Physics-
General
Easy

Question

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at A is

  1. square root of g    
  2. 2 square root of g    
  3. 3 square root of g    
  4. 4 square root of g    

The correct answer is: square root of g


    fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals m g open parentheses 3 minus 1 close parentheses equals 2 m g or v equals square root of 4 g equals 2 square root of g
    Vertical component at A equals 2 square root of g sin invisible function application 30 degree equals square root of g

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