General
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Physics-

The resultant of two forces, one double the other in magnitude, is perpendicular to the smaller of the two forces. The angle between the two forces is -

Physics-General

  1. 150 to the power of ring operator end exponent    
  2. 60 to the power of ring operator end exponent    
  3. 120 to the power of ring operator end exponent    
  4. 90 to the power of ring operator end exponent    

    Answer:The correct answer is: 120 to the power of ring operator end exponent

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    A block of mass 2kg is free to move along the x- axis. It is at rest and from t=0 onwards it is subjected to a time-dependent force F left parenthesis t right parenthesis in the x- direction. The force F left parenthesis t right parenthesis varies with t as shown in the figure. The kinetic energy of the block after 4.5 seconds is

    not stretchy integral F d t equals increment rho
    rightwards double arrow fraction numerator 1 over denominator 2 end fraction cross times 4 cross times 3 minus fraction numerator 1 over denominator 2 end fraction cross times 1.5 cross times 2 equals p subscript f end subscript minus 0 rightwards double arrow p subscript f end subscript equals 6 minus 1.5 equals fraction numerator 9 over denominator 2 end fraction
    K. E. equals fraction numerator p to the power of 2 end exponent over denominator 2 m end fraction equals fraction numerator 81 over denominator 4 cross times 2 cross times 2 end fraction semicolon K. E. blank equals 5.06 blank J

    A block of mass 2kg is free to move along the x- axis. It is at rest and from t=0 onwards it is subjected to a time-dependent force F left parenthesis t right parenthesis in the x- direction. The force F left parenthesis t right parenthesis varies with t as shown in the figure. The kinetic energy of the block after 4.5 seconds is

    physics-General
    not stretchy integral F d t equals increment rho
    rightwards double arrow fraction numerator 1 over denominator 2 end fraction cross times 4 cross times 3 minus fraction numerator 1 over denominator 2 end fraction cross times 1.5 cross times 2 equals p subscript f end subscript minus 0 rightwards double arrow p subscript f end subscript equals 6 minus 1.5 equals fraction numerator 9 over denominator 2 end fraction
    K. E. equals fraction numerator p to the power of 2 end exponent over denominator 2 m end fraction equals fraction numerator 81 over denominator 4 cross times 2 cross times 2 end fraction semicolon K. E. blank equals 5.06 blank J
    General
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    In the above figure acceleration (a) not stretchy rightwards arrow time (t) graph is given. Hence text  V  end text alpha horizontal ellipsis horizontal ellipsis

    In the above figure acceleration (a) not stretchy rightwards arrow time (t) graph is given. Hence text  V  end text alpha horizontal ellipsis horizontal ellipsis

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    The graph of displacement (x) not stretchy rightwards arrow time (t) for an object is given in the figure. In which part of the graph the acceleration of the particle is positive ?

    The graph of displacement (x) not stretchy rightwards arrow time (t) for an object is given in the figure. In which part of the graph the acceleration of the particle is positive ?

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    In uniformly accelerated motion the slope of velocity - time graph gives ....

    In uniformly accelerated motion the slope of velocity - time graph gives ....

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    General
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    A toy car of mass 5 kg moves up a ramp under the influence of force F plotted against displacement x. The maximum height attained is given by

    Work done = Gain in potential energy
    Area under curve equals m g h
    rightwards double arrow fraction numerator 1 over denominator 2 end fraction blank cross times 11 cross times 100 equals 5 cross times 10 cross times h rightwards double arrow h equals 11 m

    A toy car of mass 5 kg moves up a ramp under the influence of force F plotted against displacement x. The maximum height attained is given by

    physics-General
    Work done = Gain in potential energy
    Area under curve equals m g h
    rightwards double arrow fraction numerator 1 over denominator 2 end fraction blank cross times 11 cross times 100 equals 5 cross times 10 cross times h rightwards double arrow h equals 11 m
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    A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity fraction numerator v over denominator square root of 3 end fraction in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision

    Let mass A moves with velocity v and collides inelastically with mass B comma which is at rest

    According to problem mass A moves in a perpendicular direction and let the mass B moves at angle theta with the horizontal with velocity v
    Initial horizontal momentum of system
    (before collision) equals m v ….(i)
    Final horizontal momentum of system
    (after collision) equals m V cos invisible function application theta ….(ii)
    From the conservation of horizontal linear momentum
    m v equals m V cos invisible function application theta rightwards double arrow v equals V cos invisible function application theta …(iii)
    Initial vertical momentum of system (before collision) is zero
    Final vertical momentum of system fraction numerator m v over denominator square root of 3 end fraction minus m V sin invisible function application theta
    From the conservation of vertical linear momentum
    fraction numerator m v over denominator square root of 3 end fraction minus m V sin invisible function application theta equals 0 rightwards double arrow fraction numerator v over denominator square root of 3 end fraction equals V sin invisible function application theta …(iv)
    By solving (iii) and (iv)
    v to the power of 2 end exponent plus fraction numerator v to the power of 2 end exponent over denominator 3 end fraction equals V to the power of 2 end exponent left parenthesis sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta right parenthesis
    rightwards double arrow fraction numerator 4 v to the power of 2 end exponent over denominator 3 end fraction equals V to the power of 2 end exponent rightwards double arrow V equals fraction numerator 2 over denominator square root of 3 end fraction v

    A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity fraction numerator v over denominator square root of 3 end fraction in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision

    physics-General
    Let mass A moves with velocity v and collides inelastically with mass B comma which is at rest

