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Maths-General
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physics-
In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volt and has no ingternal resistance)

In the given circuit, resistors 4R and 2R are connected in parallel while resistance R is connected in series to it.
Hence, equivalent resistance is






Given, emf is E volts, therefore


Potential difference across R is

Potential difference across 2R is

Hence, equivalent resistance is

Given, emf is E volts, therefore

Potential difference across R is
Potential difference across 2R is
In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volt and has no ingternal resistance)

physics-General
In the given circuit, resistors 4R and 2R are connected in parallel while resistance R is connected in series to it.
Hence, equivalent resistance is






Given, emf is E volts, therefore


Potential difference across R is

Potential difference across 2R is

Hence, equivalent resistance is

Given, emf is E volts, therefore

Potential difference across R is
Potential difference across 2R is
physics-
In the adjoining figure the equivalent resistance between A and B is

Equivalent circuit of the given circuit is
Between points C and D resistors 2
, 2
and 2
are in series, therefore, their equivalent resistance,

Resistors R’ and 6
are in parallel, therefore their equivalent resistance is given by


Now between points A and B 1
, 3
and 1
are in series.
Therefore, resultant resistance is
R=1+3+1=5
Between points C and D resistors 2
Resistors R’ and 6
Now between points A and B 1
Therefore, resultant resistance is
R=1+3+1=5
In the adjoining figure the equivalent resistance between A and B is

physics-General
Equivalent circuit of the given circuit is
Between points C and D resistors 2
, 2
and 2
are in series, therefore, their equivalent resistance,

Resistors R’ and 6
are in parallel, therefore their equivalent resistance is given by


Now between points A and B 1
, 3
and 1
are in series.
Therefore, resultant resistance is
R=1+3+1=5
Between points C and D resistors 2
Resistors R’ and 6
Now between points A and B 1
Therefore, resultant resistance is
R=1+3+1=5
maths-
Period ofÂ
 is
Period ofÂ
 is
maths-General
physics-
The charge on the capacitor of capacitance
shown in the figure below will be

The charge on the capacitor of capacitance
shown in the figure below will be

physics-General
physics-
Each resistance shown in figure is 2
. The equivalent resistance between A and B is

Given circuit is a balanced Wheatstone bridge. So, diagonal resistance of 2
will be ineffective.

Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4


Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4
Each resistance shown in figure is 2
. The equivalent resistance between A and B is

physics-General
Given circuit is a balanced Wheatstone bridge. So, diagonal resistance of 2
will be ineffective.

Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4


Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4
physics-
The equivalent resistance across A and B is

The equivalent circuit can be redrawn as

we have,

So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance



we have,
So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance
The equivalent resistance across A and B is

physics-General
The equivalent circuit can be redrawn as

we have,

So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance



we have,
So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance
physics-
Figures i) and ii) below show the displacement-time graphs of two particles moving along the
-axis. We can say that

Figures i) and ii) below show the displacement-time graphs of two particles moving along the
-axis. We can say that

physics-General
physics-
The graph of displacement
time is

Its corresponding velocity-time graph will be
We know that the velocity of body is given by the slope of displacement
time graph so it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and it will become negative
The graph of displacement
time is

Its corresponding velocity-time graph will be
physics-General
We know that the velocity of body is given by the slope of displacement
time graph so it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and it will become negative
physics-
A particle starts from rest at
and moves in a straight line with an acceleration as shown below. The velocity of the particle at
is

Velocity of graph
Area of
-
graph

A particle starts from rest at
and moves in a straight line with an acceleration as shown below. The velocity of the particle at
is

physics-General
Velocity of graph
Area of
-
graph

maths-
Period ofÂ
 is
Period ofÂ
 is
maths-General
physics-
There resistances of 4
each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

The equivalent circuit is given by

4
and 2
resistances are in series on both sides.

Then 6
and6
resistances are in parallel on both sides

R=3

4
Then 6
R=3
There resistances of 4
each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

physics-General
The equivalent circuit is given by

4
and 2
resistances are in series on both sides.

Then 6
and6
resistances are in parallel on both sides

R=3

4
Then 6
R=3
physics-
The equivalent resistance between the points A and B will be (each resistance is
15
)

The circuit can be shown as given below

The equivalent resistance between D and C.



Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B






The equivalent resistance between D and C.
Now, between A and B, the resistance of upper part ADCB,
Between A and B, the resistance of middle part AOB
Therefore, equivalent resistance between A and B
The equivalent resistance between the points A and B will be (each resistance is
15
)

physics-General
The circuit can be shown as given below

The equivalent resistance between D and C.



Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B






The equivalent resistance between D and C.
Now, between A and B, the resistance of upper part ADCB,
Between A and B, the resistance of middle part AOB
Therefore, equivalent resistance between A and B
physics-
A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6
Now, R’ and 3
are in parallel,

Now, V=IR


∴ R’=3+3=6
Now, R’ and 3
Now, V=IR
A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

physics-General
Resistance in the arms AC and BC are in series,

∴ R’=3+3=6
Now, R’ and 3
are in parallel,

Now, V=IR


∴ R’=3+3=6
Now, R’ and 3
Now, V=IR
physics-
A current of 2A flows in an electric circuit as shown in figure. The potential difference
, in volts(
are potentials at R and S respectively) is

Current through each arm
PRQ and PSQ=1A


From Eqs. (i) and (ii), we get

PRQ and PSQ=1A
From Eqs. (i) and (ii), we get
A current of 2A flows in an electric circuit as shown in figure. The potential difference
, in volts(
are potentials at R and S respectively) is

physics-General
Current through each arm
PRQ and PSQ=1A


From Eqs. (i) and (ii), we get

PRQ and PSQ=1A
From Eqs. (i) and (ii), we get
physics-
The total current supplied to the given circuit by the battery is

The equivalent circuit of the given circuit is as shown

Resistances 6
and 2
are in parallel

Resistances

Resistances 3
and 3
are in parallel

The current,


Resistances 6
Resistances
Resistances 3
The current,
The total current supplied to the given circuit by the battery is

physics-General
The equivalent circuit of the given circuit is as shown

Resistances 6
and 2
are in parallel

Resistances

Resistances 3
and 3
are in parallel

The current,


Resistances 6
Resistances
Resistances 3
The current,