In the given diagram (ao)/(oc)=(bo)/(od)=(1)/(2) and ab=5" "cm -Turito

General

Easy

Maths-

In the given diagram $fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction$ and $A B equals 5 c m.$ Find the value of DC.

Maths-General

15cm
20cm
5cm
10cm

Answer:The correct answer is: 10cm

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In the given figure, find the values of x y, and z.

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ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $C equals 70 to the power of ring operator end exponent comma L equals 50 to the power of ring operator end exponent. text Find end text left floor A O B$

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In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b, the lengths of DF and AG , respectively.

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ABCD is a Parallelogram, $A E perpendicular D C$ and $C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

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Two Rectangles ABCD and DBEF are as shown in the figure. The area of Rectangle DBEF is

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In the given figure, ABCD is a Cyclic $stack D E with bar on top perpendicular stack A B with bar on top comma B A O equals 40 to the power of ring operator end exponent comma Q A D equals 20 to the power of ring operator end exponent$ and $∣ O C D equals 50 to the power of ring operator end exponent$ then $A B C equals$

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In the figure be low $stack A B with bar on top parallel to stack D C with bar on top comma stack A E with rightwards arrow on top parallel to stack B C with bar on top$ and $stack A F with bar on top parallel to stack B D with bar on top$ If $D equals x to the power of ring operator end exponent comma C equals y to the power of 0 end exponent comma open floor E A B equals k to the power of ring operator end exponent close$ and $A B P equals p to the power of ring operator end exponent comma$ then which of the following is correct ?

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If ABCD is a square, MDC is an Equilateral Triangle, find the value of x .

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If PQRS is a Square and STR is an Equilateral Triangle,find the value of a

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In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m blank$ and $A equals 60 to the power of ring operator end exponent$ then length of AB is

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In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

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In the given $v minus t$ graph, the distance travelled by the body in 5 will be

Area between

v minus t

graph and time-axis

equals fraction numerator 1 over denominator 2 end fraction cross times 2 cross times 20 plus 3 cross times 20 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 20 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 20

equals 100

In the given $v minus t$ graph, the distance travelled by the body in 5 will be

physics-General

Area between

v minus t

graph and time-axis

equals fraction numerator 1 over denominator 2 end fraction cross times 2 cross times 20 plus 3 cross times 20 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 20 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 20

equals 100

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physics-

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

Maximum acceleration will be represented by

C D

part of the graph
Acceleration

equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

physics-General

Maximum acceleration will be represented by

C D

part of the graph
Acceleration

equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent

General

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In a Rhombus PQRS; QRS = xº then P = ?

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A stone dropped from a building of height $h$ and it reaches after $t$ seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity $u$ and they reach the earth surface after $t subscript 1 end subscript$ and $t subscript 2 end subscript$ seconds respectively, then

If a stone is dropped from height

h

then

h equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent

(i)
if a stone is thrown upward with velocity

u

then

h equals negative u blank t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript

(ii)
If a stone is thrown downward with velocity

u

then

h equals u t subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 2 end subscript superscript 2 end superscript

(iii)
From (i) (ii) and (iii) we get

negative u t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent

(iv)

u t subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 2 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent

(v)
Dividing (iv) and (v) we get

therefore fraction numerator negative u t subscript 1 end subscript over denominator u t subscript 2 end subscript end fraction equals fraction numerator fraction numerator 1 over denominator 2 end fraction g left parenthesis t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript right parenthesis over denominator fraction numerator 1 over denominator 2 end fraction g left parenthesis t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript right parenthesis end fraction

negative fraction numerator t subscript 1 end subscript over denominator t subscript 2 end subscript end fraction equals fraction numerator t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript over denominator t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript end fraction

By solving

blank t equals square root of t subscript 1 end subscript t subscript 2 end subscript end root

A stone dropped from a building of height $h$ and it reaches after $t$ seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity $u$ and they reach the earth surface after $t subscript 1 end subscript$ and $t subscript 2 end subscript$ seconds respectively, then

physics-General

If a stone is dropped from height

h

then

h equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent

(i)
if a stone is thrown upward with velocity

u

then

h equals negative u blank t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript

(ii)
If a stone is thrown downward with velocity

u

then

h equals u t subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 2 end subscript superscript 2 end superscript

(iii)
From (i) (ii) and (iii) we get

negative u t subscript 1 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 1 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent

(iv)

u t subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction g t subscript 2 end subscript superscript 2 end superscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent

(v)
Dividing (iv) and (v) we get

therefore fraction numerator negative u t subscript 1 end subscript over denominator u t subscript 2 end subscript end fraction equals fraction numerator fraction numerator 1 over denominator 2 end fraction g left parenthesis t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript right parenthesis over denominator fraction numerator 1 over denominator 2 end fraction g left parenthesis t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript right parenthesis end fraction

negative fraction numerator t subscript 1 end subscript over denominator t subscript 2 end subscript end fraction equals fraction numerator t to the power of 2 end exponent minus t subscript 1 end subscript superscript 2 end superscript over denominator t to the power of 2 end exponent minus t subscript 2 end subscript superscript 2 end superscript end fraction

By solving

blank t equals square root of t subscript 1 end subscript t subscript 2 end subscript end root

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In the given diagram $fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction$ and $A B equals 5 c m.$ Find the value of DC.

