Maths-
General
Easy

Question

The point of intersection of the lines 2 c o s space theta plus s i n space theta equals 1 over r comma c o s space theta plus s i n space theta equals 1 over r is

  1. open parentheses 1 comma fraction numerator pi over denominator 4 end fraction close parentheses    
  2. open parentheses 1 comma fraction numerator pi over denominator 2 end fraction close parentheses    
  3. open parentheses 2 comma fraction numerator pi over denominator 4 end fraction close parentheses    
  4. open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses    

The correct answer is: open parentheses 1 comma fraction numerator pi over denominator 2 end fraction close parentheses

Related Questions to study

General
Maths-

The line passing through open parentheses negative 1 comma fraction numerator pi over denominator 2 end fraction close parentheses and perpendicular to square root of 3 s i n space theta plus 2 c o s space theta equals 4 over r is

The line passing through open parentheses negative 1 comma fraction numerator pi over denominator 2 end fraction close parentheses and perpendicular to square root of 3 s i n space theta plus 2 c o s space theta equals 4 over r is

Maths-General
General
Maths-

The equation of the line passing through left parenthesis negative 1 comma pi divided by 6 right parenthesis comma left parenthesis 1 comma pi divided by 2 right parenthesis is

The equation of the line passing through left parenthesis negative 1 comma pi divided by 6 right parenthesis comma left parenthesis 1 comma pi divided by 2 right parenthesis is

Maths-General
General
Maths-

The length of the perpendicular from (-1, π/6) to the line r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3 is

The length of the perpendicular from (-1, π/6) to the line r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3 is

Maths-General
parallel
General
Maths-

The sum of all the numbers that can be formed with the digits 2, 3, 4, 5 taken all at a time is (repetition is not allowed) :

Alternatively, we can use the formula for the sum of numbers as
(n - 1)! cross times (sum of digits) cross times (11111 ............ntimes). We can also solve this problem by writing all the possible numbers and finding the sum of them which will be time taking and make us confused. We should know that the value of the digits is determined by the place where they were present. We should check whether there is zero in the given digits and whether there are any repetitions present in the numbers. Similarly, we can expect problems to find the sum of numbers formed by these digits with repetition allowed.

The sum of all the numbers that can be formed with the digits 2, 3, 4, 5 taken all at a time is (repetition is not allowed) :

Maths-General

Alternatively, we can use the formula for the sum of numbers as
(n - 1)! cross times (sum of digits) cross times (11111 ............ntimes). We can also solve this problem by writing all the possible numbers and finding the sum of them which will be time taking and make us confused. We should know that the value of the digits is determined by the place where they were present. We should check whether there is zero in the given digits and whether there are any repetitions present in the numbers. Similarly, we can expect problems to find the sum of numbers formed by these digits with repetition allowed.

General
Maths-

Total number of divisors of 480, that are of the form 4n + 2, n greater or equal than 0, is equal to :

We can also solve this question by writing 4n + 2 = 2(2n + 1) where 2n + 1 is always an odd number. So, when all odd divisors will be multiplied by 2, we will get the divisors that we require. Hence, we can say a number of divisors of 4n + 2 form is the same as the number of odd divisors for 480.

Total number of divisors of 480, that are of the form 4n + 2, n greater or equal than 0, is equal to :

Maths-General

We can also solve this question by writing 4n + 2 = 2(2n + 1) where 2n + 1 is always an odd number. So, when all odd divisors will be multiplied by 2, we will get the divisors that we require. Hence, we can say a number of divisors of 4n + 2 form is the same as the number of odd divisors for 480.

General
Maths-

If 9P5 + 5 9P4 = 10Pr , then r =

If 9P5 + 5 9P4 = 10Pr , then r =

Maths-General
parallel
General
Maths-

The number of proper divisors of 2 to the power of p. 6 to the power of q. 15r is-

The number of proper divisors of 2 to the power of p. 6 to the power of q. 15r is-

Maths-General
General
Maths-

Ifx squared minus 11 x plus a text  and  end text x squared minus 14 x plus 2 a have a common factor then 'a' is equal to

Ifx squared minus 11 x plus a text  and  end text x squared minus 14 x plus 2 a have a common factor then 'a' is equal to

Maths-General
General
physics-

A block C of mass is moving with velocity and collides elastically with block of mass  and connected to another block of mass  through spring constant .What is  if  is compression of spring when velocity of  is same ?

A block C of mass is moving with velocity and collides elastically with block of mass  and connected to another block of mass  through spring constant .What is  if  is compression of spring when velocity of  is same ?

physics-General
parallel
General
Maths-

If fraction numerator 1 over denominator left parenthesis 1 plus 2 x right parenthesis open parentheses 1 minus x squared close parentheses end fraction equals fraction numerator A over denominator 1 plus 2 x end fraction plus fraction numerator B over denominator 1 plus x end fraction plus fraction numerator C over denominator 1 minus x end fraction then ascending order of A, B, C.

If fraction numerator 1 over denominator left parenthesis 1 plus 2 x right parenthesis open parentheses 1 minus x squared close parentheses end fraction equals fraction numerator A over denominator 1 plus 2 x end fraction plus fraction numerator B over denominator 1 plus x end fraction plus fraction numerator C over denominator 1 minus x end fraction then ascending order of A, B, C.

Maths-General
General
Maths-

The number of different seven digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is-

We know that there is not much difference between permutation and combination. Permutation is the way or method of arranging numbers from a given set of numbers such that the order of arrangement matters. Whereas combination is the way of selecting items from a given set of items where order of selection doesn’t matter. Both the word combination and permutation is the way of arrangement. Here, we will not use permutation because the order of toys is not necessary.

The number of different seven digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is-

Maths-General

We know that there is not much difference between permutation and combination. Permutation is the way or method of arranging numbers from a given set of numbers such that the order of arrangement matters. Whereas combination is the way of selecting items from a given set of items where order of selection doesn’t matter. Both the word combination and permutation is the way of arrangement. Here, we will not use permutation because the order of toys is not necessary.

General
Maths-

The centre and radius of the circle r equals c o s space theta minus s i n space theta are respectively

The centre and radius of the circle r equals c o s space theta minus s i n space theta are respectively

Maths-General
parallel
General
maths-

The centre of the circle r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24 is

The centre of the circle r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24 is

maths-General
General
maths-

The equation of the circle with centre at open parentheses 1 comma 0 to the power of 0 end exponent close parentheses, which passes through the point open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses is

The equation of the circle with centre at open parentheses 1 comma 0 to the power of 0 end exponent close parentheses, which passes through the point open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses is

maths-General
General
maths-

The foot of the perpendicular from left parenthesis negative 1 comma pi divided by 6 right parenthesis on the line r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3 is

The foot of the perpendicular from left parenthesis negative 1 comma pi divided by 6 right parenthesis on the line r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3 is

maths-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.