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The point of intersection of the lines 2 c o s space theta plus s i n space theta equals 1 over r comma c o s space theta plus s i n space theta equals 1 over r is

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  1. open parentheses 2 comma fraction numerator pi over denominator 4 end fraction close parentheses    
  2. open parentheses 1 comma fraction numerator pi over denominator 2 end fraction close parentheses    
  3. open parentheses 1 comma fraction numerator pi over denominator 4 end fraction close parentheses    
  4. open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses    

    Answer:The correct answer is: open parentheses 1 comma fraction numerator pi over denominator 2 end fraction close parentheses

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    The line passing through open parentheses negative 1 comma fraction numerator pi over denominator 2 end fraction close parentheses and perpendicular to square root of 3 s i n space theta plus 2 c o s space theta equals 4 over r is

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