Physics-
General
Easy

Question

A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration 'a' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration ' a ' vertically downward. The tension in the string is equal to :

  1. m square root of g to the power of 2 end exponent plus a to the power of 2 end exponent end root    
  2. m square root of g to the power of 2 end exponent plus a to the power of 2 end exponent end root minus m a    
  3. m square root of g to the power of 2 end exponent plus a to the power of 2 end exponent end root plus m a    
  4. m (g + a)    

The correct answer is: m square root of g to the power of 2 end exponent plus a to the power of 2 end exponent end root plus m a


    (Force diagram in the frame of the car) Applying Newton’s law perpendicular to string mg sinq = ma cos q
    tan invisible function application theta equals fraction numerator a over denominator g end fraction

    Applying Newton’s law along string
    rightwards double arrow T minus m square root of g to the power of 2 end exponent plus a to the power of 2 end exponent end root equals m a

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