Physics-
General
Easy
Question
A particle moves along the sides
of a square of side
wuth a velocity of
. Its average velocity is

The correct answer is: 
Average velocity =
Related Questions to study
physics-
The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in
are respectively

Displacement = Summation of all the area with sign



Distance = Summation of all the areas without sign



Distance = Summation of all the areas without sign
The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in
are respectively

physics-General
Displacement = Summation of all the area with sign



Distance = Summation of all the areas without sign



Distance = Summation of all the areas without sign
maths-
The area bounded by
, Y-axis and the line y=e is
The area bounded by
, Y-axis and the line y=e is
maths-General
maths-
If
then the general value of 'α ' is
If
then the general value of 'α ' is
maths-General
maths-
The parabolas
divide the square region bounded by the lines x=4, y=4 and the co-ordinate axes. If
are respectively the areas of these parts numbered from top to bottom then
is
The parabolas
divide the square region bounded by the lines x=4, y=4 and the co-ordinate axes. If
are respectively the areas of these parts numbered from top to bottom then
is
maths-General
physics-
The figure shows a double slit experiment P and Q are the slits. The path lengths PX and QX are
and
respectively, where n is a whole number and
is the wavelength. Taking the central fringe as zero, what is formed at X

For brightness, path difference 
So second is bright.
So second is bright.
The figure shows a double slit experiment P and Q are the slits. The path lengths PX and QX are
and
respectively, where n is a whole number and
is the wavelength. Taking the central fringe as zero, what is formed at X

physics-General
For brightness, path difference 
So second is bright.
So second is bright.
maths-
If
then
= ---
If
then
= ---
maths-General
physics-
A particle starts from rest. Its acceleration
time
is as shown in the figure. The maximum speed of the particle will be

Area under acceleration-time graph gives the change in velocity. Hence,

Therefore, the correct option is [b].
Therefore, the correct option is [b].
A particle starts from rest. Its acceleration
time
is as shown in the figure. The maximum speed of the particle will be

physics-General
Area under acceleration-time graph gives the change in velocity. Hence,

Therefore, the correct option is [b].
Therefore, the correct option is [b].
physics-
In figure, one car at rest and velocity of the light from head light is
, tehn velocity of light from head light for the moving car at velocity
, would be
Since
(negligible)
In figure, one car at rest and velocity of the light from head light is
, tehn velocity of light from head light for the moving car at velocity
, would be
physics-General
Since
(negligible)
maths-
If α and β are two different solutions lying between
and of the equation
then Tan α + Tan β is
If α and β are two different solutions lying between
and of the equation
then Tan α + Tan β is
maths-General
physics-
A particle of mass
is initially situated at the point
inside a hemispherical surface of radius
as shown in figure. A horizontal acceleration of magnitude
is suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, the time taken by particle to touch the sphere again is

Let the particle touches the sphere t the point 
Let

In


or



Let
In

or
A particle of mass
is initially situated at the point
inside a hemispherical surface of radius
as shown in figure. A horizontal acceleration of magnitude
is suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, the time taken by particle to touch the sphere again is

physics-General
Let the particle touches the sphere t the point 
Let

In


or



Let
In

or
physics-
A cyclist starts from the centre
of a circular park of radius 1 km, reaches the edge
of the park, then cycles along the circumference and returns to the point
as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

Since, the initial position of cyclist coincides with final position, so his net displacement is zero.




A cyclist starts from the centre
of a circular park of radius 1 km, reaches the edge
of the park, then cycles along the circumference and returns to the point
as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

physics-General
Since, the initial position of cyclist coincides with final position, so his net displacement is zero.




physics-
A the instant a motor bike starts from rest in a given direction, a car overtakes the motor bike, both moving in the same direction. The speed-time graphs for motor bike and car are represented by
and
respectively Then

Distance travelled by motor bike at
s
(18)(60)=540 m
Distance travelled by car at
s
=(18)(60)=720 m
Therefore, separation between them at
s is 180m. Let, separation between them decreases to zero at time
beyond 18s.
Hence,
and 


s beyond 18s or
Hence,
s=27s from start and distant travelled by both is
=
m
Distance travelled by car at
Therefore, separation between them at
Hence,
Hence,
A the instant a motor bike starts from rest in a given direction, a car overtakes the motor bike, both moving in the same direction. The speed-time graphs for motor bike and car are represented by
and
respectively Then

physics-General
Distance travelled by motor bike at
s
(18)(60)=540 m
Distance travelled by car at
s
=(18)(60)=720 m
Therefore, separation between them at
s is 180m. Let, separation between them decreases to zero at time
beyond 18s.
Hence,
and 


s beyond 18s or
Hence,
s=27s from start and distant travelled by both is
=
m
Distance travelled by car at
Therefore, separation between them at
Hence,
Hence,
physics-
Assertion : Owls can move freely during night.
Reason : They have large number of rods on their retina.
Owls can move freely during night, because they have large number of cones on their retina which help them to see in night.
Assertion : Owls can move freely during night.
Reason : They have large number of rods on their retina.
physics-General
Owls can move freely during night, because they have large number of cones on their retina which help them to see in night.
physics-
A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

Instantaneous velocity is given by the slope of the curve at that instant
from the figure it is clear that slope of the curve is maximum at point ‘
’
A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

physics-General
Instantaneous velocity is given by the slope of the curve at that instant
from the figure it is clear that slope of the curve is maximum at point ‘
’
Maths-
The area bounded by y=3x and
is
The area bounded by y=3x and
is
Maths-General