Physics-
General
Easy

Question

The displacement-time graph of a moving object is shown in figure. Which of the velocity-time graphs shown in figure could represent the motion of the same body?

  1.    
  2.    
  3.    
  4.    

The correct answer is:


    Think of the lope of the given displacement-time graph at different points and you would arrive at the correct answer.
    Alternatively, look at the self-illustrative figure.

    Book A Free Demo

    +91

    Grade*

    Related Questions to study

    General
    maths-

    The value of k for which the lines fraction numerator x plus 1 over denominator negative 3 end fraction equals fraction numerator y plus 5 over denominator 2 k end fraction equals fraction numerator z minus 4 over denominator 2 end fraction and fraction numerator x minus 3 over denominator 3 k end fraction equals fraction numerator y minus 2 over denominator 1 end fraction equals fraction numerator z plus 1 over denominator 7 end fraction are perpendicular is

    The value of k for which the lines fraction numerator x plus 1 over denominator negative 3 end fraction equals fraction numerator y plus 5 over denominator 2 k end fraction equals fraction numerator z minus 4 over denominator 2 end fraction and fraction numerator x minus 3 over denominator 3 k end fraction equals fraction numerator y minus 2 over denominator 1 end fraction equals fraction numerator z plus 1 over denominator 7 end fraction are perpendicular is

    maths-General
    General
    maths-

    If the straight lines x=1+s,y=-3-λs,z=1+λs and x equals fraction numerator t over denominator 2 end fraction comma y equals 1 plus t, z=2-t, with parameters s and t respectively, are co planar, then λ=

    If the straight lines x=1+s,y=-3-λs,z=1+λs and x equals fraction numerator t over denominator 2 end fraction comma y equals 1 plus t, z=2-t, with parameters s and t respectively, are co planar, then λ=

    maths-General
    General
    maths-

    If 5 cas 2 theta plus 2 Cos squared space left parenthesis theta divided by 2 right parenthesis plus 1 equals 0 comma 0 less than theta less than pi not stretchy rightwards double arrow theta equals

    If 5 cas 2 theta plus 2 Cos squared space left parenthesis theta divided by 2 right parenthesis plus 1 equals 0 comma 0 less than theta less than pi not stretchy rightwards double arrow theta equals

    maths-General
    General
    physics-

    A boy begins to walk eastward along a street infront of his house and the graph of his displacement from home is shown in the following figure. His average speed for in the whole-time interval is equal to

    D i s p l a c e m e n t blank f o r m blank 0 blank t o blank 5 blank s blank equals blank 40 blank m
    D i s p l a c e m e n t blank f r o m blank 5 blank t o blank 10 blank s blank equals blank 40 blank m
    D i s p l a c e m e n t blank f r o m blank 0 blank t o blank 15 blank s blank equals blank minus blank 20 blank m
    A n d blank d i s p l a c e m e n t blank f r o m blank 15 blank t o blank 20 blank s equals 0 blank m
    therefore N e t blank d i s p l a c e m e n t equals 40 plus 40 minus 20 plus 0 equals 60 blank m
    T o t a l blank t i m e blank t a k e n equals 5 plus 5 plus 15 plus 5 equals 30 blank m i n.
    H e n c e comma blank a v e r a g e blank s p e e d equals fraction numerator d i s p l a c e m e n t blank open parentheses m close parentheses over denominator t i m e blank open parentheses m i n close parentheses end fraction equals fraction numerator 60 over denominator 30 end fraction equals 2 m blank m i n to the power of negative 1 end exponent.

