The value of 'c' in lagrange's mean value theorem for f(x)=x(x--Turito

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The value of 'c' in Lagrange's mean value theorem for $f space left parenthesis x right parenthesis equals x space left parenthesis x minus 2 right parenthesis squared$ in [0, 2] is

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2
0
3/2
2/3

Answer:The correct answer is: 2/3

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The equation $r equals a c o s space theta plus b s i n space theta$ represents

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The value of 'c' in Lagrange's mean value theorem for $f space left parenthesis x right parenthesis equals x cubed minus 2 x squared minus x plus 4$ in [0, 1] is

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The polar equation of the circle whose end points of the diameter are $open parentheses square root of 2 comma fraction numerator pi over denominator 4 end fraction close parentheses$ and $open parentheses square root of 2 comma fraction numerator 3 pi over denominator 4 end fraction close parentheses$ is

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The adjoining figure shows the graph of $y equals a x to the power of 2 end exponent plus b x plus c$ Then –

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The foot of the perpendicular from the point $left parenthesis 3 , 3 pi divided by 4 right parenthesis$ on the line $r left parenthesis c o s space theta minus s i n space theta right parenthesis equals 6 square root of 2$ is

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The point of intersection of the lines $2 c o s space theta plus s i n space theta equals 1 over r comma c o s space theta plus s i n space theta equals 1 over r$ is

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The line passing through $open parentheses negative 1 comma fraction numerator pi over denominator 2 end fraction close parentheses$ and perpendicular to $square root of 3 s i n space theta plus 2 c o s space theta equals 4 over r$ is

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The equation of the line passing through $left parenthesis negative 1 comma pi divided by 6 right parenthesis comma left parenthesis 1 comma pi divided by 2 right parenthesis$ is

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The value of 'c' in Lagrange's mean value theorem for in [0, 2] is

2 0 3/2 2/3

Answer:The correct answer is: 2/3

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Related Questions to study

The equation represents

The equation represents

The value of 'c' in Lagrange's mean value theorem for in [0, 1] is

The value of 'c' in Lagrange's mean value theorem for in [0, 1] is

The polar equation of the circle whose end points of the diameter are and is

The polar equation of the circle whose end points of the diameter are and is

The radius of the circle is

The radius of the circle is

The adjoining figure shows the graph of Then –

The adjoining figure shows the graph of Then –

Graph of y = ax2 + bx + c = 0 is given adjacently. What conclusions can be drawn from this graph –

Graph of y = ax2 + bx + c = 0 is given adjacently. What conclusions can be drawn from this graph –

For the quadratic polynomial f (x) = 4x2 – 8kx + k, the statements which hold good are

For the quadratic polynomial f (x) = 4x2 – 8kx + k, the statements which hold good are

The graph of the quadratic polynomial y = ax2 + bx + c is as shown in the figure. Then :

The graph of the quadratic polynomial y = ax2 + bx + c is as shown in the figure. Then :

The greatest possible number of points of intersections of 8 straight line and 4 circles is :

The greatest possible number of points of intersections of 8 straight line and 4 circles is :

How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even position ?

How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even position ?

A person predicts the outcome of 20 cricket matches of his home team. Each match can result either in a win, loss or tie for the home team. Total number of ways in which he can make the predictions so that exactly 10 predictions are correct, is equal to :

A person predicts the outcome of 20 cricket matches of his home team. Each match can result either in a win, loss or tie for the home team. Total number of ways in which he can make the predictions so that exactly 10 predictions are correct, is equal to :

The foot of the perpendicular from the point on the line is

The foot of the perpendicular from the point on the line is

The point of intersection of the lines is

The point of intersection of the lines is

The line passing through and perpendicular to is

The line passing through and perpendicular to is

The equation of the line passing through is

The equation of the line passing through is

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The value of 'c' in Lagrange's mean value theorem for $f space left parenthesis x right parenthesis equals x space left parenthesis x minus 2 right parenthesis squared$ in [0, 2] is

2
0
3/2
2/3

The equation $r equals a c o s space theta plus b s i n space theta$ represents

The equation $r equals a c o s space theta plus b s i n space theta$ represents

The value of 'c' in Lagrange's mean value theorem for $f space left parenthesis x right parenthesis equals x cubed minus 2 x squared minus x plus 4$ in [0, 1] is

The value of 'c' in Lagrange's mean value theorem for $f space left parenthesis x right parenthesis equals x cubed minus 2 x squared minus x plus 4$ in [0, 1] is

The radius of the circle $r equals 8 s i n space theta plus 6 c o s space theta$ is

The radius of the circle $r equals 8 s i n space theta plus 6 c o s space theta$ is

The adjoining figure shows the graph of $y equals a x to the power of 2 end exponent plus b x plus c$ Then –

The adjoining figure shows the graph of $y equals a x to the power of 2 end exponent plus b x plus c$ Then –

Graph of y = ax² + bx + c = 0 is given adjacently. What conclusions can be drawn from this graph –

Graph of y = ax² + bx + c = 0 is given adjacently. What conclusions can be drawn from this graph –

For the quadratic polynomial f (x) = 4x² – 8kx + k, the statements which hold good are

For the quadratic polynomial f (x) = 4x² – 8kx + k, the statements which hold good are

The graph of the quadratic polynomial y = ax² + bx + c is as shown in the figure. Then :

The graph of the quadratic polynomial y = ax² + bx + c is as shown in the figure. Then :

The foot of the perpendicular from the point $left parenthesis 3 , 3 pi divided by 4 right parenthesis$ on the line $r left parenthesis c o s space theta minus s i n space theta right parenthesis equals 6 square root of 2$ is

The foot of the perpendicular from the point $left parenthesis 3 , 3 pi divided by 4 right parenthesis$ on the line $r left parenthesis c o s space theta minus s i n space theta right parenthesis equals 6 square root of 2$ is

The point of intersection of the lines $2 c o s space theta plus s i n space theta equals 1 over r comma c o s space theta plus s i n space theta equals 1 over r$ is

The point of intersection of the lines $2 c o s space theta plus s i n space theta equals 1 over r comma c o s space theta plus s i n space theta equals 1 over r$ is

The line passing through $open parentheses negative 1 comma fraction numerator pi over denominator 2 end fraction close parentheses$ and perpendicular to $square root of 3 s i n space theta plus 2 c o s space theta equals 4 over r$ is

The line passing through $open parentheses negative 1 comma fraction numerator pi over denominator 2 end fraction close parentheses$ and perpendicular to $square root of 3 s i n space theta plus 2 c o s space theta equals 4 over r$ is

The equation of the line passing through $left parenthesis negative 1 comma pi divided by 6 right parenthesis comma left parenthesis 1 comma pi divided by 2 right parenthesis$ is

The equation of the line passing through $left parenthesis negative 1 comma pi divided by 6 right parenthesis comma left parenthesis 1 comma pi divided by 2 right parenthesis$ is