Chemistry-

General

Easy

### Question

Oxygen atom of ether is:

- Very active
- Replaceable
- Active
- Comparatively inert

#### The correct answer is: Comparatively inert

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### Related Questions to study

physics-

#### A long current carrying wire, carrying current such that it is flowing out from the plane of paper, is placed at O A steady state current is flowing in the loop ABCD

#### A long current carrying wire, carrying current such that it is flowing out from the plane of paper, is placed at O A steady state current is flowing in the loop ABCD

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#### A loop carrying current I lies in the x-y plane as shown in fig The unit vector $\widehat{k}$ is coming out of the plane of the paper The magnetic moment of the current loop is

#### A loop carrying current I lies in the x-y plane as shown in fig The unit vector $\widehat{k}$ is coming out of the plane of the paper The magnetic moment of the current loop is

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#### A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance $h$ below the highest point such that

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physics-General

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#### In figure, a particle is placed at the highest point $A$ of a smooth sphere of radius $r$. It is given slight push, and it leaves the sphere at $B$, at a depth $h$vertically below $A$ such that $h$ is equal to

If $v$ velocity acquired at $B$, then
${v}^{2}=2gh$
The particle will leave the sphere at $B$, when
$\frac{m{v}^{2}}{r}\ge mg\mathrm{cos}\theta $
$\frac{2gh}{r}=\frac{g(r-h)}{r},$
Which gives $h=\frac{r}{3}$

#### In figure, a particle is placed at the highest point $A$ of a smooth sphere of radius $r$. It is given slight push, and it leaves the sphere at $B$, at a depth $h$vertically below $A$ such that $h$ is equal to

physics-General

If $v$ velocity acquired at $B$, then
${v}^{2}=2gh$
The particle will leave the sphere at $B$, when
$\frac{m{v}^{2}}{r}\ge mg\mathrm{cos}\theta $
$\frac{2gh}{r}=\frac{g(r-h)}{r},$
Which gives $h=\frac{r}{3}$

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#### $C-O-C$ angle would be maximum in

#### $C-O-C$ angle would be maximum in

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#### A circular loop of radius 20cm is placed in a uniform magnetic field $\overrightarrow{B}=2T\text{in}X-Y$plane the loop carries a current 1A in the direction shown in figure The magnitude of torque acting on the loop is nearly

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#### Two 1ong wires are placed parallel to each other 10cm apart as shown in fig The magnetic field at piont P is

#### Two 1ong wires are placed parallel to each other 10cm apart as shown in fig The magnetic field at piont P is

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#### A proton accelerated by a pd V=500 KV moves through a transverse magnetic field B=0.51 T as shown in figure Then the angle q through which the proton deviates from the initial direction of its motion is (approximately)

#### A proton accelerated by a pd V=500 KV moves through a transverse magnetic field B=0.51 T as shown in figure Then the angle q through which the proton deviates from the initial direction of its motion is (approximately)

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#### A particle of mass m and charge q, moving with velocity V enters Region II normal to the boundary as shown in fig Region II has a uniform magnetic field B perpendicular to the plane of the paper The length of the Region II is $l$ Then

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#### A small sphere is hung by a string fixed to a wall. The sphere is pushed away from the wall by a stick. The force acting on the sphere are shown in figure. Which of the following statements is wrong?

Here $W=T$($cos\theta +sin\theta $)$<T$
so $P+Q=T$($cos\theta +sin\theta $)$<T$
Whereas [a], [b] and [c] are correct and [d] is wrong.

#### A small sphere is hung by a string fixed to a wall. The sphere is pushed away from the wall by a stick. The force acting on the sphere are shown in figure. Which of the following statements is wrong?

physics-General

Here $W=T$($cos\theta +sin\theta $)$<T$
so $P+Q=T$($cos\theta +sin\theta $)$<T$
Whereas [a], [b] and [c] are correct and [d] is wrong.

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#### Let f : (0, ¥) → R and F(x) = ${\int}_{0}^{x}$t f (t) dt. If F (x^{2}) = x^{4} + x^{5}, then ${\sum}_{r=1}^{12}$f(r^{2}), is equal to

#### Let f : (0, ¥) → R and F(x) = ${\int}_{0}^{x}$t f (t) dt. If F (x^{2}) = x^{4} + x^{5}, then ${\sum}_{r=1}^{12}$f(r^{2}), is equal to

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Maths-

Maths-General