Maths-
General
Easy
Question
Number of ways in which 5 different toys can be distributed among 5 children if exactly one child do not get any toy
- 1100
- 1200
- 1300
- 240
The correct answer is: 1200
5 toys has to be distributed among 4 children after one of them is excluded. Which means one of them will get 2 toys.
So this can be done is
= 10 × 3 × 2 × 4 = 240
Now one child can be rejected is 
= 5 ways
Total ways = 5 × 240 = 1200
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