application x equals 0 rightwards double arrow x equals left parenthesis 2 n minus 1 right parenthesis fraction numerator pi over denominator 2 end fraction end cell row blank cell therefore x equals fraction numerator pi over denominator 2 end fraction comma fraction numerator 3 pi over denominator 2 end fraction comma fraction numerator 5 pi over denominator 2 end fraction comma horizontal ellipsis horizontal ellipsis comma fraction numerator 199 pi over denominator 2 end fraction end cell row blank cell s u m equals fraction numerator pi over denominator 2 end fraction left square bracket 1 plus 3 plus 5 plus horizontal ellipsis horizontal ellipsis plus 199 right square bracket end cell end table end cell row cell text end text text ( end text text 100 end text text end text text s end text text o end text text l end text text u end text text t end text text i end text text o end text text n end text text s end text text ) end text text end text end cell row cell equals fraction numerator pi over denominator 2 end fraction times fraction numerator 100 over denominator 2 end fraction times 200 equals 5000 pi end cell end table
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    The higher frequency TV broad casting bands range is

    The higher frequency TV broad casting bands range is

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    Frequency ranges for micro waves are :

    Frequency ranges for micro waves are :

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    The frequency band used for radar relay systems & T.V is

    The frequency band used for radar relay systems & T.V is

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    For TV transmission the frequency range employed

    For TV transmission the frequency range employed

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