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Physics-

General

Easy

Question

In the following diagram if $V subscript 2 end subscript greater than V subscript 1 end subscript$ then

$λ_{1} = \sqrt{λ_{2}}$
$λ_{1} < λ_{2}$
$λ_{1} = λ_{2}$
$λ_{1} > λ_{2}$

The correct answer is: $lambda subscript 1 end subscript greater than lambda subscript 2 end subscript$

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