A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2^nd mass after collision

The correct answer is:

Let mass moves with velocity and collides inelastically with mass which is at rest

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity
Initial horizontal momentum of system
(before collision) ….(i)
Final horizontal momentum of system
(after collision) ….(ii)
From the conservation of horizontal linear momentum
…(iii)
Initial vertical momentum of system (before collision) is zero
Final vertical momentum of system
From the conservation of vertical linear momentum
…(iv)
By solving (iii) and (iv)