Maths-

#### Number of ways in which 5 different toys can be distributed among 5 children if exactly one child do not get any toy

Maths-General

- 1300
- 1200
- 240
- 1100

#### Answer:The correct answer is: 12005 toys has to be distributed among 4 children after one of them is excluded. Which means one of them will get 2 toys.

So this can be done is

= 10 × 3 × 2 × 4 = 240

Now one child can be rejected is = 5 ways

Total ways = 5 × 240 = 1200

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Cases : i) If d = 6 then seven digit numbers possible are =

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no. of ways =

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