Physics-
General
Easy

Question

As shown in figure, the left block rests on a table at distance null = Normal reaction between A & B N subscript 2 end subscript = Normal reaction between B & C Which of the following statement(s) is/are correct ?

  1. If F subscript 1 end subscript > F subscript 2 end subscript then N subscript 1 end subscript ¹N subscript 2 end subscript and F2 < N subscript 1 end subscript N subscript 2 end subscript < F subscript 1 end subscript    
  2. If F subscript 1 end subscript < F subscript 2 end subscript then N subscript 1 end subscript > N subscript 1 end subscript    
  3. If F subscript 1 end subscript = F subscript 2 end subscript then N subscript 1 end subscript = N subscript 2 end subscript    
  4. If F subscript 1 end subscript= F subscript 2 end subscript then N subscript 1 end subscript ¹ N subscript 2 end subscript    

The correct answer is: If F subscript 1 end subscript > F subscript 2 end subscript then N subscript 1 end subscript ¹N subscript 2 end subscript and F2 < N subscript 1 end subscript N subscript 2 end subscript < F subscript 1 end subscript

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As shown in figure, the left block rests on a table at distance lambda  from the edge while the right block is kept at the same level so that thread is unstretched and does not sag and then released. What will happen first ?


As shown in figure, the left block rests on a table at distance lambda  from the edge while the right block is kept at the same level so that thread is unstretched and does not sag and then released. What will happen first ?


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If the string is pulled down with a force of 120 N as shown in the figure, then the acceleration of 8 kg block would

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With what acceleration ‘a’ shown the elevator descends so that the block of mass M exerts a force of fraction numerator M g over denominator 10 end fraction blankon the weighing machine? [g = acceleration due to gravity]

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An astronaut accidentally gets separated out of his small spaceship accelerating in inter-stellar space at a constant acceleration of 10 m/S to the power of 2 end exponent . What is the acceleration of the astronaut at the instant he is outside the spaceship ?

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An astronaut accidentally gets separated out of his small spaceship accelerating in inter-stellar space at a constant acceleration of 10 m/S to the power of 2 end exponent . What is the acceleration of the astronaut at the instant he is outside the spaceship ?

physics-General
When the astronaut is outside the spaceship, the net external force (except negligible gravitational force due to spaceship) is zero as he is isolated from all interactions.
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The two diodes A and B are biased as shown, then

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physics-General
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The value of current in the following diagram will be:

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The value of current in the adjoining diagram will be:

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A semiconductor P-N junction is to be forward biased with a battery of e.m.f. 1.5 Volt. If a potential difference of 0.5V appears on the junction which does not depend on current and on passing 10mA current through the junction there occurs huge Joule loss, then to use the junction at 5mA current, the resistance required to be connected in its series will be:

A semiconductor P-N junction is to be forward biased with a battery of e.m.f. 1.5 Volt. If a potential difference of 0.5V appears on the junction which does not depend on current and on passing 10mA current through the junction there occurs huge Joule loss, then to use the junction at 5mA current, the resistance required to be connected in its series will be:

physics-General
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maths-

  open parentheses lim for n not stretchy rightwards arrow straight infinity of   sum from r equals 1 to n of   open square brackets 1 over 2 to the power of r close square brackets close parentheses to the power of m(Where [ ] denotes GIF) is equal to

lim for n not stretchy rightwards arrow straight infinity of   open square brackets 1 half plus 1 over 2 squared plus midline horizontal ellipsis plus 1 over 2 to the power of n close square brackets equals lim for n not stretchy rightwards arrow straight infinity of   open square brackets fraction numerator 1 half open parentheses 1 minus 1 over 2 to the power of n close parentheses over denominator 1 minus 1 half end fraction close square brackets
equals lim for n not stretchy rightwards arrow straight infinity of   open square brackets 1 minus 1 over 2 to the power of n close square brackets equals 0 text  as  end text 1 over 2 to the power of n →∣ 0

  open parentheses lim for n not stretchy rightwards arrow straight infinity of   sum from r equals 1 to n of   open square brackets 1 over 2 to the power of r close square brackets close parentheses to the power of m(Where [ ] denotes GIF) is equal to

maths-General
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equals lim for n not stretchy rightwards arrow straight infinity of   open square brackets 1 minus 1 over 2 to the power of n close square brackets equals 0 text  as  end text 1 over 2 to the power of n →∣ 0
parallel
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Radius of largest circular path followed by the electrons
r equals fraction numerator m v over denominator e B end fraction equals fraction numerator 9.1 cross times 1 0 to the power of negative 31 end exponent cross times 7.036 cross times 1 0 to the power of 5 end exponent over denominator 1.6 cross times 1 0 to the power of negative 19 end exponent cross times 1 0 to the power of negative 4 end exponent end fraction = 0.04 m

In Find the maximum angle of deviation for a prism with angle A equals 60 to the power of ring operator end exponent and mu = 1.5, If a constant magnetic field of strength 10 to the power of negative 4 end exponentT is applied parallel to the metal surface, then the radius of the largest circular path followed by the electrons will be :

physics-General
Radius of largest circular path followed by the electrons
r equals fraction numerator m v over denominator e B end fraction equals fraction numerator 9.1 cross times 1 0 to the power of negative 31 end exponent cross times 7.036 cross times 1 0 to the power of 5 end exponent over denominator 1.6 cross times 1 0 to the power of negative 19 end exponent cross times 1 0 to the power of negative 4 end exponent end fraction = 0.04 m
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maths-

