Physics-
General
Easy

Question

Four capacitors are connected in a circuit as shown in the following figure. Calculate the effective capacitance between the points A a n d B.

  1. fraction numerator 4 over denominator 3 end fraction mu F    
  2. fraction numerator 24 over denominator 5 end fraction mu F    
  3. 9 blank mu F    
  4. 5 blank mu F    

The correct answer is: fraction numerator 4 over denominator 3 end fraction mu F


    Effective capacitance of C subscript 2 end subscript a n d blank C subscript 3 end subscript
    fraction numerator 1 over denominator C end fraction equals fraction numerator 1 over denominator 2 end fraction plus fraction numerator 1 over denominator 2 end fraction
    therefore blank C equals blank 1 mu blank F
    Now, C subscript 1 end subscript a n d blank C are in parallel, therefore effective capacitance C ´
    C to the power of ´ end exponent equals blank 1 plus 1 equals 2 mu blank F
    Now, C to the power of ´ end exponent a n d blank C subscript 4 end subscript are in series, therefore,
    effective capacitance between points A a n d blank B
    fraction numerator 1 over denominator C ´ ´ end fraction equals fraction numerator 1 over denominator 2 end fraction plus fraction numerator 1 over denominator 4 end fraction equals fraction numerator 3 over denominator 4 end fraction
    rightwards double arrow blank C to the power of ´ ´ end exponent equals fraction numerator 4 over denominator 3 end fraction mu F

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