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Maths-

General

Easy

Question

The number of values of x in the interval [0, 3 $straight pi$ ] satisfying the equation , $2 sin squared invisible function application x plus 5 sin invisible function application x minus 3 equals 0$ is

6
1
2
4

The correct answer is: 4

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The number of solutions of tan x + sec x = 2 cos x in [0, 2 $straight pi$ ], is

The number of solutions of tan x + sec x = 2 cos x in [0, 2 $straight pi$ ], is

Over $left square bracket negative pi comma pi right square bracket$ the solution of $2 sin squared invisible function application open parentheses x plus pi over 4 close parentheses plus square root of 3 cos invisible function application 2 x greater or equal than 0$ is

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Solution to inequality cos 2x + 5 cos x + 3 ≥ 0 over $left square bracket negative pi comma pi right square bracket$ is

Solution to inequality cos 2x + 5 cos x + 3 ≥ 0 over $left square bracket negative pi comma pi right square bracket$ is

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Let $f left parenthesis x right parenthesis equals fraction numerator c o s e c to the power of 4 end exponent invisible function application x minus 2 c o s e c to the power of 2 end exponent invisible function application x plus 1 over denominator c o s e c invisible function application x left parenthesis c o s e c invisible function application x minus s i n invisible function application x right parenthesis plus fraction numerator s i n invisible function application x minus c o s invisible function application x over denominator sin invisible function application x end fraction plus c o t invisible function application x end fraction$ The sum of all the solutions of f (x) = 0 in [0, 100p] is

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The general solution of the trigonometric equation tan x + tan 2x + tan 3x = tan x · tan 2x tan 3x is
where n $element of$ I

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The sum of all the solution of cotθ= sin 2θ(θ ≠ n $straight pi$ , n integer), 0 , $less or equal than theta less or equal than pi$ is

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$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 1 plus x right parenthesis to the power of 1 fifth end exponent minus left parenthesis 1 minus x right parenthesis to the power of 1 half end exponent over denominator x end fraction$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 1 plus x right parenthesis to the power of 1 fifth end exponent minus left parenthesis 1 minus x right parenthesis to the power of 1 half end exponent over denominator x end fraction$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin space open parentheses pi cos squared space x close parentheses over denominator x squared end fraction$

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$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of x minus e cubed over denominator x not stretchy rightwards arrow 0 end fraction$

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$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of 3 x end exponent minus e cubed over denominator x end fraction$

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$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application fraction numerator e to the power of 7 x end exponent minus 1 over denominator 7 x end fraction$

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