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Maths-

General

Easy

Question

If $Sin space x plus Cos space x equals square root of 2 cos space alpha not stretchy rightwards double arrow x equals midline horizontal ellipsis$

$2 n π - \frac{π}{4} \pm α$
$n π - \frac{π}{4} + α$
$2 n π + \frac{π}{4} \pm α$
$n π - \frac{π}{4} \pm α$

The correct answer is: $2 n pi plus pi over 4 plus-or-minus alpha$

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