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Question

An intense stream of water of cross-sectional area A strikes a wall at an angle theta with the normal to the wall and returns back elastically. If the density of water is rho and its velocity is v,then the force exerted in the wall will be

  1. 2 A v rho cos invisible function application theta    
  2. 2 A v to the power of 2 end exponent rho cos invisible function application theta    
  3. 2 A v to the power of 2 end exponent rho    
  4. 2 A v rho    

The correct answer is: 2 A v to the power of 2 end exponent rho cos invisible function application theta


    Linear momentum of water striking per second to the wall P subscript 1 end subscript equals m v equals A v rho blank v equals A v to the power of 2 end exponent blank rho, similarly linear momentum of reflected water per second P subscript r end subscript equals A v to the power of 2 end exponent rho

    Now making components of momentum along x- axes and y-axes. Change in momentum of water per second
    equals P subscript i end subscript cos invisible function application theta plus P subscript r end subscript cos invisible function application theta
    equals 2 A v to the power of 2 end exponent blank rho cos invisible function application theta
    By definition of force, force exerted on the Wall equals 2 A v to the power of 2 end exponent blank rho cos invisible function application theta

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