    A boy begins to walk eastward along a street infront of his house and the graph of his displacement from home is shown in the following figure. His average speed for in the whole-time interval is equal to

    physics-General
    D i s p l a c e m e n t blank f o r m blank 0 blank t o blank 5 blank s blank equals blank 40 blank m
    D i s p l a c e m e n t blank f r o m blank 5 blank t o blank 10 blank s blank equals blank 40 blank m
    D i s p l a c e m e n t blank f r o m blank 0 blank t o blank 15 blank s blank equals blank minus blank 20 blank m
    A n d blank d i s p l a c e m e n t blank f r o m blank 15 blank t o blank 20 blank s equals 0 blank m
    therefore N e t blank d i s p l a c e m e n t equals 40 plus 40 minus 20 plus 0 equals 60 blank m
    T o t a l blank t i m e blank t a k e n equals 5 plus 5 plus 15 plus 5 equals 30 blank m i n.
    H e n c e comma blank a v e r a g e blank s p e e d equals fraction numerator d i s p l a c e m e n t blank open parentheses m close parentheses over denominator t i m e blank open parentheses m i n close parentheses end fraction equals fraction numerator 60 over denominator 30 end fraction equals 2 m blank m i n to the power of negative 1 end exponent.
    General
    maths-

    The values of theta satisfying Sin space 5 theta equals Sin space 3 theta minus Sin space theta and 0 less than theta less than pi over 2 are

    The values of theta satisfying Sin space 5 theta equals Sin space 3 theta minus Sin space theta and 0 less than theta less than pi over 2 are

    maths-General
    General
    physics-

    A body of mass m is resting on a wedge of angle theta as shown in figure. The wedge is given at acceleration alpha. What is the value of a son that the mass m just falls freely?

    The horizontal acceleration a of the wedge should be such that in time the wedge moves the horizontal distance B C. The body must fall through a vertical distance A B under gravity. Hence,
    B C equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent and A B equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
    tantheta equals fraction numerator A B over denominator B C end fraction equals fraction numerator g over denominator a end fractionor a equals fraction numerator g over denominator t a n theta end fraction equals g blank c o t theta

    A body of mass m is resting on a wedge of angle theta as shown in figure. The wedge is given at acceleration alpha. What is the value of a son that the mass m just falls freely?

    physics-General
    The horizontal acceleration a of the wedge should be such that in time the wedge moves the horizontal distance B C. The body must fall through a vertical distance A B under gravity. Hence,
    B C equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent and A B equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
    tantheta equals fraction numerator A B over denominator B C end fraction equals fraction numerator g over denominator a end fractionor a equals fraction numerator g over denominator t a n theta end fraction equals g blank c o t theta
    General
    physics-

    A cyclist starts from the centre O of a circular park of radius one kilometre, reaches the edge P of the park, then cycles along the circumference and returns to the centre along Q O as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

    Net displacement equals 0 and total distance equals O P plus P Q plus Q O
    equals 1 plus fraction numerator 2 pi cross times 1 over denominator 4 end fraction plus 1 equals fraction numerator 14.28 over denominator 4 end fraction blank k m
    Average speedblank equals fraction numerator 14.28 over denominator 4 cross times 10 divided by 60 end fraction
    equals fraction numerator 6 cross times 14.28 over denominator 4 end fraction equals 21.42 blank k m divided by h

    A cyclist starts from the centre O of a circular park of radius one kilometre, reaches the edge P of the park, then cycles along the circumference and returns to the centre along Q O as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

    physics-General
    Net displacement equals 0 and total distance equals O P plus P Q plus Q O
    equals 1 plus fraction numerator 2 pi cross times 1 over denominator 4 end fraction plus 1 equals fraction numerator 14.28 over denominator 4 end fraction blank k m
    Average speedblank equals fraction numerator 14.28 over denominator 4 cross times 10 divided by 60 end fraction
    equals fraction numerator 6 cross times 14.28 over denominator 4 end fraction equals 21.42 blank k m divided by h
    General
    physics-

    A ball is thrown vertically upwards. Which of the following graph/graphs represent velocity-time graph of the ball during its flight (air resistance is neglected)

    In the positive region the velocity decreases linearly (during rise) and in the negative region velocity increases linearly (during fall) and the direction is opposite to each other during rise and fall, hence fall is shown in the negative region

    A ball is thrown vertically upwards. Which of the following graph/graphs represent velocity-time graph of the ball during its flight (air resistance is neglected)

    physics-General
    In the positive region the velocity decreases linearly (during rise) and in the negative region velocity increases linearly (during fall) and the direction is opposite to each other during rise and fall, hence fall is shown in the negative region
    General
    physics-