15cm
20cm
5cm
10cm

Answer:The correct answer is: 10cm

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In the given figure, find the values of x y, and z.

In the given figure, find the values of x y, and z.

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $C equals 70 to the power of ring operator end exponent comma L equals 50 to the power of ring operator end exponent. text Find end text left floor A O B$

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $C equals 70 to the power of ring operator end exponent comma L equals 50 to the power of ring operator end exponent. text Find end text left floor A O B$

In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b, the lengths of DF and AG , respectively.

In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b, the lengths of DF and AG , respectively.

ABCD is a Parallelogram, $A E perpendicular D C$ and $C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

ABCD is a Parallelogram, $A E perpendicular D C$ and $C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

Two Rectangles ABCD and DBEF are as shown in the figure. The area of Rectangle DBEF is

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If ABCD is a square, MDC is an Equilateral Triangle, find the value of x .

If ABCD is a square, MDC is an Equilateral Triangle, find the value of x .

If PQRS is a Square and STR is an Equilateral Triangle,find the value of a

If PQRS is a Square and STR is an Equilateral Triangle,find the value of a

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m blank$ and $A equals 60 to the power of ring operator end exponent$ then length of AB is

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m blank$ and $A equals 60 to the power of ring operator end exponent$ then length of AB is

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In the given $v minus t$ graph, the distance travelled by the body in 5 will be

In the given $v minus t$ graph, the distance travelled by the body in 5 will be

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

In a Rhombus PQRS; QRS = xº then P = ?

In a Rhombus PQRS; QRS = xº then P = ?

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In the given diagram and Find the value of DC.

15cm 20cm 5cm 10cm

Answer:The correct answer is: 10cm

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Related Questions to study

In the given figure, find the values of x y, and z.

In the given figure, find the values of x y, and z.

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If

In the unit Square, find the distance from E to in terms of a and b, the lengths of DF and AG , respectively.

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ABCD is a Parallelogram, and If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

ABCD is a Parallelogram, and If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

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In the given figure, ABCD is a Cyclic and then

In the given figure, ABCD is a Cyclic and then

In the figure be low and If and then which of the following is correct ?

In the figure be low and If and then which of the following is correct ?

If ABCD is a square, MDC is an Equilateral Triangle, find the value of x .

If ABCD is a square, MDC is an Equilateral Triangle, find the value of x .

If PQRS is a Square and STR is an Equilateral Triangle,find the value of a

If PQRS is a Square and STR is an Equilateral Triangle,find the value of a

In a Trapezium ABCD, as shown, and then length of AB is

In a Trapezium ABCD, as shown, and then length of AB is

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In the given graph, the distance travelled by the body in 5 will be

In the given graph, the distance travelled by the body in 5 will be

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

In a Rhombus PQRS; QRS = xº then P = ?

In a Rhombus PQRS; QRS = xº then P = ?

A stone dropped from a building of height and it reaches after seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity and they reach the earth surface after and seconds respectively, then

A stone dropped from a building of height and it reaches after seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity and they reach the earth surface after and seconds respectively, then

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In the given diagram $fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction$ and $A B equals 5 c m.$ Find the value of DC.

15cm
20cm
5cm
10cm

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $C equals 70 to the power of ring operator end exponent comma L equals 50 to the power of ring operator end exponent. text Find end text left floor A O B$

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $C equals 70 to the power of ring operator end exponent comma L equals 50 to the power of ring operator end exponent. text Find end text left floor A O B$

In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b, the lengths of DF and AG , respectively.

In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b, the lengths of DF and AG , respectively.

ABCD is a Parallelogram, $A E perpendicular D C$ and $C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

ABCD is a Parallelogram, $A E perpendicular D C$ and $C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m blank$ and $A equals 60 to the power of ring operator end exponent$ then length of AB is

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m blank$ and $A equals 60 to the power of ring operator end exponent$ then length of AB is

In the given $v minus t$ graph, the distance travelled by the body in 5 will be

In the given $v minus t$ graph, the distance travelled by the body in 5 will be