    According to problem mass A moves in a perpendicular direction and let the mass B moves at angle theta with the horizontal with velocity v
    Initial horizontal momentum of system
    (before collision) equals m v ….(i)
    Final horizontal momentum of system
    (after collision) equals m V cos invisible function application theta ….(ii)
    From the conservation of horizontal linear momentum
    m v equals m V cos invisible function application theta rightwards double arrow v equals V cos invisible function application theta …(iii)
    Initial vertical momentum of system (before collision) is zero
    Final vertical momentum of system fraction numerator m v over denominator square root of 3 end fraction minus m V sin invisible function application theta
    From the conservation of vertical linear momentum
    fraction numerator m v over denominator square root of 3 end fraction minus m V sin invisible function application theta equals 0 rightwards double arrow fraction numerator v over denominator square root of 3 end fraction equals V sin invisible function application theta …(iv)
    By solving (iii) and (iv)
    v to the power of 2 end exponent plus fraction numerator v to the power of 2 end exponent over denominator 3 end fraction equals V to the power of 2 end exponent left parenthesis sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta right parenthesis
    rightwards double arrow fraction numerator 4 v to the power of 2 end exponent over denominator 3 end fraction equals V to the power of 2 end exponent rightwards double arrow V equals fraction numerator 2 over denominator square root of 3 end fraction v
    General
    physics-

    In a children’s park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenth of his weight. The work done by the slide on the boy as he comes down is

    F equals fraction numerator 3 over denominator 10 end fraction m g
    W equals negative F blank s blank o r blank W equals negative fraction numerator 3 over denominator 10 end fraction m g s
    or W equals negative fraction numerator 3 over denominator 10 end fraction cross times 200 cross times 10 blank J equals negative 600 blank J

    In a children’s park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenth of his weight. The work done by the slide on the boy as he comes down is

    physics-General
    F equals fraction numerator 3 over denominator 10 end fraction m g
    W equals negative F blank s blank o r blank W equals negative fraction numerator 3 over denominator 10 end fraction m g s
    or W equals negative fraction numerator 3 over denominator 10 end fraction cross times 200 cross times 10 blank J equals negative 600 blank J
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    The area covered by the curve of V-t graph and time axis is equal to magnitude of

    The area covered by the curve of V-t graph and time axis is equal to magnitude of

    physicsGeneral
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    The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collides is

    Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted KE.
    According to conservation of energy
    fraction numerator 1 over denominator 2 end fraction k L to the power of 2 end exponent equals fraction numerator 1 over denominator 2 end fraction M v to the power of 2 end exponent
    Or k L to the power of 2 end exponent equals fraction numerator open parentheses M v close parentheses to the power of 2 end exponent over denominator M end fraction
    M K L to the power of 2 end exponent equals p to the power of 2 end exponent left parenthesis p equals M v right parenthesis
    therefore p equals L square root of M K end root

    The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collides is

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    Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted KE.
    According to conservation of energy
    fraction numerator 1 over denominator 2 end fraction k L to the power of 2 end exponent equals fraction numerator 1 over denominator 2 end fraction M v to the power of 2 end exponent
    Or k L to the power of 2 end exponent equals fraction numerator open parentheses M v close parentheses to the power of 2 end exponent over denominator M end fraction
    M K L to the power of 2 end exponent equals p to the power of 2 end exponent left parenthesis p equals M v right parenthesis
    therefore p equals L square root of M K end root
    General
    physics-

    What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of 10 blank c m (Take g equals 9.8 blank m divided by s to the power of 2 end exponent)

    v equals square root of 2 g h end root equals square root of 2 cross times 9.8 cross times 0.1 end root equals square root of 1.96 end root equals 1.4 blank m divided by s

    What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of 10 blank c m (Take g equals 9.8 blank m divided by s to the power of 2 end exponent)

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    v equals square root of 2 g h end root equals square root of 2 cross times 9.8 cross times 0.1 end root equals square root of 1.96 end root equals 1.4 blank m divided by s
    General
    physics-

    A force F acting on an object varies with distance x as shown here. The force is in n e w t o n and xin m e t r e. The work done by the force in moving the object from x equals 0 to x equals 6 m is

    Work done = Area enclosed by F minus x graph
    equals fraction numerator 1 over denominator 2 end fraction blank cross times open parentheses 3 plus 6 close parentheses cross times 3 equals 13.5 blank J

    A force F acting on an object varies with distance x as shown here. The force is in n e w t o n and xin m e t r e. The work done by the force in moving the object from x equals 0 to x equals 6 m is

    physics-General
    Work done = Area enclosed by F minus x graph
    equals fraction numerator 1 over denominator 2 end fraction blank cross times open parentheses 3 plus 6 close parentheses cross times 3 equals 13.5 blank J
    General
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    Here is a velocity - time graph of a motorbike moving in one direction. Calculate the distance covered by it in last two seconds.

    Here is a velocity - time graph of a motorbike moving in one direction. Calculate the distance covered by it in last two seconds.

    physicsGeneral
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    Here are the graphs of velocity not stretchy rightwards arrow time of two cars A and B, Find the ratio of the acceleration. after time t.

    Here are the graphs of velocity not stretchy rightwards arrow time of two cars A and B, Find the ratio of the acceleration. after time t.

    physicsGeneral
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    The intercept of the velocity-time graph on the velocity axis gives.

    The intercept of the velocity-time graph on the velocity axis gives.

    physicsGeneral
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    Slope of the velocity-time graph gives …….. of a moving body

    Slope of the velocity-time graph gives …….. of a moving body

    physicsGeneral