A quadratic equation f(x) = ax+ bx + c = 0 has positive distinct roots reciprocal of each other .Which one is correct ?

table row cell alpha plus fraction numerator 1 over denominator alpha end fraction greater than 2 rightwards double arrow fraction numerator negative b over denominator a end fraction greater than 2 rightwards double arrow fraction numerator 2 a plus b over denominator a end fraction less than 0 end cell row cell rightwards double arrow a left parenthesis 2 a plus b right parenthesis less than 0 rightwards double arrow a f to the power of ´ end exponent left parenthesis 1 right parenthesis less than 0 end cell end table

A quadratic equation f(x) = ax+ bx + c = 0 has positive distinct roots reciprocal of each other .Which one is correct ?

maths-General
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physics-

The sun deliverse 10 to the power of 3 end exponent W divided by m to the power of 2 end exponent of electromagnetic flux to the earth's surface. The total power that is incident on a roof of dimensions 8m ,20m, will be:

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Let P(4 cos alpha, 3 sin alpha) and Q (4 cos beta, 3 sin beta) be a focal chord of the ellipse passing through the focus at (square root of 7, 0).
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rightwards double arrowfraction numerator sin invisible function application left parenthesis alpha minus beta right parenthesis over denominator sin invisible function application alpha minus sin invisible function application beta end fraction=fraction numerator square root of 7 over denominator 4 end fraction
rightwards double arrowfraction numerator cos invisible function application left square bracket left parenthesis alpha minus beta right parenthesis divided by 2 right square bracket over denominator cos invisible function application left square bracket left parenthesis alpha plus beta right parenthesis divided by 2 right square bracket end fraction = fraction numerator square root of 7 over denominator 4 end fraction
rightwards double arrowtan open parentheses fraction numerator alpha over denominator 2 end fraction close parenthesestan open parentheses fraction numerator beta over denominator 2 end fraction close parentheses = fraction numerator square root of 7 minus 4 over denominator square root of 7 plus 4 end fraction= fraction numerator 23 minus 8 square root of 7 over denominator negative 9 end fraction.

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rightwards double arrowfraction numerator sin invisible function application left parenthesis alpha minus beta right parenthesis over denominator sin invisible function application alpha minus sin invisible function application beta end fraction=fraction numerator square root of 7 over denominator 4 end fraction
rightwards double arrowfraction numerator cos invisible function application left square bracket left parenthesis alpha minus beta right parenthesis divided by 2 right square bracket over denominator cos invisible function application left square bracket left parenthesis alpha plus beta right parenthesis divided by 2 right square bracket end fraction = fraction numerator square root of 7 over denominator 4 end fraction
rightwards double arrowtan open parentheses fraction numerator alpha over denominator 2 end fraction close parenthesestan open parentheses fraction numerator beta over denominator 2 end fraction close parentheses = fraction numerator square root of 7 minus 4 over denominator square root of 7 plus 4 end fraction= fraction numerator 23 minus 8 square root of 7 over denominator negative 9 end fraction.
General
maths-

If P(theta), Q open parentheses theta plus fraction numerator pi over denominator 2 end fraction close parentheses are points on ellipse and alpha is angle between normals at P and Q then -

If P(theta), Q open parentheses theta plus fraction numerator pi over denominator 2 end fraction close parentheses are points on ellipse and alpha is angle between normals at P and Q then -

maths-General
General
physics-

The Maxwell's four equations are written as:
i) not stretchy contour integral stack E with rightwards arrow on top. stack d s with rightwards arrow on top equals fraction numerator q subscript 0 end subscript over denominator epsilon subscript 0 end subscript end fraction
ii) not stretchy contour integral stack B with rightwards arrow on top. stack d s with rightwards arrow on top equals 0
iii) not stretchy contour integral stack E with rightwards arrow on top. stack d l with rightwards arrow on top equals fraction numerator d over denominator d t end fraction not stretchy contour integral stack B with rightwards arrow on top. stack d s with rightwards arrow on top
iv) not stretchy contour integral stack B with rightwards arrow on top. stack d s with rightwards arrow on top equals mu subscript 0 end subscript epsilon subscript 0 end subscript fraction numerator d over denominator d t end fraction not stretchy contour integral stack E with rightwards arrow on top. stack d s with rightwards arrow on top
The equations which have sources of stack E with rightwards arrow on top and stack B with rightwards arrow on top

The Maxwell's four equations are written as:
i) not stretchy contour integral stack E with rightwards arrow on top. stack d s with rightwards arrow on top equals fraction numerator q subscript 0 end subscript over denominator epsilon subscript 0 end subscript end fraction
ii) not stretchy contour integral stack B with rightwards arrow on top. stack d s with rightwards arrow on top equals 0
iii) not stretchy contour integral stack E with rightwards arrow on top. stack d l with rightwards arrow on top equals fraction numerator d over denominator d t end fraction not stretchy contour integral stack B with rightwards arrow on top. stack d s with rightwards arrow on top
iv) not stretchy contour integral stack B with rightwards arrow on top. stack d s with rightwards arrow on top equals mu subscript 0 end subscript epsilon subscript 0 end subscript fraction numerator d over denominator d t end fraction not stretchy contour integral stack E with rightwards arrow on top. stack d s with rightwards arrow on top
The equations which have sources of stack E with rightwards arrow on top and stack B with rightwards arrow on top

physics-General
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