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    General
    Easy
    Physics-

    In the given v minus t graph, the distance travelled by the body in 5 will be

    Physics-General

    1. 20 m    
    2. 80 m    
    3. 100 m    
    4. 40 m    

      Answer:The correct answer is: 100 mArea between v minus t graph and time-axis
      equals fraction numerator 1 over denominator 2 end fraction cross times 2 cross times 20 plus 3 cross times 20 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 20 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 20
      equals 100 m.

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      A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

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      Acceleration equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent

      A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

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      Maximum acceleration will be represented by C D part of the graph
      Acceleration equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent
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      A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after t subscript 1 end subscript and t subscript 2 end subscript seconds respectively, then

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      h equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent(i)
      if a stone is thrown upward with velocity u then
      h equals negative u blank t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript(ii)
      If a stone is thrown downward with velocity u then
      h equals u t subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 2 end subscript superscript 2 end superscript(iii)
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      negative u t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent(iv)
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      therefore fraction numerator negative u t subscript 1 end subscript over denominator u t subscript 2 end subscript end fraction equals fraction numerator fraction numerator 1 over denominator 2 end fraction g left parenthesis t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript right parenthesis over denominator fraction numerator 1 over denominator 2 end fraction g left parenthesis t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript right parenthesis end fraction
      Or negative fraction numerator t subscript 1 end subscript over denominator t subscript 2 end subscript end fraction equals fraction numerator t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript over denominator t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript end fraction
      By solvingblank t equals square root of t subscript 1 end subscript t subscript 2 end subscript end root

      A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after t subscript 1 end subscript and t subscript 2 end subscript seconds respectively, then

      physics-General
      If a stone is dropped from height h then
      h equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent(i)
      if a stone is thrown upward with velocity u then
      h equals negative u blank t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript(ii)
      If a stone is thrown downward with velocity u then
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      negative u t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent(iv)
      u t subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 2 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent(v)
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      Or negative fraction numerator t subscript 1 end subscript over denominator t subscript 2 end subscript end fraction equals fraction numerator t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript over denominator t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript end fraction
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