Physics-
General
Easy
Question
A particle starts from rest at 
and moves in a straight line with an acceleration as shown below. The velocity of the particle at 
is
The correct answer is:
Velocity of graph 
Area of
-
graph
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Period of 
is
Period of is
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Period of 
Period of
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In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volt and has no ingternal resistance)
In the given circuit, resistors 4R and 2R are connected in parallel while resistance R is connected in series to it.
Hence, equivalent resistance is
Given, emf is E volts, therefore
Potential difference across R is
Potential difference across 2R is
Hence, equivalent resistance is
Given, emf is E volts, therefore
Potential difference across R is
Potential difference across 2R is
In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volt and has no ingternal resistance)
physics-General
In the given circuit, resistors 4R and 2R are connected in parallel while resistance R is connected in series to it.
Hence, equivalent resistance is
Given, emf is E volts, therefore
Potential difference across R is
Potential difference across 2R is
Hence, equivalent resistance is
Given, emf is E volts, therefore
Potential difference across R is
Potential difference across 2R is
physics-
In the adjoining figure the equivalent resistance between A and B is
Equivalent circuit of the given circuit is
Between points C and D resistors 2
, 2 and 2 are in series, therefore, their equivalent resistance,
Resistors R’ and 6 are in parallel, therefore their equivalent resistance is given by
Now between points A and B 1, 3
and 1 are in series.
Therefore, resultant resistance is
R=1+3+1=5
Between points C and D resistors 2
, 2 and 2 are in series, therefore, their equivalent resistance,Resistors R’ and 6
are in parallel, therefore their equivalent resistance is given byNow between points A and B 1
, 3 and 1 are in series.Therefore, resultant resistance is
R=1+3+1=5
In the adjoining figure the equivalent resistance between A and B is
physics-General
Equivalent circuit of the given circuit is
Between points C and D resistors 2, 2 and 2 are in series, therefore, their equivalent resistance,
Resistors R’ and 6 are in parallel, therefore their equivalent resistance is given by
Now between points A and B 1, 3 and 1 are in series.
Therefore, resultant resistance is
R=1+3+1=5
Between points C and D resistors 2
, 2 and 2 are in series, therefore, their equivalent resistance,Resistors R’ and 6
are in parallel, therefore their equivalent resistance is given byNow between points A and B 1
, 3 and 1 are in series.Therefore, resultant resistance is
R=1+3+1=5
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The charge on the capacitor of capacitance 
shown in the figure below will be
The charge on the capacitor of capacitance shown in the figure below will be
physics-General
physics-
Each resistance shown in figure is 2. The equivalent resistance between A and B is
Given circuit is a balanced Wheatstone bridge. So, diagonal resistance of 2 will be ineffective.
Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4
will be ineffective.Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4
Each resistance shown in figure is 2. The equivalent resistance between A and B is
physics-General
Given circuit is a balanced Wheatstone bridge. So, diagonal resistance of 2 will be ineffective.
Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
=2+2=4
will be ineffective.Equivalent resistance of upper arms
=2+2=4
Equivalent resistance of lower arms
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The equivalent resistance across A and B is
The equivalent circuit can be redrawn as
we have,
So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance
we have,
So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance
The equivalent resistance across A and B is
physics-General
The equivalent circuit can be redrawn as
we have,
So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance
we have,
So, the given circuit is a balanced Wheatstone’s bridge.
Hence, the equivalent resistance
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Figures i) and ii) below show the displacement-time graphs of two particles moving along the 
-axis. We can say that
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The graph of displacement 
time is
Its corresponding velocity-time graph will be
We know that the velocity of body is given by the slope of displacement 
time graph so it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and it will become negative
time graph so it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and it will become negativeThe graph of displacement time is
Its corresponding velocity-time graph will be
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We know that the velocity of body is given by the slope of displacement time graph so it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and it will become negative
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Period of 
is
Period of is
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The current I drawn from the 5V source will be
The given circuit can be redrawn as
The current I drawn from the 5V source will be
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The given circuit can be redrawn as
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In the circuit given E=0.6V, 
=100,
. The equivalent resistance of the circuit, in ohm is
are in parallel order, so their equivalent resistance
In the circuit given E=0.6V, =100,. The equivalent resistance of the circuit, in ohm is
physics-General
are in parallel order, so their equivalent resistancephysics-
Six equal resistances are connected between points P, 
and R as shown in the figure. Then the net resistance will be maximum between
is maximum.Six equal resistances are connected between points P, and R as shown in the figure. Then the net resistance will be maximum between
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is maximum.physics-
In the circuit shown the equivalent resistance between A and B is
The three resistances between A and B are parallel,
In the circuit shown the equivalent resistance between A and B is
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The three resistances between A and B are parallel,
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In the circuit shown, the currents 
are
In the circuit shown, the currents are
physics-General