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Physics-

General

Easy

Question

A spherical ball of mass 15 kg stationary at the top of a hill of height 82 m. It slides down a smooth surface to the ground, then climbs up another hill of height 32 m and finally slides down to horizontal base at a height of 10 m above the ground. The velocity attained by the ball is

$30 \sqrt{10} m / s$
$10 \sqrt{30} m / s$
$12 \sqrt{10} m / s$
$10 \sqrt{12} m / s$

The correct answer is: $12 square root of 10 text end text m divided by s$

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