Physics-
General
Easy

Question

A wire left parenthesis Y equals 2 cross times 10 to the power of 11 end exponent N m to the power of negative 2 end exponent right parenthesis has length 1 m and cross-sectional area 1 m m to the power of negative 2 end exponent. The work required to increase the length by 2 mm is

  1. 0.4 J    
  2. 4 J    
  3. 40 J    
  4. 400 J    

The correct answer is: 0.4 J


    Work done = fraction numerator 1 over denominator 2 end fraction blank F increment l
    fraction numerator equals blank fraction numerator 1 over denominator 2 end fraction fraction numerator Y A increment l to the power of 2 end exponent over denominator l end fraction over denominator fraction numerator 2 cross times 10 to the power of 11 end exponent cross times 10 to the power of negative 6 end exponent open parentheses 2 cross times 10 to the power of negative 3 end exponent close parentheses to the power of 2 end exponent over denominator 2 cross times 1 end fraction end fraction open vertical bar table row cell Y equals fraction numerator F l over denominator A increment l end fraction end cell row cell o r blank F equals fraction numerator Y A increment l over denominator l end fraction end cell end table close
    = 4cross times 10 to the power of negative 1 end exponent blank J equals 0.4 blank J

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