    Which of the following graphs cannot possibly represent one dimensional motion of a particle

    I is not possible because total distance covered by a particle increases with time
    II is not possible because at a particular time, position cannot have two values
    III is not possible because at a particular time, velocity cannot have two values
    IV is not possible because speed can never be negative

    Which of the following graphs cannot possibly represent one dimensional motion of a particle

    physics-General
    I is not possible because total distance covered by a particle increases with time
    II is not possible because at a particular time, position cannot have two values
    III is not possible because at a particular time, velocity cannot have two values
    IV is not possible because speed can never be negative
    General
    physics-

    Which of the following graphs cannot possibly represent one dimensional motion of a particle

    I is not possible because total distance covered by a particle increases with time
    II is not possible because at a particular time, position cannot have two values
    III is not possible because at a particular time, velocity cannot have two values
    IV is not possible because speed can never be negative

    Which of the following graphs cannot possibly represent one dimensional motion of a particle

    physics-General
    I is not possible because total distance covered by a particle increases with time
    II is not possible because at a particular time, position cannot have two values
    III is not possible because at a particular time, velocity cannot have two values
    IV is not possible because speed can never be negative
    General
    maths-

    The solution of left parenthesis sin space x minus 2 right parenthesis squared plus left parenthesis cos space x minus 3 divided by 2 right parenthesis squared equals 0 is

    The solution of left parenthesis sin space x minus 2 right parenthesis squared plus left parenthesis cos space x minus 3 divided by 2 right parenthesis squared equals 0 is

    maths-General
    General
    maths-

    If Sin space x plus Cos space x equals square root of 2 cos space alpha not stretchy rightwards double arrow x equals midline horizontal ellipsis

    If Sin space x plus Cos space x equals square root of 2 cos space alpha not stretchy rightwards double arrow x equals midline horizontal ellipsis

    maths-General
    General
    physics-

    Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

    From acceleration-velocity graph, we have a equals k blank v blankwhere k is a constant which represents the slope of the given line.
    As, a equals v fraction numerator d v over denominator d s end fraction comma so v equals fraction numerator d v over denominator d s end fraction equals k v
    or fraction numerator d v over denominator d s end fraction equals k equals a constant
    Thus, the slope of velocity-displacement graphs is same as that of acceleration velocity. Which is constant.

    Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

    physics-General
    From acceleration-velocity graph, we have a equals k blank v blankwhere k is a constant which represents the slope of the given line.
    As, a equals v fraction numerator d v over denominator d s end fraction comma so v equals fraction numerator d v over denominator d s end fraction equals k v
    or fraction numerator d v over denominator d s end fraction equals k equals a constant
    Thus, the slope of velocity-displacement graphs is same as that of acceleration velocity. Which is constant.
    General
    maths-

    If Tanp space theta equals Cotq space theta then solutions of theta are in -

    If Tanp space theta equals Cotq space theta then solutions of theta are in -

    maths-General
    General
    maths-

    In capital delta A B C comma I f a comma b, care in H.P., then Sin invisible function application 2 A over 2 , Sin2 fraction numerator B over denominator 2 end fraction , Sin2 fraction numerator C over denominator 2 end fraction are in

    a comma b comma c are in H. P comma fraction numerator 1 over denominator a end fraction comma fraction numerator 1 over denominator b end fraction comma fraction numerator 1 over denominator c end fraction are in A. P fraction numerator s minus a over denominator a end fraction comma fraction numerator s minus b over denominator b end fraction comma fraction numerator s minus c over denominator c end fraction are in A. P

    In capital delta A B C comma I f a comma b, care in H.P., then Sin invisible function application 2 A over 2 , Sin2 fraction numerator B over denominator 2 end fraction , Sin2 fraction numerator C over denominator 2 end fraction are in

    maths-General
    a comma b comma c are in H. P comma fraction numerator 1 over denominator a end fraction comma fraction numerator 1 over denominator b end fraction comma fraction numerator 1 over denominator c end fraction are in A. P fraction numerator s minus a over denominator a end fraction comma fraction numerator s minus b over denominator b end fraction comma fraction numerator s minus c over denominator c end fraction are in A. P